CELLS,KIRCHOFF'SLAW'S, WHEAT STONE BRIDGE
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Current Electricity

268539 Find out the value ofcưrrent through \(2 \Omega\) resistance for the given circuit.

1 0
2 \(1.6 \mathrm{~A}\)
3 \(2.4 \mathrm{~A}\)
4 3A
Current Electricity

268525 A group of\(\mathrm{N}\) cells wheree.m.f. varies directly with the internal resistance as per the equation \(E_{N}=1.5 r_{N}\) are connected as shown in the figure. The current I in the circuit is:

1 \(0.51 \mathrm{~A}\)
2 \(5.1 \mathrm{~A}\)
3 \(0.15 \mathrm{~A}\)
4 \(1.5 \mathrm{~A}\)
Current Electricity

268526 Cell\(A\) has emf \(2 E\) and internal resistannce \(4 r\). Cell \(B\) has emf \(E\) and internal resistance \(r\). The negative of \(A\) is connected to the positive of \(B\) and a load resistance of \(R\) is connected across the battery formed. If the terminal potential difference across A is zero, then \(R\) is equal to

1 \(3 r\)
2 \(2 r\)
3 \(r\)
4 \(5 r\)
Current Electricity

268527 For the circuit shown in the figure, potential difference between points\(A\) and \(B\) is \(16 \mathrm{~V}\). Find the current passing through \(2 \Omega\)

1 \(3.5 \mathrm{~A}\)
2 \(3 \mathrm{~A}\)
3 \(4.5 \mathrm{~A}\)
4 \(5.5 \mathrm{~A}\)
Current Electricity

268528 Theminimum number of cells in mixed group ing required to produce a maximum current of \(1.5 \mathrm{~A}\) through an external resistance of \(30 \Omega\),given the emf of each cell is \(1.5 \mathrm{~V}\) and internal resistance is \(1 \Omega\) is

1 30
2 120
3 40
4 60
NEET DIGITAL LIBRARY
Current Electricity

268539 Find out the value ofcưrrent through \(2 \Omega\) resistance for the given circuit.

1 0
2 \(1.6 \mathrm{~A}\)
3 \(2.4 \mathrm{~A}\)
4 3A
Current Electricity

268525 A group of\(\mathrm{N}\) cells wheree.m.f. varies directly with the internal resistance as per the equation \(E_{N}=1.5 r_{N}\) are connected as shown in the figure. The current I in the circuit is:

1 \(0.51 \mathrm{~A}\)
2 \(5.1 \mathrm{~A}\)
3 \(0.15 \mathrm{~A}\)
4 \(1.5 \mathrm{~A}\)
Current Electricity

268526 Cell\(A\) has emf \(2 E\) and internal resistannce \(4 r\). Cell \(B\) has emf \(E\) and internal resistance \(r\). The negative of \(A\) is connected to the positive of \(B\) and a load resistance of \(R\) is connected across the battery formed. If the terminal potential difference across A is zero, then \(R\) is equal to

1 \(3 r\)
2 \(2 r\)
3 \(r\)
4 \(5 r\)
Current Electricity

268527 For the circuit shown in the figure, potential difference between points\(A\) and \(B\) is \(16 \mathrm{~V}\). Find the current passing through \(2 \Omega\)

1 \(3.5 \mathrm{~A}\)
2 \(3 \mathrm{~A}\)
3 \(4.5 \mathrm{~A}\)
4 \(5.5 \mathrm{~A}\)
Current Electricity

268528 Theminimum number of cells in mixed group ing required to produce a maximum current of \(1.5 \mathrm{~A}\) through an external resistance of \(30 \Omega\),given the emf of each cell is \(1.5 \mathrm{~V}\) and internal resistance is \(1 \Omega\) is

1 30
2 120
3 40
4 60
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Current Electricity

268539 Find out the value ofcưrrent through \(2 \Omega\) resistance for the given circuit.

1 0
2 \(1.6 \mathrm{~A}\)
3 \(2.4 \mathrm{~A}\)
4 3A
Current Electricity

268525 A group of\(\mathrm{N}\) cells wheree.m.f. varies directly with the internal resistance as per the equation \(E_{N}=1.5 r_{N}\) are connected as shown in the figure. The current I in the circuit is:

1 \(0.51 \mathrm{~A}\)
2 \(5.1 \mathrm{~A}\)
3 \(0.15 \mathrm{~A}\)
4 \(1.5 \mathrm{~A}\)
Current Electricity

268526 Cell\(A\) has emf \(2 E\) and internal resistannce \(4 r\). Cell \(B\) has emf \(E\) and internal resistance \(r\). The negative of \(A\) is connected to the positive of \(B\) and a load resistance of \(R\) is connected across the battery formed. If the terminal potential difference across A is zero, then \(R\) is equal to

