QBManager

Motion in Plane

269872 A man can row a boat in still water with a velocity of $8 kmph$ . Water is flowing in a river with a velocity of $4 kmph$ . At what angle should he row the boat so as to reach the exact opposite point

1

150^{\circ}

to flow of water

2

120^{\circ}

to flow of water.

3

30^{\circ}

to flow of water.

4

90^{\circ}

to flow of water.

Explanation:

$\sin θ = \frac{V_{river}}{V_{boat}}; α = 90 + θ with stream$

Motion in Plane

269873 A person can swim in still water at $5 m / s$ . He moves in a river of velocity $3 m / s$ , first down the stream and next same distance up the stream. The ratio of times taken are

1

1 : 1

2

1 : 2

3

1 : 4

4

4 : 1

Explanation:

$t_{1} = \frac{d}{v + u}$ and $t_{2} = \frac{d}{v - u}$

Motion in Plane

269874 The velocity of water in a river is $2 m m p h$ , while width is $400 m$ . A boat is rowed from a point rowing always aiming opposite point at $8 kmph$ of still water velocity. On reaching the opposite bank the drift obtained is

1

93 m

2

100.8 m

3

112.4 m

4

100 m

Explanation:

$x = V_{W} \cdot \frac{d}{V_{B}}$

Motion in Plane

269875 A man can swim in still water at a speed of 4 $kmph$ . He desires to cross a river flowing at a speed of $3 kmph$ in the shortest time interval. If the width of the river is $3 km$ time taken to cross the river (in hours) and the horizontal distance travelled ( in $k m$ ) are respectively

1

\frac{3}{4}, \frac{9}{4}

2

\frac{3}{5}, 3

3

\frac{1}{4}, \frac{15}{4}

4

\frac{3}{\sqrt{7}}, 7

Motion in Plane

269914 A man can swim in still water at a speed of 6 $kmph$ and he has to cross the river and reach just opposite point on the other bank. If the river is flowing at a speed of $3 k m p h$ , and the width of the river is $2 km$ , the time taken to cross the river is (in hours)

1

\frac{2}{27}

2

\frac{2}{\sqrt{27}}

3

\frac{2}{3}

4

\frac{2}{\sqrt{45}}

Explanation:

$V_{m} = 6 kmph, V_{w} = 3 kmph, t = \frac{d}{\sqrt{v_{m}^{2} - v_{w}^{2}}}$

Motion in Plane

269872 A man can row a boat in still water with a velocity of $8 kmph$ . Water is flowing in a river with a velocity of $4 kmph$ . At what angle should he row the boat so as to reach the exact opposite point

1

150^{\circ}

to flow of water

2

120^{\circ}

to flow of water.

3

30^{\circ}

to flow of water.

4

90^{\circ}

to flow of water.

Explanation:

$\sin θ = \frac{V_{river}}{V_{boat}}; α = 90 + θ with stream$

Motion in Plane

269873 A person can swim in still water at $5 m / s$ . He moves in a river of velocity $3 m / s$ , first down the stream and next same distance up the stream. The ratio of times taken are

1

1 : 1

2

1 : 2

3

1 : 4

4

4 : 1

Explanation:

$t_{1} = \frac{d}{v + u}$ and $t_{2} = \frac{d}{v - u}$

Motion in Plane

269874 The velocity of water in a river is $2 m m p h$ , while width is $400 m$ . A boat is rowed from a point rowing always aiming opposite point at $8 kmph$ of still water velocity. On reaching the opposite bank the drift obtained is

1

93 m

2

100.8 m

3

112.4 m

4

100 m

Explanation:

$x = V_{W} \cdot \frac{d}{V_{B}}$

Motion in Plane

269875 A man can swim in still water at a speed of 4 $kmph$ . He desires to cross a river flowing at a speed of $3 kmph$ in the shortest time interval. If the width of the river is $3 km$ time taken to cross the river (in hours) and the horizontal distance travelled ( in $k m$ ) are respectively

