INTERNAL RESISTANCE AND EMF
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Current Electricity

268493 The potential difference across the terminals of a battery is\(10 \mathrm{~V}\) when there is a current of \(3 A\) in the battery from the negative to the positive terminal. When the current is \(2 \mathrm{~A}\) in the reverse direction, the potential difference becomes \(15 \mathrm{~V}\). T he internal resistance of the battery is

1 \(1 \Omega\)
2 \(0.4 \Omega\)
3 \(0.6 \Omega\)
4 \(0.8 \Omega\)
Current Electricity

268494 Two cells ofemf \(3 \mathrm{~V}\) and \(5 \mathrm{~V}\) and internal resistance \(r_{1}\) and \(r_{2}\) respectively are in series with an external resistance R. If the p.d. across 1st cell is zero, then \(R\) is

1 \(\frac{5 r_{1}-3 r_{2}}{3}\)
2 \(\frac{2 r_{1}-3 r_{2}}{4}\)
3 \(\frac{3 r_{1}-5 r_{2}}{3}\)
4 \(\frac{4 r_{1}-5 r_{2}}{3}\)
Current Electricity

268495 A battery when connected by a resistance of\(16 \Omega\) gives a terminal voltage of \(12 \mathrm{~V}\). and when connected by a resistance of \(10 \Omega\) gives a terminal voltage of 11V. Then the emf of the battery and its internal resistance

1 \(12.8 \mathrm{~V}\)
2 \(13.7 \mathrm{~V}\)
3 \(10.7 \mathrm{~V}\)
4 \(9 \mathrm{~V}\)
Current Electricity

268496 When a resistor of 11 ohm is connected in series with an electric cell the current flowing in it is\(0.5 \mathrm{~A}\). Instead, when a resistor of \(5 \Omega\) is connected to the same electric cell in series, the current increases by \(0.4 \mathrm{~A}\). The internal resistance of cell is

1 \(1.5 \Omega\)
2 \(2 \Omega\)
3 \(2.5 \Omega\)
4 \(6 \Omega\)
Current Electricity

268497 Two cells ofemf \(4 \mathrm{~V}\) and \(8 \mathrm{~V}\) are connected to two resister \(4 \Omega\) and \(6 \Omega\) as shown. If \(8 \mathrm{~V}\) cell is short circuited. Then current through resistance \(4 \Omega\) and \(6 \Omega\)

1 2 A
2 1 A
3 2.5 A
4 3 A
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Current Electricity

268493 The potential difference across the terminals of a battery is\(10 \mathrm{~V}\) when there is a current of \(3 A\) in the battery from the negative to the positive terminal. When the current is \(2 \mathrm{~A}\) in the reverse direction, the potential difference becomes \(15 \mathrm{~V}\). T he internal resistance of the battery is

1 \(1 \Omega\)
2 \(0.4 \Omega\)
3 \(0.6 \Omega\)
4 \(0.8 \Omega\)
Current Electricity

268494 Two cells ofemf \(3 \mathrm{~V}\) and \(5 \mathrm{~V}\) and internal resistance \(r_{1}\) and \(r_{2}\) respectively are in series with an external resistance R. If the p.d. across 1st cell is zero, then \(R\) is

1 \(\frac{5 r_{1}-3 r_{2}}{3}\)
2 \(\frac{2 r_{1}-3 r_{2}}{4}\)
3 \(\frac{3 r_{1}-5 r_{2}}{3}\)
4 \(\frac{4 r_{1}-5 r_{2}}{3}\)
Current Electricity

268495 A battery when connected by a resistance of\(16 \Omega\) gives a terminal voltage of \(12 \mathrm{~V}\). and when connected by a resistance of \(10 \Omega\) gives a terminal voltage of 11V. Then the emf of the battery and its internal resistance

1 \(12.8 \mathrm{~V}\)
2 \(13.7 \mathrm{~V}\)
3 \(10.7 \mathrm{~V}\)
4 \(9 \mathrm{~V}\)
Current Electricity