1 \(3 r\)
2 \(2 r\)
3 \(r\)
4 \(5 r\)
Current Electricity

268527 For the circuit shown in the figure, potential difference between points\(A\) and \(B\) is \(16 \mathrm{~V}\). Find the current passing through \(2 \Omega\)

1 \(3.5 \mathrm{~A}\)
2 \(3 \mathrm{~A}\)
3 \(4.5 \mathrm{~A}\)
4 \(5.5 \mathrm{~A}\)
Current Electricity

268528 Theminimum number of cells in mixed group ing required to produce a maximum current of \(1.5 \mathrm{~A}\) through an external resistance of \(30 \Omega\),given the emf of each cell is \(1.5 \mathrm{~V}\) and internal resistance is \(1 \Omega\) is

1 30
2 120
3 40
4 60
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Current Electricity

268539 Find out the value ofcưrrent through \(2 \Omega\) resistance for the given circuit.

1 0
2 \(1.6 \mathrm{~A}\)
3 \(2.4 \mathrm{~A}\)
4 3A
Current Electricity

268525 A group of\(\mathrm{N}\) cells wheree.m.f. varies directly with the internal resistance as per the equation \(E_{N}=1.5 r_{N}\) are connected as shown in the figure. The current I in the circuit is:

1 \(0.51 \mathrm{~A}\)
2 \(5.1 \mathrm{~A}\)
3 \(0.15 \mathrm{~A}\)
4 \(1.5 \mathrm{~A}\)
Current Electricity

268526 Cell\(A\) has emf \(2 E\) and internal resistannce \(4 r\). Cell \(B\) has emf \(E\) and internal resistance \(r\). The negative of \(A\) is connected to the positive of \(B\) and a load resistance of \(R\) is connected across the battery formed. If the terminal potential difference across A is zero, then \(R\) is equal to

1 \(3 r\)
2 \(2 r\)
3 \(r\)
4 \(5 r\)
Current Electricity

268527 For the circuit shown in the figure, potential difference between points\(A\) and \(B\) is \(16 \mathrm{~V}\). Find the current passing through \(2 \Omega\)

1 \(3.5 \mathrm{~A}\)
2 \(3 \mathrm{~A}\)
3 \(4.5 \mathrm{~A}\)
4 \(5.5 \mathrm{~A}\)
Current Electricity

268528 Theminimum number of cells in mixed group ing required to produce a maximum current of \(1.5 \mathrm{~A}\) through an external resistance of \(30 \Omega\),given the emf of each cell is \(1.5 \mathrm{~V}\) and internal resistance is \(1 \Omega\) is

1 30
2 120
3 40
4 60
NEET DIGITAL LIBRARY
Current Electricity

268539 Find out the value ofcưrrent through \(2 \Omega\) resistance for the given circuit.

1 0
2 \(1.6 \mathrm{~A}\)
3 \(2.4 \mathrm{~A}\)
4 3A
Current Electricity

268525 A group of\(\mathrm{N}\) cells wheree.m.f. varies directly with the internal resistance as per the equation \(E_{N}=1.5 r_{N}\) are connected as shown in the figure. The current I in the circuit is:

1 \(0.51 \mathrm{~A}\)
2 \(5.1 \mathrm{~A}\)
3 \(0.15 \mathrm{~A}\)
4 \(1.5 \mathrm{~A}\)
Current Electricity

268526 Cell\(A\) has emf \(2 E\) and internal resistannce \(4 r\). Cell \(B\) has emf \(E\) and internal resistance \(r\). The negative of \(A\) is connected to the positive of \(B\) and a load resistance of \(R\) is connected across the battery formed. If the terminal potential difference across A is zero, then \(R\) is equal to

1 \(3 r\)
2 \(2 r\)
3 \(r\)
4 \(5 r\)
Current Electricity

268527 For the circuit shown in the figure, potential difference between points\(A\) and \(B\) is \(16 \mathrm{~V}\). Find the current passing through \(2 \Omega\)

1 \(3.5 \mathrm{~A}\)
2 \(3 \mathrm{~A}\)
3 \(4.5 \mathrm{~A}\)
4 \(5.5 \mathrm{~A}\)
Current Electricity

268528 Theminimum number of cells in mixed group ing required to produce a maximum current of \(1.5 \mathrm{~A}\) through an external resistance of \(30 \Omega\),given the emf of each cell is \(1.5 \mathrm{~V}\) and internal resistance is \(1 \Omega\) is

1 30
2 120
3 40
4 60