KIRCHOFF'SLAWSAND WHEAT SHONE'S BRIDGE
Current Electricity

268458 Theelectric current \(i\) in the circuit shown is ( \(\mathrm{E}-2011\) )

1 \(6 \mathrm{~A}\)
2 \(2 \mathrm{~A}\)
3 \(3 \mathrm{~A}\)
4 \(4 \mathrm{~A}\)
Current Electricity

268459 In the circuit shown in the figure, the current ' \(I\) ' is

1 \(6 \mathrm{~A}\)
2 \(2 \mathrm{~A}\)
3 \(4 \mathrm{~A}\)
4 \(7 \mathrm{~A}\)
Current Electricity

268460 Four resistors \(A, B, C\) and \(D\) form a wheatstone's bridge. The bridge is balanced when \(C=100 \Omega\). If \(A\) and \(B\) are inter changed, the bridge balances for \(C=121 \Omega\). The vlaue of \(D\) is
( E-2012)

1 \(10 \Omega\)
2 \(100 \Omega\)
3 \(110 \Omega\)
4 \(120 \Omega\)
Current Electricity

268461 In the circuit shown below, the ammeter reading is zero. Then the value of the resistance \(R\) is
( E-2011)

1 \(50 \Omega\)
2 \(100 \Omega_{500 \Omega}\)
3 \(200 \Omega\)
4 \(400 \Omega\)
Current Electricity

268504 The current\(i\) drawn from the 5 volt source will be

1 0.5
2 \(2 \mathrm{~A}\)
3 \(1.5 \mathrm{~A}\)
4 \(3 \mathrm{~A}\)
Current Electricity

268458 Theelectric current \(i\) in the circuit shown is ( \(\mathrm{E}-2011\) )

1 \(6 \mathrm{~A}\)
2 \(2 \mathrm{~A}\)
3 \(3 \mathrm{~A}\)
4 \(4 \mathrm{~A}\)
Current Electricity

268459 In the circuit shown in the figure, the current ' \(I\) ' is

1 \(6 \mathrm{~A}\)
2 \(2 \mathrm{~A}\)
3 \(4 \mathrm{~A}\)
4 \(7 \mathrm{~A}\)
Current Electricity

268460 Four resistors \(A, B, C\) and \(D\) form a wheatstone's bridge. The bridge is balanced when \(C=100 \Omega\). If \(A\) and \(B\) are inter changed, the bridge balances for \(C=121 \Omega\). The vlaue of \(D\) is
( E-2012)

1 \(10 \Omega\)
2 \(100 \Omega\)
3 \(110 \Omega\)
4 \(120 \Omega\)
Current Electricity

268461 In the circuit shown below, the ammeter reading is zero. Then the value of the resistance \(R\) is
( E-2011)

1 \(50 \Omega\)
2 \(100 \Omega_{500 \Omega}\)
3 \(200 \Omega\)
4 \(400 \Omega\)
Current Electricity

268504 The current\(i\) drawn from the 5 volt source will be

1 0.5
2 \(2 \mathrm{~A}\)
3 \(1.5 \mathrm{~A}\)
4 \(3 \mathrm{~A}\)
Current Electricity

268458 Theelectric current \(i\) in the circuit shown is ( \(\mathrm{E}-2011\) )

1 \(6 \mathrm{~A}\)
2 \(2 \mathrm{~A}\)
3 \(3 \mathrm{~A}\)
4 \(4 \mathrm{~A}\)
Current Electricity

268459 In the circuit shown in the figure, the current ' \(I\) ' is

1 \(6 \mathrm{~A}\)
2 \(2 \mathrm{~A}\)
3 \(4 \mathrm{~A}\)
4 \(7 \mathrm{~A}\)
Current Electricity

268460 Four resistors \(A, B, C\) and \(D\) form a wheatstone's bridge. The bridge is balanced when \(C=100 \Omega\). If \(A\) and \(B\) are inter changed, the bridge balances for \(C=121 \Omega\). The vlaue of \(D\) is
( E-2012)

1 \(10 \Omega\)
2 \(100 \Omega\)
3 \(110 \Omega\)
4 \(120 \Omega\)
Current Electricity

268461 In the circuit shown below, the ammeter reading is zero. Then the value of the resistance \(R\) is
( E-2011)

1 \(50 \Omega\)
2 \(100 \Omega_{500 \Omega}\)
3 \(200 \Omega\)
4 \(400 \Omega\)
Current Electricity

268504 The current\(i\) drawn from the 5 volt source will be

1 0.5
2 \(2 \mathrm{~A}\)
3 \(1.5 \mathrm{~A}\)
4 \(3 \mathrm{~A}\)
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Current Electricity

268458 Theelectric current \(i\) in the circuit shown is ( \(\mathrm{E}-2011\) )

1 \(6 \mathrm{~A}\)
2 \(2 \mathrm{~A}\)
3 \(3 \mathrm{~A}\)
4 \(4 \mathrm{~A}\)
Current Electricity

268459 In the circuit shown in the figure, the current ' \(I\) ' is

1 \(6 \mathrm{~A}\)
2 \(2 \mathrm{~A}\)
3 \(4 \mathrm{~A}\)
4 \(7 \mathrm{~A}\)
Current Electricity

268460 Four resistors \(A, B, C\) and \(D\) form a wheatstone's bridge. The bridge is balanced when \(C=100 \Omega\). If \(A\) and \(B\) are inter changed, the bridge balances for \(C=121 \Omega\). The vlaue of \(D\) is
( E-2012)

1 \(10 \Omega\)
2 \(100 \Omega\)
3 \(110 \Omega\)
4 \(120 \Omega\)
Current Electricity

268461 In the circuit shown below, the ammeter reading is zero. Then the value of the resistance \(R\) is
( E-2011)

1 \(50 \Omega\)
2 \(100 \Omega_{500 \Omega}\)
3 \(200 \Omega\)
4 \(400 \Omega\)
Current Electricity

268504 The current\(i\) drawn from the 5 volt source will be

1 0.5
2 \(2 \mathrm{~A}\)
3 \(1.5 \mathrm{~A}\)
4 \(3 \mathrm{~A}\)
Current Electricity

268458 Theelectric current \(i\) in the circuit shown is ( \(\mathrm{E}-2011\) )

1 \(6 \mathrm{~A}\)
2 \(2 \mathrm{~A}\)
3 \(3 \mathrm{~A}\)
4 \(4 \mathrm{~A}\)
Current Electricity

268459 In the circuit shown in the figure, the current ' \(I\) ' is

1 \(6 \mathrm{~A}\)
2 \(2 \mathrm{~A}\)
3 \(4 \mathrm{~A}\)
4 \(7 \mathrm{~A}\)
Current Electricity

268460 Four resistors \(A, B, C\) and \(D\) form a wheatstone's bridge. The bridge is balanced when \(C=100 \Omega\). If \(A\) and \(B\) are inter changed, the bridge balances for \(C=121 \Omega\). The vlaue of \(D\) is
( E-2012)

1 \(10 \Omega\)
2 \(100 \Omega\)
3 \(110 \Omega\)
4 \(120 \Omega\)
Current Electricity

268461 In the circuit shown below, the ammeter reading is zero. Then the value of the resistance \(R\) is
( E-2011)

1 \(50 \Omega\)
2 \(100 \Omega_{500 \Omega}\)
3 \(200 \Omega\)
4 \(400 \Omega\)
Current Electricity

268504 The current\(i\) drawn from the 5 volt source will be

1 0.5
2 \(2 \mathrm{~A}\)
3 \(1.5 \mathrm{~A}\)
4 \(3 \mathrm{~A}\)