NEET Test Series from KOTA - 10 Papers In MS WORD
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Laws of Motion
270318
The pulley and strings shown in the figure are smooth and of negligible mass. For the system to remain in equilibrium, the angle '\(\theta\) ' should be
1 \(0^{0}\)
2 \(30^{\circ}\)
3 \(45^{\circ}\)
4 \(60^{\circ}\)
Explanation:
Draw \(\mathrm{FBD}\) of \(\mathrm{m}\) is \(\mathrm{T}=\mathrm{mg}\) Draw FBD of \(\sqrt{2} \mathrm{~m}\) is \(2 \mathrm{~T} \cos \theta=\sqrt{2} \mathrm{mg}\)
Laws of Motion
270319
Two bodies of masses\(4 \mathrm{~kg}\) and \(6 \mathrm{~kg}\) are attached to the ends of a string which passes over a pulley,the \(4 \mathrm{~kg}\) mass is attached to the table top by another string. The tension in this string \(T_{1}\) is equal to
1 \(10 \mathrm{~N}\)
2 \(10.6 \mathrm{~N}\)
3 \(25 \mathrm{~N}\)
4 \(20 \mathrm{~N}\)
Explanation:
\(T=m_{1} g ; T=m_{2} g+T_{1}\)
Laws of Motion
270320
Acceleration of block\(m\) is \(\left(\theta<45^{\circ}\right)\)
270318
The pulley and strings shown in the figure are smooth and of negligible mass. For the system to remain in equilibrium, the angle '\(\theta\) ' should be
1 \(0^{0}\)
2 \(30^{\circ}\)
3 \(45^{\circ}\)
4 \(60^{\circ}\)
Explanation:
Draw \(\mathrm{FBD}\) of \(\mathrm{m}\) is \(\mathrm{T}=\mathrm{mg}\) Draw FBD of \(\sqrt{2} \mathrm{~m}\) is \(2 \mathrm{~T} \cos \theta=\sqrt{2} \mathrm{mg}\)
Laws of Motion
270319
Two bodies of masses\(4 \mathrm{~kg}\) and \(6 \mathrm{~kg}\) are attached to the ends of a string which passes over a pulley,the \(4 \mathrm{~kg}\) mass is attached to the table top by another string. The tension in this string \(T_{1}\) is equal to
1 \(10 \mathrm{~N}\)
2 \(10.6 \mathrm{~N}\)
3 \(25 \mathrm{~N}\)
4 \(20 \mathrm{~N}\)
Explanation:
\(T=m_{1} g ; T=m_{2} g+T_{1}\)
Laws of Motion
270320
Acceleration of block\(m\) is \(\left(\theta<45^{\circ}\right)\)
270318
The pulley and strings shown in the figure are smooth and of negligible mass. For the system to remain in equilibrium, the angle '\(\theta\) ' should be
1 \(0^{0}\)
2 \(30^{\circ}\)
3 \(45^{\circ}\)
4 \(60^{\circ}\)
Explanation:
Draw \(\mathrm{FBD}\) of \(\mathrm{m}\) is \(\mathrm{T}=\mathrm{mg}\) Draw FBD of \(\sqrt{2} \mathrm{~m}\) is \(2 \mathrm{~T} \cos \theta=\sqrt{2} \mathrm{mg}\)
Laws of Motion
270319
Two bodies of masses\(4 \mathrm{~kg}\) and \(6 \mathrm{~kg}\) are attached to the ends of a string which passes over a pulley,the \(4 \mathrm{~kg}\) mass is attached to the table top by another string. The tension in this string \(T_{1}\) is equal to
1 \(10 \mathrm{~N}\)
2 \(10.6 \mathrm{~N}\)
3 \(25 \mathrm{~N}\)
4 \(20 \mathrm{~N}\)
Explanation:
\(T=m_{1} g ; T=m_{2} g+T_{1}\)
Laws of Motion
270320
Acceleration of block\(m\) is \(\left(\theta<45^{\circ}\right)\)
