269669
The distance covered by a moving body is directly proportional to the square of thetime. The acceleration of the body is
1 increasing
2 decreasing
3 zero
4 constant
Explanation:
MOTION IN A STRIGHT LINE
269670
M ark the incorrect statement for a particle going on a straight line.
1 If the velocity and acceleration haveopposite sign, then theobject isslowing down.
2 If the position and velocity haveoppositesign, thentheparticleismoving towards theorigin.
3 If the velocity is zero at an instant, then the acceleration should also bezero at that instant.
4 If the velocity is zero for atimeinterval, then theacceleration is zero at any instant within the timeinterval.
Explanation:
MOTION IN A STRIGHT LINE
269707
A bullet travelling horizontallylooses \(1 / 20^{\text {th }}\) of itsvelocity while piercing a wooden plank. Then the number of such planksrequired to stop the bullet is
1 6
2 9
3 11
4 13
Explanation:
\(\frac{1}{n}=\frac{1}{20} \Rightarrow n=20 ;\) no. of planks \(=\frac{n^{2}}{2 n-1}\)
MOTION IN A STRIGHT LINE
269705
A body moves with a velocity of\(3 \mathrm{~m} / \mathrm{s}\) due east and then turns due north to travel with the same velocity. If the total time of travel is \(6 \mathrm{~s}\), the acceleration of the body is
1 \(\sqrt{3} \mathrm{~m} / \mathrm{s}^{2}\) towards north west
2 \(\frac{1}{\sqrt{2}} m / s^{2}\) towards north west
NEET Test Series from KOTA - 10 Papers In MS WORD
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MOTION IN A STRIGHT LINE
269669
The distance covered by a moving body is directly proportional to the square of thetime. The acceleration of the body is
1 increasing
2 decreasing
3 zero
4 constant
Explanation:
MOTION IN A STRIGHT LINE
269670
M ark the incorrect statement for a particle going on a straight line.
1 If the velocity and acceleration haveopposite sign, then theobject isslowing down.
2 If the position and velocity haveoppositesign, thentheparticleismoving towards theorigin.
3 If the velocity is zero at an instant, then the acceleration should also bezero at that instant.
4 If the velocity is zero for atimeinterval, then theacceleration is zero at any instant within the timeinterval.
Explanation:
MOTION IN A STRIGHT LINE
269707
A bullet travelling horizontallylooses \(1 / 20^{\text {th }}\) of itsvelocity while piercing a wooden plank. Then the number of such planksrequired to stop the bullet is
1 6
2 9
3 11
4 13
Explanation:
\(\frac{1}{n}=\frac{1}{20} \Rightarrow n=20 ;\) no. of planks \(=\frac{n^{2}}{2 n-1}\)
MOTION IN A STRIGHT LINE
269705
A body moves with a velocity of\(3 \mathrm{~m} / \mathrm{s}\) due east and then turns due north to travel with the same velocity. If the total time of travel is \(6 \mathrm{~s}\), the acceleration of the body is
1 \(\sqrt{3} \mathrm{~m} / \mathrm{s}^{2}\) towards north west
2 \(\frac{1}{\sqrt{2}} m / s^{2}\) towards north west
269669
The distance covered by a moving body is directly proportional to the square of thetime. The acceleration of the body is
1 increasing
2 decreasing
3 zero
4 constant
Explanation:
MOTION IN A STRIGHT LINE
269670
M ark the incorrect statement for a particle going on a straight line.
1 If the velocity and acceleration haveopposite sign, then theobject isslowing down.
2 If the position and velocity haveoppositesign, thentheparticleismoving towards theorigin.
3 If the velocity is zero at an instant, then the acceleration should also bezero at that instant.
4 If the velocity is zero for atimeinterval, then theacceleration is zero at any instant within the timeinterval.
Explanation:
MOTION IN A STRIGHT LINE
269707
A bullet travelling horizontallylooses \(1 / 20^{\text {th }}\) of itsvelocity while piercing a wooden plank. Then the number of such planksrequired to stop the bullet is
1 6
2 9
3 11
4 13
Explanation:
\(\frac{1}{n}=\frac{1}{20} \Rightarrow n=20 ;\) no. of planks \(=\frac{n^{2}}{2 n-1}\)
MOTION IN A STRIGHT LINE
269705
A body moves with a velocity of\(3 \mathrm{~m} / \mathrm{s}\) due east and then turns due north to travel with the same velocity. If the total time of travel is \(6 \mathrm{~s}\), the acceleration of the body is
1 \(\sqrt{3} \mathrm{~m} / \mathrm{s}^{2}\) towards north west
2 \(\frac{1}{\sqrt{2}} m / s^{2}\) towards north west
269669
The distance covered by a moving body is directly proportional to the square of thetime. The acceleration of the body is
1 increasing
2 decreasing
3 zero
4 constant
Explanation:
MOTION IN A STRIGHT LINE
269670
M ark the incorrect statement for a particle going on a straight line.
1 If the velocity and acceleration haveopposite sign, then theobject isslowing down.
2 If the position and velocity haveoppositesign, thentheparticleismoving towards theorigin.
3 If the velocity is zero at an instant, then the acceleration should also bezero at that instant.
4 If the velocity is zero for atimeinterval, then theacceleration is zero at any instant within the timeinterval.
Explanation:
MOTION IN A STRIGHT LINE
269707
A bullet travelling horizontallylooses \(1 / 20^{\text {th }}\) of itsvelocity while piercing a wooden plank. Then the number of such planksrequired to stop the bullet is
1 6
2 9
3 11
4 13
Explanation:
\(\frac{1}{n}=\frac{1}{20} \Rightarrow n=20 ;\) no. of planks \(=\frac{n^{2}}{2 n-1}\)
MOTION IN A STRIGHT LINE
269705
A body moves with a velocity of\(3 \mathrm{~m} / \mathrm{s}\) due east and then turns due north to travel with the same velocity. If the total time of travel is \(6 \mathrm{~s}\), the acceleration of the body is
1 \(\sqrt{3} \mathrm{~m} / \mathrm{s}^{2}\) towards north west
2 \(\frac{1}{\sqrt{2}} m / s^{2}\) towards north west