268496 When a resistor of 11 ohm is connected in series with an electric cell the current flowing in it is\(0.5 \mathrm{~A}\). Instead, when a resistor of \(5 \Omega\) is connected to the same electric cell in series, the current increases by \(0.4 \mathrm{~A}\). The internal resistance of cell is

1 \(1.5 \Omega\)
2 \(2 \Omega\)
3 \(2.5 \Omega\)
4 \(6 \Omega\)
Current Electricity

268497 Two cells ofemf \(4 \mathrm{~V}\) and \(8 \mathrm{~V}\) are connected to two resister \(4 \Omega\) and \(6 \Omega\) as shown. If \(8 \mathrm{~V}\) cell is short circuited. Then current through resistance \(4 \Omega\) and \(6 \Omega\)

1 2 A
2 1 A
3 2.5 A
4 3 A
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Current Electricity

268493 The potential difference across the terminals of a battery is\(10 \mathrm{~V}\) when there is a current of \(3 A\) in the battery from the negative to the positive terminal. When the current is \(2 \mathrm{~A}\) in the reverse direction, the potential difference becomes \(15 \mathrm{~V}\). T he internal resistance of the battery is

1 \(1 \Omega\)
2 \(0.4 \Omega\)
3 \(0.6 \Omega\)
4 \(0.8 \Omega\)
Current Electricity

268494 Two cells ofemf \(3 \mathrm{~V}\) and \(5 \mathrm{~V}\) and internal resistance \(r_{1}\) and \(r_{2}\) respectively are in series with an external resistance R. If the p.d. across 1st cell is zero, then \(R\) is

1 \(\frac{5 r_{1}-3 r_{2}}{3}\)
2 \(\frac{2 r_{1}-3 r_{2}}{4}\)
3 \(\frac{3 r_{1}-5 r_{2}}{3}\)
4 \(\frac{4 r_{1}-5 r_{2}}{3}\)
Current Electricity

268495 A battery when connected by a resistance of\(16 \Omega\) gives a terminal voltage of \(12 \mathrm{~V}\). and when connected by a resistance of \(10 \Omega\) gives a terminal voltage of 11V. Then the emf of the battery and its internal resistance

1 \(12.8 \mathrm{~V}\)
2 \(13.7 \mathrm{~V}\)
3 \(10.7 \mathrm{~V}\)
4 \(9 \mathrm{~V}\)
Current Electricity

268496 When a resistor of 11 ohm is connected in series with an electric cell the current flowing in it is\(0.5 \mathrm{~A}\). Instead, when a resistor of \(5 \Omega\) is connected to the same electric cell in series, the current increases by \(0.4 \mathrm{~A}\). The internal resistance of cell is

1 \(1.5 \Omega\)
2 \(2 \Omega\)
3 \(2.5 \Omega\)
4 \(6 \Omega\)
Current Electricity

268497 Two cells ofemf \(4 \mathrm{~V}\) and \(8 \mathrm{~V}\) are connected to two resister \(4 \Omega\) and \(6 \Omega\) as shown. If \(8 \mathrm{~V}\) cell is short circuited. Then current through resistance \(4 \Omega\) and \(6 \Omega\)

1 2 A
2 1 A
3 2.5 A
4 3 A
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Current Electricity

268493 The potential difference across the terminals of a battery is\(10 \mathrm{~V}\) when there is a current of \(3 A\) in the battery from the negative to the positive terminal. When the current is \(2 \mathrm{~A}\) in the reverse direction, the potential difference becomes \(15 \mathrm{~V}\). T he internal resistance of the battery is

1 \(1 \Omega\)
2 \(0.4 \Omega\)
3 \(0.6 \Omega\)
4 \(0.8 \Omega\)
Current Electricity

268494 Two cells ofemf \(3 \mathrm{~V}\) and \(5 \mathrm{~V}\) and internal resistance \(r_{1}\) and \(r_{2}\) respectively are in series with an external resistance R. If the p.d. across 1st cell is zero, then \(R\) is