1

\frac{3}{4}, \frac{9}{4}

2

\frac{3}{5}, 3

3

\frac{1}{4}, \frac{15}{4}

4

\frac{3}{\sqrt{7}}, 7

Motion in Plane

269914 A man can swim in still water at a speed of 6 $kmph$ and he has to cross the river and reach just opposite point on the other bank. If the river is flowing at a speed of $3 k m p h$ , and the width of the river is $2 km$ , the time taken to cross the river is (in hours)

1

\frac{2}{27}

2

\frac{2}{\sqrt{27}}

3

\frac{2}{3}

4

\frac{2}{\sqrt{45}}

Explanation:

$V_{m} = 6 kmph, V_{w} = 3 kmph, t = \frac{d}{\sqrt{v_{m}^{2} - v_{w}^{2}}}$

Motion in Plane

269872 A man can row a boat in still water with a velocity of $8 kmph$ . Water is flowing in a river with a velocity of $4 kmph$ . At what angle should he row the boat so as to reach the exact opposite point

1

150^{\circ}

to flow of water

2

120^{\circ}

to flow of water.

3

30^{\circ}

to flow of water.

4

90^{\circ}

to flow of water.

Explanation:

$\sin θ = \frac{V_{river}}{V_{boat}}; α = 90 + θ with stream$

Motion in Plane

269873 A person can swim in still water at $5 m / s$ . He moves in a river of velocity $3 m / s$ , first down the stream and next same distance up the stream. The ratio of times taken are

1

1 : 1

2

1 : 2

3

1 : 4

4

4 : 1

Explanation:

$t_{1} = \frac{d}{v + u}$ and $t_{2} = \frac{d}{v - u}$

Motion in Plane

269874 The velocity of water in a river is $2 m m p h$ , while width is $400 m$ . A boat is rowed from a point rowing always aiming opposite point at $8 kmph$ of still water velocity. On reaching the opposite bank the drift obtained is

1

93 m

2

100.8 m

3

112.4 m

4

100 m

Explanation:

$x = V_{W} \cdot \frac{d}{V_{B}}$

Motion in Plane

269875 A man can swim in still water at a speed of 4 $kmph$ . He desires to cross a river flowing at a speed of $3 kmph$ in the shortest time interval. If the width of the river is $3 km$ time taken to cross the river (in hours) and the horizontal distance travelled ( in $k m$ ) are respectively

1

\frac{3}{4}, \frac{9}{4}

2

\frac{3}{5}, 3

3

\frac{1}{4}, \frac{15}{4}

4

\frac{3}{\sqrt{7}}, 7

Motion in Plane

269914 A man can swim in still water at a speed of 6 $kmph$ and he has to cross the river and reach just opposite point on the other bank. If the river is flowing at a speed of $3 k m p h$ , and the width of the river is $2 km$ , the time taken to cross the river is (in hours)

1

\frac{2}{27}

2

\frac{2}{\sqrt{27}}

3

\frac{2}{3}

4

\frac{2}{\sqrt{45}}

Explanation:

$V_{m} = 6 kmph, V_{w} = 3 kmph, t = \frac{d}{\sqrt{v_{m}^{2} - v_{w}^{2}}}$

Motion in Plane

269872 A man can row a boat in still water with a velocity of $8 kmph$ . Water is flowing in a river with a velocity of $4 kmph$ . At what angle should he row the boat so as to reach the exact opposite point

1

150^{\circ}

to flow of water

2

120^{\circ}

to flow of water.

3

30^{\circ}

to flow of water.

4

90^{\circ}

to flow of water.

