CAPACITORSIN SERIES AND IN PARALLEL
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Electrostatic Potentials and Capacitance

268115 An infinite number of identical capacitorseach of capacitance \(1 \mathrm{mF}\) are connected as shown in the figure. Then the equivalent capacitance between \(A\) and \(B\) is

1 \(1 \mathrm{mF}\)
2 \(2 \mathrm{mF}\)
3 \(1 / 2 \mathrm{mF}\)
4 \(0.75 \mathrm{mF}\)
Electrostatic Potentials and Capacitance

268101 The resultant capacity between the points \(P\) and \(Q\) of the given figure is

1 \(4 \mu F\)
2 \(\frac{16}{3} \mu F\)
3 \(1.6 \mu \mathrm{F}\)
4 \(1 \mu F\)
Electrostatic Potentials and Capacitance

268125 'A' and ' \(B\) ' are two condensers of capacities \(2 \mu \mathbf{F}\) and \(4 \mu \mathbf{F}\). They arecharged to potential differences of \(12 \mathrm{~V}\) and \(6 \mathrm{~V}\) respectively. If they are now connected (+ve to +ve), the charge that flows through the connecting wire is

1 \(24 \mu \mathrm{C}\) fromA to \(B\)
2 \(8 \mu \mathrm{C}\) fromA to \(\mathrm{B}\)
3 \(8 \mu \mathrm{C}\) fromB to \(\mathrm{A}\)
4 \(24 \mu \mathrm{C}\) fromB to \(A\)
Electrostatic Potentials and Capacitance

268126 Force of attraction between the plates of a parallel plate capacitor is

1 \(\frac{q^{2}}{2 \varepsilon_{0} A}\)
2 \(\frac{q^{2}}{\varepsilon_{0} A}\)
3 \(\frac{q}{2 \varepsilon_{0} A}\)
4 \(\frac{q^{2}}{2 \varepsilon_{0} A^{2}}\)
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Electrostatic Potentials and Capacitance

268115 An infinite number of identical capacitorseach of capacitance \(1 \mathrm{mF}\) are connected as shown in the figure. Then the equivalent capacitance between \(A\) and \(B\) is

1 \(1 \mathrm{mF}\)
2 \(2 \mathrm{mF}\)
3 \(1 / 2 \mathrm{mF}\)
4 \(0.75 \mathrm{mF}\)
Electrostatic Potentials and Capacitance

268101 The resultant capacity between the points \(P\) and \(Q\) of the given figure is

1 \(4 \mu F\)
2 \(\frac{16}{3} \mu F\)
3 \(1.6 \mu \mathrm{F}\)
4 \(1 \mu F\)
Electrostatic Potentials and Capacitance

268125 'A' and ' \(B\) ' are two condensers of capacities \(2 \mu \mathbf{F}\) and \(4 \mu \mathbf{F}\). They arecharged to potential differences of \(12 \mathrm{~V}\) and \(6 \mathrm{~V}\) respectively. If they are now connected (+ve to +ve), the charge that flows through the connecting wire is

1 \(24 \mu \mathrm{C}\) fromA to \(B\)
2 \(8 \mu \mathrm{C}\) fromA to \(\mathrm{B}\)
3 \(8 \mu \mathrm{C}\) fromB to \(\mathrm{A}\)
4 \(24 \mu \mathrm{C}\) fromB to \(A\)
Electrostatic Potentials and Capacitance

268126 Force of attraction between the plates of a parallel plate capacitor is

1 \(\frac{q^{2}}{2 \varepsilon_{0} A}\)
2 \(\frac{q^{2}}{\varepsilon_{0} A}\)
3 \(\frac{q}{2 \varepsilon_{0} A}\)
4 \(\frac{q^{2}}{2 \varepsilon_{0} A^{2}}\)
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Electrostatic Potentials and Capacitance

268115 An infinite number of identical capacitorseach of capacitance \(1 \mathrm{mF}\) are connected as shown in the figure. Then the equivalent capacitance between \(A\) and \(B\) is

1 \(1 \mathrm{mF}\)
2 \(2 \mathrm{mF}\)
3 \(1 / 2 \mathrm{mF}\)
4 \(0.75 \mathrm{mF}\)
Electrostatic Potentials and Capacitance

268101 The resultant capacity between the points \(P\) and \(Q\) of the given figure is

1 \(4 \mu F\)
2 \(\frac{16}{3} \mu F\)
3 \(1.6 \mu \mathrm{F}\)
4 \(1 \mu F\)
Electrostatic Potentials and Capacitance

268125 'A' and ' \(B\) ' are two condensers of capacities \(2 \mu \mathbf{F}\) and \(4 \mu \mathbf{F}\). They arecharged to potential differences of \(12 \mathrm{~V}\) and \(6 \mathrm{~V}\) respectively. If they are now connected (+ve to +ve), the charge that flows through the connecting wire is

1 \(24 \mu \mathrm{C}\) fromA to \(B\)
2 \(8 \mu \mathrm{C}\) fromA to \(\mathrm{B}\)
3 \(8 \mu \mathrm{C}\) fromB to \(\mathrm{A}\)
4 \(24 \mu \mathrm{C}\) fromB to \(A\)
Electrostatic Potentials and Capacitance

268126 Force of attraction between the plates of a parallel plate capacitor is

1 \(\frac{q^{2}}{2 \varepsilon_{0} A}\)
2 \(\frac{q^{2}}{\varepsilon_{0} A}\)
3 \(\frac{q}{2 \varepsilon_{0} A}\)
4 \(\frac{q^{2}}{2 \varepsilon_{0} A^{2}}\)
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Electrostatic Potentials and Capacitance

268115 An infinite number of identical capacitorseach of capacitance \(1 \mathrm{mF}\) are connected as shown in the figure. Then the equivalent capacitance between \(A\) and \(B\) is

1 \(1 \mathrm{mF}\)
2 \(2 \mathrm{mF}\)
3 \(1 / 2 \mathrm{mF}\)
4 \(0.75 \mathrm{mF}\)
Electrostatic Potentials and Capacitance

268101 The resultant capacity between the points \(P\) and \(Q\) of the given figure is

1 \(4 \mu F\)
2 \(\frac{16}{3} \mu F\)
3 \(1.6 \mu \mathrm{F}\)
4 \(1 \mu F\)
Electrostatic Potentials and Capacitance

268125 'A' and ' \(B\) ' are two condensers of capacities \(2 \mu \mathbf{F}\) and \(4 \mu \mathbf{F}\). They arecharged to potential differences of \(12 \mathrm{~V}\) and \(6 \mathrm{~V}\) respectively. If they are now connected (+ve to +ve), the charge that flows through the connecting wire is

1 \(24 \mu \mathrm{C}\) fromA to \(B\)
2 \(8 \mu \mathrm{C}\) fromA to \(\mathrm{B}\)
3 \(8 \mu \mathrm{C}\) fromB to \(\mathrm{A}\)
4 \(24 \mu \mathrm{C}\) fromB to \(A\)
Electrostatic Potentials and Capacitance

268126 Force of attraction between the plates of a parallel plate capacitor is

1 \(\frac{q^{2}}{2 \varepsilon_{0} A}\)
2 \(\frac{q^{2}}{\varepsilon_{0} A}\)
3 \(\frac{q}{2 \varepsilon_{0} A}\)
4 \(\frac{q^{2}}{2 \varepsilon_{0} A^{2}}\)