268983 A man travels \(\mathbf{1}\) mile due east, then 5 miles due south, then 2 miles due east and finally 9 miles due north. His displacement is

268958 The vector sum of two vectors of magnitudes 10 units and 15 units can never be

268959 A car moves \(40 \mathrm{~m}\) due east and turns towards north and moves \(30 \mathrm{~m}\) then turns \(45^{\circ}\) east of north and moves \(20 \sqrt{2} \mathrm{~m}\). The net displacement of car is ( east is taken positive \(x\)-axis, North as positive \(\mathbf{y}\)-axis)

268956 If \(\vec{A}=3 \hat{i}-4 \hat{j}\) and \(\vec{B}=-\hat{i}-4 \hat{j}\), calculate the direction of \(\vec{A}-\vec{B}\).

268957 The resultant of the forces \(\vec{F}_{1}=4 \hat{i}-3 \hat{j}\) and \(\overrightarrow{F_{2}}=6 \hat{i}+8 \hat{j}\) is

268983 A man travels \(\mathbf{1}\) mile due east, then 5 miles due south, then 2 miles due east and finally 9 miles due north. His displacement is

268958 The vector sum of two vectors of magnitudes 10 units and 15 units can never be

268959 A car moves \(40 \mathrm{~m}\) due east and turns towards north and moves \(30 \mathrm{~m}\) then turns \(45^{\circ}\) east of north and moves \(20 \sqrt{2} \mathrm{~m}\). The net displacement of car is ( east is taken positive \(x\)-axis, North as positive \(\mathbf{y}\)-axis)

268956 If \(\vec{A}=3 \hat{i}-4 \hat{j}\) and \(\vec{B}=-\hat{i}-4 \hat{j}\), calculate the direction of \(\vec{A}-\vec{B}\).

268957 The resultant of the forces \(\vec{F}_{1}=4 \hat{i}-3 \hat{j}\) and \(\overrightarrow{F_{2}}=6 \hat{i}+8 \hat{j}\) is

268983 A man travels \(\mathbf{1}\) mile due east, then 5 miles due south, then 2 miles due east and finally 9 miles due north. His displacement is

268958 The vector sum of two vectors of magnitudes 10 units and 15 units can never be

268959 A car moves \(40 \mathrm{~m}\) due east and turns towards north and moves \(30 \mathrm{~m}\) then turns \(45^{\circ}\) east of north and moves \(20 \sqrt{2} \mathrm{~m}\). The net displacement of car is ( east is taken positive \(x\)-axis, North as positive \(\mathbf{y}\)-axis)

268956 If \(\vec{A}=3 \hat{i}-4 \hat{j}\) and \(\vec{B}=-\hat{i}-4 \hat{j}\), calculate the direction of \(\vec{A}-\vec{B}\).

268957 The resultant of the forces \(\vec{F}_{1}=4 \hat{i}-3 \hat{j}\) and \(\overrightarrow{F_{2}}=6 \hat{i}+8 \hat{j}\) is

268983 A man travels \(\mathbf{1}\) mile due east, then 5 miles due south, then 2 miles due east and finally 9 miles due north. His displacement is

268958 The vector sum of two vectors of magnitudes 10 units and 15 units can never be

268959 A car moves \(40 \mathrm{~m}\) due east and turns towards north and moves \(30 \mathrm{~m}\) then turns \(45^{\circ}\) east of north and moves \(20 \sqrt{2} \mathrm{~m}\). The net displacement of car is ( east is taken positive \(x\)-axis, North as positive \(\mathbf{y}\)-axis)

268956 If \(\vec{A}=3 \hat{i}-4 \hat{j}\) and \(\vec{B}=-\hat{i}-4 \hat{j}\), calculate the direction of \(\vec{A}-\vec{B}\).

268957 The resultant of the forces \(\vec{F}_{1}=4 \hat{i}-3 \hat{j}\) and \(\overrightarrow{F_{2}}=6 \hat{i}+8 \hat{j}\) is

268983 A man travels \(\mathbf{1}\) mile due east, then 5 miles due south, then 2 miles due east and finally 9 miles due north. His displacement is

268958 The vector sum of two vectors of magnitudes 10 units and 15 units can never be

268959 A car moves \(40 \mathrm{~m}\) due east and turns towards north and moves \(30 \mathrm{~m}\) then turns \(45^{\circ}\) east of north and moves \(20 \sqrt{2} \mathrm{~m}\). The net displacement of car is ( east is taken positive \(x\)-axis, North as positive \(\mathbf{y}\)-axis)

268956 If \(\vec{A}=3 \hat{i}-4 \hat{j}\) and \(\vec{B}=-\hat{i}-4 \hat{j}\), calculate the direction of \(\vec{A}-\vec{B}\).

268957 The resultant of the forces \(\vec{F}_{1}=4 \hat{i}-3 \hat{j}\) and \(\overrightarrow{F_{2}}=6 \hat{i}+8 \hat{j}\) is