269868
A particle is moving eastwards with a velocity\(5 \mathrm{~ms}^{-1}\), changes its direction northwards in 10 seconds and moves with same magnitude of velocity. The average acceleration is
1 zero
2 \(\frac{1}{\sqrt{2}} m s^{-2}\) towards N-E
3 \(\frac{1}{\sqrt{2}} m s^{-2}\) towards S-E
4 \(\frac{1}{\sqrt{2}} m s^{-2}\) towards \(N-W\)
Explanation:
Concept Based
Motion in Plane
269869
A man is going due east with a velocity of\(5 \mathrm{~ms}^{-1}\). It is vertically raining downwards with a velocity of \(4 \mathbf{~ m s}^{-1}\). At what angle should he hold the umbrella to the vertical so as to protect him self from the rain?
1 \(\tan ^{-1}-\frac{5}{4} \theta\) in anti-clockwise direction
2 \(\tan ^{-1}\left[\frac{5}{4}\right.\) in clock-wise direction
3 \(\tan ^{-1} \cdot \frac{4}{5}\) - North of East
4
Explanation:
Concept Based
Motion in Plane
269870
Rain drops are falling down ward vertically at\(4 \mathrm{kmph}\). For a person moving forward at \(3 \mathrm{kmph}\) feels the rain falling at
1 \(7 \mathrm{kmph}\)
2 \(1 \mathrm{kmph}\)
3 \(5 \mathrm{kmph}\)
4 \(25 \mathrm{kmph}\)
Explanation:
Concept Based
Motion in Plane
269871
A man travelling at\(10.8 \mathrm{kmph}\) in topless car on a rainy day. He holds an umbrella at angle of \(37^{0}\) with the vertical so that he does not wet.If rain drops falls vertically downwards what is rain velocity.
1 \(1 \mathrm{~m} / \mathrm{s}\)
2 \(2 \mathrm{~m} / \mathrm{s}\)
3 \(3 \mathrm{~m} / \mathrm{s}\)
4 \(4 \mathrm{~m} / \mathrm{s}\).
Explanation:
Motion in Plane
269909
A particle is moving eastwards with a velocity\(15 \mathrm{~ms}^{-1}\). Suddenly it moves towards north and moves with the same speed in a time \(10 \mathrm{sec}\). The average acceleration during this time is
269868
A particle is moving eastwards with a velocity\(5 \mathrm{~ms}^{-1}\), changes its direction northwards in 10 seconds and moves with same magnitude of velocity. The average acceleration is
1 zero
2 \(\frac{1}{\sqrt{2}} m s^{-2}\) towards N-E
3 \(\frac{1}{\sqrt{2}} m s^{-2}\) towards S-E
4 \(\frac{1}{\sqrt{2}} m s^{-2}\) towards \(N-W\)
Explanation:
Concept Based
Motion in Plane
269869
A man is going due east with a velocity of\(5 \mathrm{~ms}^{-1}\). It is vertically raining downwards with a velocity of \(4 \mathbf{~ m s}^{-1}\). At what angle should he hold the umbrella to the vertical so as to protect him self from the rain?
1 \(\tan ^{-1}-\frac{5}{4} \theta\) in anti-clockwise direction
2 \(\tan ^{-1}\left[\frac{5}{4}\right.\) in clock-wise direction
3 \(\tan ^{-1} \cdot \frac{4}{5}\) - North of East
4
Explanation:
Concept Based
Motion in Plane
269870
Rain drops are falling down ward vertically at\(4 \mathrm{kmph}\). For a person moving forward at \(3 \mathrm{kmph}\) feels the rain falling at
1 \(7 \mathrm{kmph}\)
2 \(1 \mathrm{kmph}\)
3 \(5 \mathrm{kmph}\)
4 \(25 \mathrm{kmph}\)
Explanation:
Concept Based
Motion in Plane
269871
A man travelling at\(10.8 \mathrm{kmph}\) in topless car on a rainy day. He holds an umbrella at angle of \(37^{0}\) with the vertical so that he does not wet.If rain drops falls vertically downwards what is rain velocity.
1 \(1 \mathrm{~m} / \mathrm{s}\)
2 \(2 \mathrm{~m} / \mathrm{s}\)
3 \(3 \mathrm{~m} / \mathrm{s}\)
4 \(4 \mathrm{~m} / \mathrm{s}\).
Explanation:
Motion in Plane
269909
A particle is moving eastwards with a velocity\(15 \mathrm{~ms}^{-1}\). Suddenly it moves towards north and moves with the same speed in a time \(10 \mathrm{sec}\). The average acceleration during this time is
269868
A particle is moving eastwards with a velocity\(5 \mathrm{~ms}^{-1}\), changes its direction northwards in 10 seconds and moves with same magnitude of velocity. The average acceleration is
1 zero
2 \(\frac{1}{\sqrt{2}} m s^{-2}\) towards N-E
3 \(\frac{1}{\sqrt{2}} m s^{-2}\) towards S-E
4 \(\frac{1}{\sqrt{2}} m s^{-2}\) towards \(N-W\)
Explanation:
Concept Based
Motion in Plane
269869
A man is going due east with a velocity of\(5 \mathrm{~ms}^{-1}\). It is vertically raining downwards with a velocity of \(4 \mathbf{~ m s}^{-1}\). At what angle should he hold the umbrella to the vertical so as to protect him self from the rain?