Explanation:

$\sin θ = \frac{V_{river}}{V_{boat}}; α = 90 + θ with stream$

Motion in Plane

269873 A person can swim in still water at $5 m / s$ . He moves in a river of velocity $3 m / s$ , first down the stream and next same distance up the stream. The ratio of times taken are

1

1 : 1

2

1 : 2

3

1 : 4

4

4 : 1

Explanation:

$t_{1} = \frac{d}{v + u}$ and $t_{2} = \frac{d}{v - u}$

Motion in Plane

269874 The velocity of water in a river is $2 m m p h$ , while width is $400 m$ . A boat is rowed from a point rowing always aiming opposite point at $8 kmph$ of still water velocity. On reaching the opposite bank the drift obtained is

1

93 m

2

100.8 m

3

112.4 m

4

100 m

Explanation:

$x = V_{W} \cdot \frac{d}{V_{B}}$

Motion in Plane

269875 A man can swim in still water at a speed of 4 $kmph$ . He desires to cross a river flowing at a speed of $3 kmph$ in the shortest time interval. If the width of the river is $3 km$ time taken to cross the river (in hours) and the horizontal distance travelled ( in $k m$ ) are respectively

1

\frac{3}{4}, \frac{9}{4}

2

\frac{3}{5}, 3

3

\frac{1}{4}, \frac{15}{4}

4

\frac{3}{\sqrt{7}}, 7

Motion in Plane

269914 A man can swim in still water at a speed of 6 $kmph$ and he has to cross the river and reach just opposite point on the other bank. If the river is flowing at a speed of $3 k m p h$ , and the width of the river is $2 km$ , the time taken to cross the river is (in hours)

1

\frac{2}{27}

2

\frac{2}{\sqrt{27}}

3

\frac{2}{3}

4

\frac{2}{\sqrt{45}}

Explanation:

$V_{m} = 6 kmph, V_{w} = 3 kmph, t = \frac{d}{\sqrt{v_{m}^{2} - v_{w}^{2}}}$

Motion in Plane

269872 A man can row a boat in still water with a velocity of $8 kmph$ . Water is flowing in a river with a velocity of $4 kmph$ . At what angle should he row the boat so as to reach the exact opposite point

1

150^{\circ}

to flow of water

2

120^{\circ}

to flow of water.

3

30^{\circ}

to flow of water.

4

90^{\circ}

to flow of water.

Explanation:

$\sin θ = \frac{V_{river}}{V_{boat}}; α = 90 + θ with stream$

Motion in Plane

269873 A person can swim in still water at $5 m / s$ . He moves in a river of velocity $3 m / s$ , first down the stream and next same distance up the stream. The ratio of times taken are

1

1 : 1

2

1 : 2

3

1 : 4

4

4 : 1

Explanation:

$t_{1} = \frac{d}{v + u}$ and $t_{2} = \frac{d}{v - u}$

Motion in Plane

269874 The velocity of water in a river is $2 m m p h$ , while width is $400 m$ . A boat is rowed from a point rowing always aiming opposite point at $8 kmph$ of still water velocity. On reaching the opposite bank the drift obtained is

1

93 m

2

100.8 m

3

112.4 m

4

100 m

Explanation:

$x = V_{W} \cdot \frac{d}{V_{B}}$

Motion in Plane

269875 A man can swim in still water at a speed of 4 $kmph$ . He desires to cross a river flowing at a speed of $3 kmph$ in the shortest time interval. If the width of the river is $3 km$ time taken to cross the river (in hours) and the horizontal distance travelled ( in $k m$ ) are respectively

1

\frac{3}{4}, \frac{9}{4}

2

\frac{3}{5}, 3

3

\frac{1}{4}, \frac{15}{4}

4

\frac{3}{\sqrt{7}}, 7

Motion in Plane

269914 A man can swim in still water at a speed of 6 $kmph$ and he has to cross the river and reach just opposite point on the other bank. If the river is flowing at a speed of $3 k m p h$ , and the width of the river is $2 km$ , the time taken to cross the river is (in hours)

1

\frac{2}{27}

2

\frac{2}{\sqrt{27}}

3

\frac{2}{3}

4

\frac{2}{\sqrt{45}}

Explanation:

$V_{m} = 6 kmph, V_{w} = 3 kmph, t = \frac{d}{\sqrt{v_{m}^{2} - v_{w}^{2}}}$