268505
In the given circuit which is a part of a closedcirucit the current \(\mathrm{i}_{1}\), \(\mathrm{i}_{2}\) are respcetively
1 \(0.4 \mathrm{~A}\)
2 \(0.6 \mathrm{~A}\)
3 \(1.6 \mathrm{~A}\)
4 \(2 \mathrm{~A}\)
Explanation:
Applyingkirchoff's law
Current Electricity
268506
A 5V battery with internal resistance\(2 \Omega\) and \(\mathrm{a} 2 \mathrm{~V}\) battery with internal resistance \(1 \Omega\) are connected to a \(100_{\Omega}\) resistor as shown in the figure [M ains-2008] Thecurrent in the \(10_{\Omega}^{P}\) resistor is
268505
In the given circuit which is a part of a closedcirucit the current \(\mathrm{i}_{1}\), \(\mathrm{i}_{2}\) are respcetively
1 \(0.4 \mathrm{~A}\)
2 \(0.6 \mathrm{~A}\)
3 \(1.6 \mathrm{~A}\)
4 \(2 \mathrm{~A}\)
Explanation:
Applyingkirchoff's law
Current Electricity
268506
A 5V battery with internal resistance\(2 \Omega\) and \(\mathrm{a} 2 \mathrm{~V}\) battery with internal resistance \(1 \Omega\) are connected to a \(100_{\Omega}\) resistor as shown in the figure [M ains-2008] Thecurrent in the \(10_{\Omega}^{P}\) resistor is