268977 If \(\vec{a}\) and \(\vec{b}\) are two unit vectors and the angle between them is \(60^{0}\) then \(\frac{(1+\vec{a} \cdot \vec{b})}{(1-\vec{a} \cdot \vec{b})}\) is
\(\frac{1+\vec{a} \cdot \vec{b}}{1-\vec{a} \cdot \vec{b}}=\frac{1+\cos \theta}{1-\cos \theta}=\cot ^{2} \Theta^{\theta}-\frac{\theta}{2}\)
