269866 A body starts with a velocity(2i^+3j^+11k^)m/s and moves with an acceleration (5i^+5j^−5k^)m/s2. What is its velocity after 0.2 sec?
v^=u^+a^.t
269867 The position vector of a particle is given byr→=(3t2i^+4t2j^+7k^)m at a given time t. The net displacement of the particle after 10 s is
Att=0,r→1=7k→ At t=10,r→2=300i→+400j→+7k→;s→=r→2−r→1
269906 A force2i^+j^−k^ newton acts on a body which is initially at rest. If the velocity of the body at the end of 20 seconds is 4i^+2j^+2k^ ms−1, the mass of the body
v→=(a→)t, and f→=ma→
269907 The position vector of a moving particle at seconds is given byr→=3i^+4t2j^−t3k^. Its displacement during an interval of 1 s to 3 s is
Position vector at(t=1sec) is r→1 Position vector at ( t=3sec ) is r3→ Displacement s→=r→3−r→11
269908 If initial velocity of a body is u→=2i→−2j→+3k→ and the final velocity is v→=2i→−4j→+5k→ and it is changed in time of 10sec. Find the acceleration vector?
a→=v→−u→t