Electric Capacity:
Electrostatic Potentials and Capacitance

268006 A parallel plate capacitor filled with amaterail of dielectric constant \(K\) is charged to a certain voltage and isisolated. Thedielectric material is removed. Then
a)T he capacitance decreases by a factor \(K\)
b) The electric field reduces by a factor \(K\)
c) The voltage across the capacitor increases by a factor K
d) The charge strored in the capacitor increases by a factor \(K\)

1 a and baretrue
2 a and c are true
3 b and c are true
4 b and d are true
Electrostatic Potentials and Capacitance

268007 Force acting upon a charged particle kept between the plates of a charged condenser is F. If one of the plates of the condenseris removed, force acting on the same particle will become

1 zero
2 \(F / 2\)
3 \(F\)
4 \(2 \mathrm{~F}\)
Electrostatic Potentials and Capacitance

268008 A condenser is charged and then batteryis removed. A dielectric plate is put between the plates of condenser, then correct statement is

1 \(Q\) constant \(V\) and \(U\) decrease
2 \(Q\) constant \(V\) increases \(U\) decreases
3 \(Q\) increases \(V\) decreases \(U\) increases
4 \(Q, V\) and \(U\) increase
Electrostatic Potentials and Capacitance

268009 If an uncharged capacitoris charged by connecting it to a battery, then the amount of energy lost as heat is

1 \(1 / 2 Q V\)
2 QV
3 \(1 / 2 \mathrm{QV}{ }^{2}\)
4 \(Q V^{2}\)
Electrostatic Potentials and Capacitance

268006 A parallel plate capacitor filled with amaterail of dielectric constant \(K\) is charged to a certain voltage and isisolated. Thedielectric material is removed. Then
a)T he capacitance decreases by a factor \(K\)
b) The electric field reduces by a factor \(K\)
c) The voltage across the capacitor increases by a factor K
d) The charge strored in the capacitor increases by a factor \(K\)

1 a and baretrue
2 a and c are true
3 b and c are true
4 b and d are true
Electrostatic Potentials and Capacitance

268007 Force acting upon a charged particle kept between the plates of a charged condenser is F. If one of the plates of the condenseris removed, force acting on the same particle will become

1 zero
2 \(F / 2\)
3 \(F\)
4 \(2 \mathrm{~F}\)
Electrostatic Potentials and Capacitance

268008 A condenser is charged and then batteryis removed. A dielectric plate is put between the plates of condenser, then correct statement is

1 \(Q\) constant \(V\) and \(U\) decrease
2 \(Q\) constant \(V\) increases \(U\) decreases
3 \(Q\) increases \(V\) decreases \(U\) increases
4 \(Q, V\) and \(U\) increase
Electrostatic Potentials and Capacitance

268009 If an uncharged capacitoris charged by connecting it to a battery, then the amount of energy lost as heat is

1 \(1 / 2 Q V\)
2 QV
3 \(1 / 2 \mathrm{QV}{ }^{2}\)
4 \(Q V^{2}\)
Electrostatic Potentials and Capacitance

268006 A parallel plate capacitor filled with amaterail of dielectric constant \(K\) is charged to a certain voltage and isisolated. Thedielectric material is removed. Then
a)T he capacitance decreases by a factor \(K\)
b) The electric field reduces by a factor \(K\)
c) The voltage across the capacitor increases by a factor K
d) The charge strored in the capacitor increases by a factor \(K\)

1 a and baretrue
2 a and c are true
3 b and c are true
4 b and d are true
Electrostatic Potentials and Capacitance

268007 Force acting upon a charged particle kept between the plates of a charged condenser is F. If one of the plates of the condenseris removed, force acting on the same particle will become

1 zero
2 \(F / 2\)
3 \(F\)
4 \(2 \mathrm{~F}\)
Electrostatic Potentials and Capacitance

268008 A condenser is charged and then batteryis removed. A dielectric plate is put between the plates of condenser, then correct statement is

1 \(Q\) constant \(V\) and \(U\) decrease
2 \(Q\) constant \(V\) increases \(U\) decreases
3 \(Q\) increases \(V\) decreases \(U\) increases
4 \(Q, V\) and \(U\) increase
Electrostatic Potentials and Capacitance

268009 If an uncharged capacitoris charged by connecting it to a battery, then the amount of energy lost as heat is

1 \(1 / 2 Q V\)
2 QV
3 \(1 / 2 \mathrm{QV}{ }^{2}\)
4 \(Q V^{2}\)
Electrostatic Potentials and Capacitance

268006 A parallel plate capacitor filled with amaterail of dielectric constant \(K\) is charged to a certain voltage and isisolated. Thedielectric material is removed. Then
a)T he capacitance decreases by a factor \(K\)
b) The electric field reduces by a factor \(K\)
c) The voltage across the capacitor increases by a factor K
d) The charge strored in the capacitor increases by a factor \(K\)

1 a and baretrue
2 a and c are true
3 b and c are true
4 b and d are true
Electrostatic Potentials and Capacitance

268007 Force acting upon a charged particle kept between the plates of a charged condenser is F. If one of the plates of the condenseris removed, force acting on the same particle will become

1 zero
2 \(F / 2\)
3 \(F\)
4 \(2 \mathrm{~F}\)
Electrostatic Potentials and Capacitance

268008 A condenser is charged and then batteryis removed. A dielectric plate is put between the plates of condenser, then correct statement is

1 \(Q\) constant \(V\) and \(U\) decrease
2 \(Q\) constant \(V\) increases \(U\) decreases
3 \(Q\) increases \(V\) decreases \(U\) increases
4 \(Q, V\) and \(U\) increase
Electrostatic Potentials and Capacitance

268009 If an uncharged capacitoris charged by connecting it to a battery, then the amount of energy lost as heat is

1 \(1 / 2 Q V\)
2 QV
3 \(1 / 2 \mathrm{QV}{ }^{2}\)
4 \(Q V^{2}\)