269888
If\(\overrightarrow{\mathrm{u}}=\mathrm{a} \hat{i}+\mathrm{b} \hat{j}+\mathrm{c} \hat{\mathrm{k}}\) with \(\hat{i}, \hat{j}, \hat{k}\) are in east, north and vertical directions, the maximum height of the projectile is
269918
The parabolic path of a projectile is represented by \(y=\frac{x}{\sqrt{3}}-\frac{x^{2}}{60}\) in MKS units : Its angle of projection is \(\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)\)
1 \(30^{\circ}\)
2 \(45^{\circ}\)
3 \(60^{\circ}\)
4 \(90^{\circ}\)
Explanation:
\(y=A x-B x^{2}, \quad \theta=\tan ^{-1}(A) \)
Motion in Plane
269919
A body is projected at angle\(30^{\circ}\) to horizontal with a velocity \(50 \mathrm{~ms}^{-1}\). Its time of flight is
1 \(4 \mathrm{~s}\)
2 \(5 \mathrm{~s}\)
3 \(6 \mathrm{~s}\)
4 \(7 \mathrm{~s}\)
Explanation:
\(T=\frac{2 u \sin \theta}{g}\)
Motion in Plane
269920
A body is projected with velocity\(60 \mathrm{~m} / \mathrm{s}\) at \(30^{\circ}\) to the horizontal. The velocity of the body after 3 seconds is
269888
If\(\overrightarrow{\mathrm{u}}=\mathrm{a} \hat{i}+\mathrm{b} \hat{j}+\mathrm{c} \hat{\mathrm{k}}\) with \(\hat{i}, \hat{j}, \hat{k}\) are in east, north and vertical directions, the maximum height of the projectile is
269918
The parabolic path of a projectile is represented by \(y=\frac{x}{\sqrt{3}}-\frac{x^{2}}{60}\) in MKS units : Its angle of projection is \(\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)\)
1 \(30^{\circ}\)
2 \(45^{\circ}\)
3 \(60^{\circ}\)
4 \(90^{\circ}\)
Explanation:
\(y=A x-B x^{2}, \quad \theta=\tan ^{-1}(A) \)
Motion in Plane
269919
A body is projected at angle\(30^{\circ}\) to horizontal with a velocity \(50 \mathrm{~ms}^{-1}\). Its time of flight is
1 \(4 \mathrm{~s}\)
2 \(5 \mathrm{~s}\)
3 \(6 \mathrm{~s}\)
4 \(7 \mathrm{~s}\)
Explanation:
\(T=\frac{2 u \sin \theta}{g}\)
Motion in Plane
269920
A body is projected with velocity\(60 \mathrm{~m} / \mathrm{s}\) at \(30^{\circ}\) to the horizontal. The velocity of the body after 3 seconds is
269888
If\(\overrightarrow{\mathrm{u}}=\mathrm{a} \hat{i}+\mathrm{b} \hat{j}+\mathrm{c} \hat{\mathrm{k}}\) with \(\hat{i}, \hat{j}, \hat{k}\) are in east, north and vertical directions, the maximum height of the projectile is
269918
The parabolic path of a projectile is represented by \(y=\frac{x}{\sqrt{3}}-\frac{x^{2}}{60}\) in MKS units : Its angle of projection is \(\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)\)
1 \(30^{\circ}\)
2 \(45^{\circ}\)
3 \(60^{\circ}\)
4 \(90^{\circ}\)
Explanation:
\(y=A x-B x^{2}, \quad \theta=\tan ^{-1}(A) \)
Motion in Plane
269919
A body is projected at angle\(30^{\circ}\) to horizontal with a velocity \(50 \mathrm{~ms}^{-1}\). Its time of flight is
1 \(4 \mathrm{~s}\)
2 \(5 \mathrm{~s}\)
3 \(6 \mathrm{~s}\)
4 \(7 \mathrm{~s}\)
Explanation:
\(T=\frac{2 u \sin \theta}{g}\)
Motion in Plane
269920
A body is projected with velocity\(60 \mathrm{~m} / \mathrm{s}\) at \(30^{\circ}\) to the horizontal. The velocity of the body after 3 seconds is
269888
If\(\overrightarrow{\mathrm{u}}=\mathrm{a} \hat{i}+\mathrm{b} \hat{j}+\mathrm{c} \hat{\mathrm{k}}\) with \(\hat{i}, \hat{j}, \hat{k}\) are in east, north and vertical directions, the maximum height of the projectile is
269918
The parabolic path of a projectile is represented by \(y=\frac{x}{\sqrt{3}}-\frac{x^{2}}{60}\) in MKS units : Its angle of projection is \(\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)\)
1 \(30^{\circ}\)
2 \(45^{\circ}\)
3 \(60^{\circ}\)
4 \(90^{\circ}\)
Explanation:
\(y=A x-B x^{2}, \quad \theta=\tan ^{-1}(A) \)
Motion in Plane
269919
A body is projected at angle\(30^{\circ}\) to horizontal with a velocity \(50 \mathrm{~ms}^{-1}\). Its time of flight is
1 \(4 \mathrm{~s}\)
2 \(5 \mathrm{~s}\)
3 \(6 \mathrm{~s}\)
4 \(7 \mathrm{~s}\)
Explanation:
\(T=\frac{2 u \sin \theta}{g}\)
Motion in Plane
269920
A body is projected with velocity\(60 \mathrm{~m} / \mathrm{s}\) at \(30^{\circ}\) to the horizontal. The velocity of the body after 3 seconds is
269888
If\(\overrightarrow{\mathrm{u}}=\mathrm{a} \hat{i}+\mathrm{b} \hat{j}+\mathrm{c} \hat{\mathrm{k}}\) with \(\hat{i}, \hat{j}, \hat{k}\) are in east, north and vertical directions, the maximum height of the projectile is
269918
The parabolic path of a projectile is represented by \(y=\frac{x}{\sqrt{3}}-\frac{x^{2}}{60}\) in MKS units : Its angle of projection is \(\left(\mathrm{g}=10 \mathrm{~ms}^{-2}\right)\)
1 \(30^{\circ}\)
2 \(45^{\circ}\)
3 \(60^{\circ}\)
4 \(90^{\circ}\)
Explanation:
\(y=A x-B x^{2}, \quad \theta=\tan ^{-1}(A) \)
Motion in Plane
269919
A body is projected at angle\(30^{\circ}\) to horizontal with a velocity \(50 \mathrm{~ms}^{-1}\). Its time of flight is
1 \(4 \mathrm{~s}\)
2 \(5 \mathrm{~s}\)
3 \(6 \mathrm{~s}\)
4 \(7 \mathrm{~s}\)
Explanation:
\(T=\frac{2 u \sin \theta}{g}\)
Motion in Plane
269920
A body is projected with velocity\(60 \mathrm{~m} / \mathrm{s}\) at \(30^{\circ}\) to the horizontal. The velocity of the body after 3 seconds is