269434
A uniform sphere has radius\(R\). A sphere of diameter \(R\) is cut from its edge as shown. Then the distance of centre of mass of remaining portion from the centre of mass of the original sphere is
1 R/7
2 \(R / 14\)
3 \(2 R / 7\)
4 \(R / 18\)
Explanation:
shift \(=\frac{r^{3} d}{R^{3}-r^{3}}\)
Rotational Motion
269435
The area of the parallelogram whose adjacent sides are\(P=3 \hat{i}+4 \hat{j} ; Q=-5 \hat{i}+7 \hat{j}\) is (in sq.units)
1 20.5
2 82
3 41
4 46
Explanation:
Area of parallelogram\(=|\vec{P} \times \vec{Q}|\)
Rotational Motion
269436
If\(\vec{A}=3 i+j+2 k\) and \(\vec{B}=2 i-2 j+4 k\) and \(\theta\) is the angle between the two vectors, then \(\sin \theta\) is equal to
269434
A uniform sphere has radius\(R\). A sphere of diameter \(R\) is cut from its edge as shown. Then the distance of centre of mass of remaining portion from the centre of mass of the original sphere is
1 R/7
2 \(R / 14\)
3 \(2 R / 7\)
4 \(R / 18\)
Explanation:
shift \(=\frac{r^{3} d}{R^{3}-r^{3}}\)
Rotational Motion
269435
The area of the parallelogram whose adjacent sides are\(P=3 \hat{i}+4 \hat{j} ; Q=-5 \hat{i}+7 \hat{j}\) is (in sq.units)
1 20.5
2 82
3 41
4 46
Explanation:
Area of parallelogram\(=|\vec{P} \times \vec{Q}|\)
Rotational Motion
269436
If\(\vec{A}=3 i+j+2 k\) and \(\vec{B}=2 i-2 j+4 k\) and \(\theta\) is the angle between the two vectors, then \(\sin \theta\) is equal to
269434
A uniform sphere has radius\(R\). A sphere of diameter \(R\) is cut from its edge as shown. Then the distance of centre of mass of remaining portion from the centre of mass of the original sphere is
1 R/7
2 \(R / 14\)
3 \(2 R / 7\)
4 \(R / 18\)
Explanation:
shift \(=\frac{r^{3} d}{R^{3}-r^{3}}\)
Rotational Motion
269435
The area of the parallelogram whose adjacent sides are\(P=3 \hat{i}+4 \hat{j} ; Q=-5 \hat{i}+7 \hat{j}\) is (in sq.units)
1 20.5
2 82
3 41
4 46
Explanation:
Area of parallelogram\(=|\vec{P} \times \vec{Q}|\)
Rotational Motion
269436
If\(\vec{A}=3 i+j+2 k\) and \(\vec{B}=2 i-2 j+4 k\) and \(\theta\) is the angle between the two vectors, then \(\sin \theta\) is equal to
269434
A uniform sphere has radius\(R\). A sphere of diameter \(R\) is cut from its edge as shown. Then the distance of centre of mass of remaining portion from the centre of mass of the original sphere is
1 R/7
2 \(R / 14\)
3 \(2 R / 7\)
4 \(R / 18\)
Explanation:
shift \(=\frac{r^{3} d}{R^{3}-r^{3}}\)
Rotational Motion
269435
The area of the parallelogram whose adjacent sides are\(P=3 \hat{i}+4 \hat{j} ; Q=-5 \hat{i}+7 \hat{j}\) is (in sq.units)
1 20.5
2 82
3 41
4 46
Explanation:
Area of parallelogram\(=|\vec{P} \times \vec{Q}|\)
Rotational Motion
269436
If\(\vec{A}=3 i+j+2 k\) and \(\vec{B}=2 i-2 j+4 k\) and \(\theta\) is the angle between the two vectors, then \(\sin \theta\) is equal to