1 \(\tan ^{-1}-\frac{5}{4} \theta\) in anti-clockwise direction
2 \(\tan ^{-1}\left[\frac{5}{4}\right.\) in clock-wise direction
3 \(\tan ^{-1} \cdot \frac{4}{5}\) - North of East
4
Explanation:
Concept Based
Motion in Plane
269870
Rain drops are falling down ward vertically at\(4 \mathrm{kmph}\). For a person moving forward at \(3 \mathrm{kmph}\) feels the rain falling at
1 \(7 \mathrm{kmph}\)
2 \(1 \mathrm{kmph}\)
3 \(5 \mathrm{kmph}\)
4 \(25 \mathrm{kmph}\)
Explanation:
Concept Based
Motion in Plane
269871
A man travelling at\(10.8 \mathrm{kmph}\) in topless car on a rainy day. He holds an umbrella at angle of \(37^{0}\) with the vertical so that he does not wet.If rain drops falls vertically downwards what is rain velocity.
1 \(1 \mathrm{~m} / \mathrm{s}\)
2 \(2 \mathrm{~m} / \mathrm{s}\)
3 \(3 \mathrm{~m} / \mathrm{s}\)
4 \(4 \mathrm{~m} / \mathrm{s}\).
Explanation:
Motion in Plane
269909
A particle is moving eastwards with a velocity\(15 \mathrm{~ms}^{-1}\). Suddenly it moves towards north and moves with the same speed in a time \(10 \mathrm{sec}\). The average acceleration during this time is
269868
A particle is moving eastwards with a velocity\(5 \mathrm{~ms}^{-1}\), changes its direction northwards in 10 seconds and moves with same magnitude of velocity. The average acceleration is
1 zero
2 \(\frac{1}{\sqrt{2}} m s^{-2}\) towards N-E
3 \(\frac{1}{\sqrt{2}} m s^{-2}\) towards S-E
4 \(\frac{1}{\sqrt{2}} m s^{-2}\) towards \(N-W\)
Explanation:
Concept Based
Motion in Plane
269869
A man is going due east with a velocity of\(5 \mathrm{~ms}^{-1}\). It is vertically raining downwards with a velocity of \(4 \mathbf{~ m s}^{-1}\). At what angle should he hold the umbrella to the vertical so as to protect him self from the rain?
1 \(\tan ^{-1}-\frac{5}{4} \theta\) in anti-clockwise direction
2 \(\tan ^{-1}\left[\frac{5}{4}\right.\) in clock-wise direction
3 \(\tan ^{-1} \cdot \frac{4}{5}\) - North of East
4
Explanation:
Concept Based
Motion in Plane
269870
Rain drops are falling down ward vertically at\(4 \mathrm{kmph}\). For a person moving forward at \(3 \mathrm{kmph}\) feels the rain falling at
1 \(7 \mathrm{kmph}\)
2 \(1 \mathrm{kmph}\)
3 \(5 \mathrm{kmph}\)
4 \(25 \mathrm{kmph}\)
Explanation:
Concept Based
Motion in Plane
269871
A man travelling at\(10.8 \mathrm{kmph}\) in topless car on a rainy day. He holds an umbrella at angle of \(37^{0}\) with the vertical so that he does not wet.If rain drops falls vertically downwards what is rain velocity.
1 \(1 \mathrm{~m} / \mathrm{s}\)
2 \(2 \mathrm{~m} / \mathrm{s}\)
3 \(3 \mathrm{~m} / \mathrm{s}\)
4 \(4 \mathrm{~m} / \mathrm{s}\).
Explanation:
Motion in Plane
269909
A particle is moving eastwards with a velocity\(15 \mathrm{~ms}^{-1}\). Suddenly it moves towards north and moves with the same speed in a time \(10 \mathrm{sec}\). The average acceleration during this time is
269868
A particle is moving eastwards with a velocity\(5 \mathrm{~ms}^{-1}\), changes its direction northwards in 10 seconds and moves with same magnitude of velocity. The average acceleration is
1 zero
2 \(\frac{1}{\sqrt{2}} m s^{-2}\) towards N-E
3 \(\frac{1}{\sqrt{2}} m s^{-2}\) towards S-E
4 \(\frac{1}{\sqrt{2}} m s^{-2}\) towards \(N-W\)
Explanation:
Concept Based
Motion in Plane
269869
A man is going due east with a velocity of\(5 \mathrm{~ms}^{-1}\). It is vertically raining downwards with a velocity of \(4 \mathbf{~ m s}^{-1}\). At what angle should he hold the umbrella to the vertical so as to protect him self from the rain?
1 \(\tan ^{-1}-\frac{5}{4} \theta\) in anti-clockwise direction
2 \(\tan ^{-1}\left[\frac{5}{4}\right.\) in clock-wise direction
3 \(\tan ^{-1} \cdot \frac{4}{5}\) - North of East
4
Explanation:
Concept Based
Motion in Plane
269870
Rain drops are falling down ward vertically at\(4 \mathrm{kmph}\). For a person moving forward at \(3 \mathrm{kmph}\) feels the rain falling at
1 \(7 \mathrm{kmph}\)
2 \(1 \mathrm{kmph}\)
3 \(5 \mathrm{kmph}\)
4 \(25 \mathrm{kmph}\)
Explanation:
Concept Based
Motion in Plane
269871
A man travelling at\(10.8 \mathrm{kmph}\) in topless car on a rainy day. He holds an umbrella at angle of \(37^{0}\) with the vertical so that he does not wet.If rain drops falls vertically downwards what is rain velocity.
1 \(1 \mathrm{~m} / \mathrm{s}\)
2 \(2 \mathrm{~m} / \mathrm{s}\)
3 \(3 \mathrm{~m} / \mathrm{s}\)
4 \(4 \mathrm{~m} / \mathrm{s}\).
Explanation:
Motion in Plane
269909
A particle is moving eastwards with a velocity\(15 \mathrm{~ms}^{-1}\). Suddenly it moves towards north and moves with the same speed in a time \(10 \mathrm{sec}\). The average acceleration during this time is