269753 A person is running athismaximum speed of \(4 \mathrm{~m} / \mathrm{s}\) to catch a train. When he is \(6 \mathrm{~m}\) from the door of the compartment the train starts to leave the station at a constant acceleration of \(1 \mathrm{~m} / \mathrm{s}^{2}\). Find how long it takes him to catch up the train
269770 The average velocity of a body moving with uniform acceleration after travelling a distance of\(3.06 \mathrm{~m}\) is \(0.34 \mathrm{~m} / \mathrm{s}\). If the change in velocity of the body is \(0.18 \mathrm{~ms}^{-1}\) during this time, itsuniform acceleration is ( in \(\mathrm{ms}^{-2}\) )
269753 A person is running athismaximum speed of \(4 \mathrm{~m} / \mathrm{s}\) to catch a train. When he is \(6 \mathrm{~m}\) from the door of the compartment the train starts to leave the station at a constant acceleration of \(1 \mathrm{~m} / \mathrm{s}^{2}\). Find how long it takes him to catch up the train
269770 The average velocity of a body moving with uniform acceleration after travelling a distance of\(3.06 \mathrm{~m}\) is \(0.34 \mathrm{~m} / \mathrm{s}\). If the change in velocity of the body is \(0.18 \mathrm{~ms}^{-1}\) during this time, itsuniform acceleration is ( in \(\mathrm{ms}^{-2}\) )
269753 A person is running athismaximum speed of \(4 \mathrm{~m} / \mathrm{s}\) to catch a train. When he is \(6 \mathrm{~m}\) from the door of the compartment the train starts to leave the station at a constant acceleration of \(1 \mathrm{~m} / \mathrm{s}^{2}\). Find how long it takes him to catch up the train
269770 The average velocity of a body moving with uniform acceleration after travelling a distance of\(3.06 \mathrm{~m}\) is \(0.34 \mathrm{~m} / \mathrm{s}\). If the change in velocity of the body is \(0.18 \mathrm{~ms}^{-1}\) during this time, itsuniform acceleration is ( in \(\mathrm{ms}^{-2}\) )
269753 A person is running athismaximum speed of \(4 \mathrm{~m} / \mathrm{s}\) to catch a train. When he is \(6 \mathrm{~m}\) from the door of the compartment the train starts to leave the station at a constant acceleration of \(1 \mathrm{~m} / \mathrm{s}^{2}\). Find how long it takes him to catch up the train
269770 The average velocity of a body moving with uniform acceleration after travelling a distance of\(3.06 \mathrm{~m}\) is \(0.34 \mathrm{~m} / \mathrm{s}\). If the change in velocity of the body is \(0.18 \mathrm{~ms}^{-1}\) during this time, itsuniform acceleration is ( in \(\mathrm{ms}^{-2}\) )