1 \(\frac{5 r_{1}-3 r_{2}}{3}\)
2 \(\frac{2 r_{1}-3 r_{2}}{4}\)
3 \(\frac{3 r_{1}-5 r_{2}}{3}\)
4 \(\frac{4 r_{1}-5 r_{2}}{3}\)
Current Electricity

268495 A battery when connected by a resistance of\(16 \Omega\) gives a terminal voltage of \(12 \mathrm{~V}\). and when connected by a resistance of \(10 \Omega\) gives a terminal voltage of 11V. Then the emf of the battery and its internal resistance

1 \(12.8 \mathrm{~V}\)
2 \(13.7 \mathrm{~V}\)
3 \(10.7 \mathrm{~V}\)
4 \(9 \mathrm{~V}\)
Current Electricity

268496 When a resistor of 11 ohm is connected in series with an electric cell the current flowing in it is\(0.5 \mathrm{~A}\). Instead, when a resistor of \(5 \Omega\) is connected to the same electric cell in series, the current increases by \(0.4 \mathrm{~A}\). The internal resistance of cell is

1 \(1.5 \Omega\)
2 \(2 \Omega\)
3 \(2.5 \Omega\)
4 \(6 \Omega\)
Current Electricity

268497 Two cells ofemf \(4 \mathrm{~V}\) and \(8 \mathrm{~V}\) are connected to two resister \(4 \Omega\) and \(6 \Omega\) as shown. If \(8 \mathrm{~V}\) cell is short circuited. Then current through resistance \(4 \Omega\) and \(6 \Omega\)

1 2 A
2 1 A
3 2.5 A
4 3 A
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Current Electricity

268493 The potential difference across the terminals of a battery is\(10 \mathrm{~V}\) when there is a current of \(3 A\) in the battery from the negative to the positive terminal. When the current is \(2 \mathrm{~A}\) in the reverse direction, the potential difference becomes \(15 \mathrm{~V}\). T he internal resistance of the battery is

1 \(1 \Omega\)
2 \(0.4 \Omega\)
3 \(0.6 \Omega\)
4 \(0.8 \Omega\)
Current Electricity

268494 Two cells ofemf \(3 \mathrm{~V}\) and \(5 \mathrm{~V}\) and internal resistance \(r_{1}\) and \(r_{2}\) respectively are in series with an external resistance R. If the p.d. across 1st cell is zero, then \(R\) is

1 \(\frac{5 r_{1}-3 r_{2}}{3}\)
2 \(\frac{2 r_{1}-3 r_{2}}{4}\)
3 \(\frac{3 r_{1}-5 r_{2}}{3}\)
4 \(\frac{4 r_{1}-5 r_{2}}{3}\)
Current Electricity

268495 A battery when connected by a resistance of\(16 \Omega\) gives a terminal voltage of \(12 \mathrm{~V}\). and when connected by a resistance of \(10 \Omega\) gives a terminal voltage of 11V. Then the emf of the battery and its internal resistance

1 \(12.8 \mathrm{~V}\)
2 \(13.7 \mathrm{~V}\)
3 \(10.7 \mathrm{~V}\)
4 \(9 \mathrm{~V}\)
Current Electricity

268496 When a resistor of 11 ohm is connected in series with an electric cell the current flowing in it is\(0.5 \mathrm{~A}\). Instead, when a resistor of \(5 \Omega\) is connected to the same electric cell in series, the current increases by \(0.4 \mathrm{~A}\). The internal resistance of cell is

1 \(1.5 \Omega\)
2 \(2 \Omega\)
3 \(2.5 \Omega\)
4 \(6 \Omega\)
Current Electricity

268497 Two cells ofemf \(4 \mathrm{~V}\) and \(8 \mathrm{~V}\) are connected to two resister \(4 \Omega\) and \(6 \Omega\) as shown. If \(8 \mathrm{~V}\) cell is short circuited. Then current through resistance \(4 \Omega\) and \(6 \Omega\)

1 2 A
2 1 A
3 2.5 A
4 3 A