268352
Two wires made of same material have lengths in the ratio \(1: 2\) and their volumes in the same ratio. The ratio of their resistances is
1 \(4: 1\)
2 \(2: 1\)
3 \(1: 2\)
4 \(1: 4\)
Explanation:
\(R \propto I^{2} \quad \because V\) constant
Current Electricity
268353
Two wires made of same material have their electrical resistances in the ratio \(1: 4\). If their lengths are in the ratio \(1: 2\), the ratio of their masses is
1 \(1: 1\)
2 \(1: 8\)
3 \(8: 1\)
4 \(2: 1\)
Explanation:
\(R \propto \frac{l^{2}}{m}\)
Current Electricity
268354
There are five equal resistors. The minimum resistance possible by their combination is 2 ohm. The maximum possible resistance we can make with them is
1 25 ohm
2 50 o
3 100 ohm
4 150 ohm
Explanation:
\(\frac{R}{5}=2 \quad R_{\max }=5 R \quad R_{\min }=\frac{R}{5}\).
Current Electricity
268355
An electric current is passed through a circuit containing two wires of the same material, connected in parallel. If the lengthsand radii of the wires are in the ratio \(4 / 3\) and \(2 / 3\), then the ratio of the currents passing through the wires will be
268356
A current of \(1 \mathrm{~A}\) is passed through two resistances \(1_{\Omega}\) and \(2_{\Omega}\) connected in parallel. The current flowing through \(2 \Omega\) resistor will be
268352
Two wires made of same material have lengths in the ratio \(1: 2\) and their volumes in the same ratio. The ratio of their resistances is
1 \(4: 1\)
2 \(2: 1\)
3 \(1: 2\)
4 \(1: 4\)
Explanation:
\(R \propto I^{2} \quad \because V\) constant
Current Electricity
268353
Two wires made of same material have their electrical resistances in the ratio \(1: 4\). If their lengths are in the ratio \(1: 2\), the ratio of their masses is
1 \(1: 1\)
2 \(1: 8\)
3 \(8: 1\)
4 \(2: 1\)
Explanation:
\(R \propto \frac{l^{2}}{m}\)
Current Electricity
268354
There are five equal resistors. The minimum resistance possible by their combination is 2 ohm. The maximum possible resistance we can make with them is
1 25 ohm
2 50 o
3 100 ohm
4 150 ohm
Explanation:
\(\frac{R}{5}=2 \quad R_{\max }=5 R \quad R_{\min }=\frac{R}{5}\).
Current Electricity
268355
An electric current is passed through a circuit containing two wires of the same material, connected in parallel. If the lengthsand radii of the wires are in the ratio \(4 / 3\) and \(2 / 3\), then the ratio of the currents passing through the wires will be
268356
A current of \(1 \mathrm{~A}\) is passed through two resistances \(1_{\Omega}\) and \(2_{\Omega}\) connected in parallel. The current flowing through \(2 \Omega\) resistor will be
268352
Two wires made of same material have lengths in the ratio \(1: 2\) and their volumes in the same ratio. The ratio of their resistances is
1 \(4: 1\)
2 \(2: 1\)
3 \(1: 2\)
4 \(1: 4\)
Explanation:
\(R \propto I^{2} \quad \because V\) constant
Current Electricity
268353
Two wires made of same material have their electrical resistances in the ratio \(1: 4\). If their lengths are in the ratio \(1: 2\), the ratio of their masses is
1 \(1: 1\)
2 \(1: 8\)
3 \(8: 1\)
4 \(2: 1\)
Explanation:
\(R \propto \frac{l^{2}}{m}\)
Current Electricity
268354
There are five equal resistors. The minimum resistance possible by their combination is 2 ohm. The maximum possible resistance we can make with them is
1 25 ohm
2 50 o
3 100 ohm
4 150 ohm
Explanation:
\(\frac{R}{5}=2 \quad R_{\max }=5 R \quad R_{\min }=\frac{R}{5}\).
Current Electricity
268355
An electric current is passed through a circuit containing two wires of the same material, connected in parallel. If the lengthsand radii of the wires are in the ratio \(4 / 3\) and \(2 / 3\), then the ratio of the currents passing through the wires will be
268356
A current of \(1 \mathrm{~A}\) is passed through two resistances \(1_{\Omega}\) and \(2_{\Omega}\) connected in parallel. The current flowing through \(2 \Omega\) resistor will be
268352
Two wires made of same material have lengths in the ratio \(1: 2\) and their volumes in the same ratio. The ratio of their resistances is
1 \(4: 1\)
2 \(2: 1\)
3 \(1: 2\)
4 \(1: 4\)
Explanation:
\(R \propto I^{2} \quad \because V\) constant
Current Electricity
268353
Two wires made of same material have their electrical resistances in the ratio \(1: 4\). If their lengths are in the ratio \(1: 2\), the ratio of their masses is
1 \(1: 1\)
2 \(1: 8\)
3 \(8: 1\)
4 \(2: 1\)
Explanation:
\(R \propto \frac{l^{2}}{m}\)
Current Electricity
268354
There are five equal resistors. The minimum resistance possible by their combination is 2 ohm. The maximum possible resistance we can make with them is
1 25 ohm
2 50 o
3 100 ohm
4 150 ohm
Explanation:
\(\frac{R}{5}=2 \quad R_{\max }=5 R \quad R_{\min }=\frac{R}{5}\).
Current Electricity
268355
An electric current is passed through a circuit containing two wires of the same material, connected in parallel. If the lengthsand radii of the wires are in the ratio \(4 / 3\) and \(2 / 3\), then the ratio of the currents passing through the wires will be
268356
A current of \(1 \mathrm{~A}\) is passed through two resistances \(1_{\Omega}\) and \(2_{\Omega}\) connected in parallel. The current flowing through \(2 \Omega\) resistor will be
268352
Two wires made of same material have lengths in the ratio \(1: 2\) and their volumes in the same ratio. The ratio of their resistances is
1 \(4: 1\)
2 \(2: 1\)
3 \(1: 2\)
4 \(1: 4\)
Explanation:
\(R \propto I^{2} \quad \because V\) constant
Current Electricity
268353
Two wires made of same material have their electrical resistances in the ratio \(1: 4\). If their lengths are in the ratio \(1: 2\), the ratio of their masses is
1 \(1: 1\)
2 \(1: 8\)
3 \(8: 1\)
4 \(2: 1\)
Explanation:
\(R \propto \frac{l^{2}}{m}\)
Current Electricity
268354
There are five equal resistors. The minimum resistance possible by their combination is 2 ohm. The maximum possible resistance we can make with them is
1 25 ohm
2 50 o
3 100 ohm
4 150 ohm
Explanation:
\(\frac{R}{5}=2 \quad R_{\max }=5 R \quad R_{\min }=\frac{R}{5}\).
Current Electricity
268355
An electric current is passed through a circuit containing two wires of the same material, connected in parallel. If the lengthsand radii of the wires are in the ratio \(4 / 3\) and \(2 / 3\), then the ratio of the currents passing through the wires will be
268356
A current of \(1 \mathrm{~A}\) is passed through two resistances \(1_{\Omega}\) and \(2_{\Omega}\) connected in parallel. The current flowing through \(2 \Omega\) resistor will be
