VECTOR PRODUCT (OR) CROSS PRODUCT
Rotational Motion

269434 A uniform sphere has radius\(R\). A sphere of diameter \(R\) is cut from its edge as shown. Then the distance of centre of mass of remaining portion from the centre of mass of the original sphere is

1 R/7
2 \(R / 14\)
3 \(2 R / 7\)
4 \(R / 18\)
Rotational Motion

269435 The area of the parallelogram whose adjacent sides are\(P=3 \hat{i}+4 \hat{j} ; Q=-5 \hat{i}+7 \hat{j}\) is (in sq.units)

1 20.5
2 82
3 41
4 46
Rotational Motion

269436 If\(\vec{A}=3 i+j+2 k\) and \(\vec{B}=2 i-2 j+4 k\) and \(\theta\) is the angle between the two vectors, then \(\sin \theta\) is equal to

1 \(\frac{2}{3}\)
2 \(\frac{2}{\sqrt{3}}\)
3 \(\frac{2}{\sqrt{7}}\)
4 \(\frac{2}{\sqrt{13}}\)
Rotational Motion

269498 The unit vector perpendicular to \(\vec{A}=2 \hat{i}+3 \hat{j}+\hat{k}\) and \(\vec{B}=\hat{i}-\hat{j}+\hat{k}\) is

1 \(\frac{4 \hat{i}-\hat{j}-5 \hat{k}}{\sqrt{42}}\)
2 \(\frac{4 \hat{i}-\hat{j}+5 \hat{k}}{\sqrt{42}}\)
3 \(\frac{4 \hat{i}+\hat{j}+5 \hat{k}}{\sqrt{42}}\)
4 \(\frac{4 \hat{i}+\hat{j}-5 \hat{k}}{\sqrt{42}}\)
Rotational Motion

269434 A uniform sphere has radius\(R\). A sphere of diameter \(R\) is cut from its edge as shown. Then the distance of centre of mass of remaining portion from the centre of mass of the original sphere is

1 R/7
2 \(R / 14\)
3 \(2 R / 7\)
4 \(R / 18\)
Rotational Motion

269435 The area of the parallelogram whose adjacent sides are\(P=3 \hat{i}+4 \hat{j} ; Q=-5 \hat{i}+7 \hat{j}\) is (in sq.units)

1 20.5
2 82
3 41
4 46
Rotational Motion

269436 If\(\vec{A}=3 i+j+2 k\) and \(\vec{B}=2 i-2 j+4 k\) and \(\theta\) is the angle between the two vectors, then \(\sin \theta\) is equal to

1 \(\frac{2}{3}\)
2 \(\frac{2}{\sqrt{3}}\)
3 \(\frac{2}{\sqrt{7}}\)
4 \(\frac{2}{\sqrt{13}}\)
Rotational Motion

269498 The unit vector perpendicular to \(\vec{A}=2 \hat{i}+3 \hat{j}+\hat{k}\) and \(\vec{B}=\hat{i}-\hat{j}+\hat{k}\) is

1 \(\frac{4 \hat{i}-\hat{j}-5 \hat{k}}{\sqrt{42}}\)
2 \(\frac{4 \hat{i}-\hat{j}+5 \hat{k}}{\sqrt{42}}\)
3 \(\frac{4 \hat{i}+\hat{j}+5 \hat{k}}{\sqrt{42}}\)
4 \(\frac{4 \hat{i}+\hat{j}-5 \hat{k}}{\sqrt{42}}\)
Rotational Motion

269434 A uniform sphere has radius\(R\). A sphere of diameter \(R\) is cut from its edge as shown. Then the distance of centre of mass of remaining portion from the centre of mass of the original sphere is

1 R/7
2 \(R / 14\)
3 \(2 R / 7\)
4 \(R / 18\)
Rotational Motion

269435 The area of the parallelogram whose adjacent sides are\(P=3 \hat{i}+4 \hat{j} ; Q=-5 \hat{i}+7 \hat{j}\) is (in sq.units)

1 20.5
2 82
3 41
4 46
Rotational Motion

269436 If\(\vec{A}=3 i+j+2 k\) and \(\vec{B}=2 i-2 j+4 k\) and \(\theta\) is the angle between the two vectors, then \(\sin \theta\) is equal to

1 \(\frac{2}{3}\)
2 \(\frac{2}{\sqrt{3}}\)
3 \(\frac{2}{\sqrt{7}}\)
4 \(\frac{2}{\sqrt{13}}\)
Rotational Motion

269498 The unit vector perpendicular to \(\vec{A}=2 \hat{i}+3 \hat{j}+\hat{k}\) and \(\vec{B}=\hat{i}-\hat{j}+\hat{k}\) is

1 \(\frac{4 \hat{i}-\hat{j}-5 \hat{k}}{\sqrt{42}}\)
2 \(\frac{4 \hat{i}-\hat{j}+5 \hat{k}}{\sqrt{42}}\)
3 \(\frac{4 \hat{i}+\hat{j}+5 \hat{k}}{\sqrt{42}}\)
4 \(\frac{4 \hat{i}+\hat{j}-5 \hat{k}}{\sqrt{42}}\)
Rotational Motion

269434 A uniform sphere has radius\(R\). A sphere of diameter \(R\) is cut from its edge as shown. Then the distance of centre of mass of remaining portion from the centre of mass of the original sphere is

1 R/7
2 \(R / 14\)
3 \(2 R / 7\)
4 \(R / 18\)
Rotational Motion

269435 The area of the parallelogram whose adjacent sides are\(P=3 \hat{i}+4 \hat{j} ; Q=-5 \hat{i}+7 \hat{j}\) is (in sq.units)

1 20.5
2 82
3 41
4 46
Rotational Motion

269436 If\(\vec{A}=3 i+j+2 k\) and \(\vec{B}=2 i-2 j+4 k\) and \(\theta\) is the angle between the two vectors, then \(\sin \theta\) is equal to

1 \(\frac{2}{3}\)
2 \(\frac{2}{\sqrt{3}}\)
3 \(\frac{2}{\sqrt{7}}\)
4 \(\frac{2}{\sqrt{13}}\)
Rotational Motion

269498 The unit vector perpendicular to \(\vec{A}=2 \hat{i}+3 \hat{j}+\hat{k}\) and \(\vec{B}=\hat{i}-\hat{j}+\hat{k}\) is

1 \(\frac{4 \hat{i}-\hat{j}-5 \hat{k}}{\sqrt{42}}\)
2 \(\frac{4 \hat{i}-\hat{j}+5 \hat{k}}{\sqrt{42}}\)
3 \(\frac{4 \hat{i}+\hat{j}+5 \hat{k}}{\sqrt{42}}\)
4 \(\frac{4 \hat{i}+\hat{j}-5 \hat{k}}{\sqrt{42}}\)