266517 A charge \(q\) is at rest in a magnetic field of flux density \(B\). Force acting on it is:

266518 If a body is moving with velocity \((10 \hat{i}+20 \hat{j}\} \mathrm{m} / \mathrm{s}, \&\) having acceleration of \(2 \hat{i}{\mathrm{~m} / \mathrm{sec}^2 \text {, then find the }}^{-2}\) time after which \(y\)-component of velocity become zero.

266519 In the given circuit, the current through the resistor \(3 k \Omega\) is:

266520 A force acts on a 2 kg particle in such a way that the position of the particle as s function of time is givne by \(x=t^3-2 t+10\), where \(x\) is in metres and \(t\) is in seconds. The work done during the first 3 seconds is:

266517 A charge \(q\) is at rest in a magnetic field of flux density \(B\). Force acting on it is:

266518 If a body is moving with velocity \((10 \hat{i}+20 \hat{j}\} \mathrm{m} / \mathrm{s}, \&\) having acceleration of \(2 \hat{i}{\mathrm{~m} / \mathrm{sec}^2 \text {, then find the }}^{-2}\) time after which \(y\)-component of velocity become zero.

266519 In the given circuit, the current through the resistor \(3 k \Omega\) is:

266520 A force acts on a 2 kg particle in such a way that the position of the particle as s function of time is givne by \(x=t^3-2 t+10\), where \(x\) is in metres and \(t\) is in seconds. The work done during the first 3 seconds is:

266517 A charge \(q\) is at rest in a magnetic field of flux density \(B\). Force acting on it is:

266518 If a body is moving with velocity \((10 \hat{i}+20 \hat{j}\} \mathrm{m} / \mathrm{s}, \&\) having acceleration of \(2 \hat{i}{\mathrm{~m} / \mathrm{sec}^2 \text {, then find the }}^{-2}\) time after which \(y\)-component of velocity become zero.

266519 In the given circuit, the current through the resistor \(3 k \Omega\) is:

266520 A force acts on a 2 kg particle in such a way that the position of the particle as s function of time is givne by \(x=t^3-2 t+10\), where \(x\) is in metres and \(t\) is in seconds. The work done during the first 3 seconds is:

266517 A charge \(q\) is at rest in a magnetic field of flux density \(B\). Force acting on it is:

266518 If a body is moving with velocity \((10 \hat{i}+20 \hat{j}\} \mathrm{m} / \mathrm{s}, \&\) having acceleration of \(2 \hat{i}{\mathrm{~m} / \mathrm{sec}^2 \text {, then find the }}^{-2}\) time after which \(y\)-component of velocity become zero.

266519 In the given circuit, the current through the resistor \(3 k \Omega\) is:

266520 A force acts on a 2 kg particle in such a way that the position of the particle as s function of time is givne by \(x=t^3-2 t+10\), where \(x\) is in metres and \(t\) is in seconds. The work done during the first 3 seconds is: