266417
The charge stored on the capacitor shown in the circuit diagram at steady state is :
1 zero
2 \(250 \mu \mathrm{C}\)
3 \(750 \mu \mathrm{C}\)
4 \(1200 \mu \mathrm{C}\)
Explanation:
a
**NCERT-XII-I-85**
TEST SERIES (PHYSICS FST)
266448
An organ pipe \(P_1\) closed at one end vibrating in its first overtone and another pipe \(P_2\) open at both ends vibrating in its third overtone are in resonance with a given tunning fork. The ratio of the length of \(P_1\) to that of \(P_2\) is
266449
Find the angular frequency of particle from given equation : Where \(y=\) displacement and \(t=\) time \(\frac{4 d^2 y}{d t^2}+9 y=0\)
1 \(9 / 4\)
2 419
3 \(3 / 2\)
4 213
Explanation:
c \[ \begin{aligned} & m \frac{d^2 y}{d t^2}+k y=0 \\ & \omega^2=\frac{k}{m} \\ & \omega=\sqrt{\frac{k}{m}}=\sqrt{\frac{9}{4}} \\ & \omega=\frac{3}{2} \end{aligned} \]
**NCERT-XI-I-267**
TEST SERIES (PHYSICS FST)
266408
A soap film of surface tension \(3 \times 10^{-2} \mathrm{Nm}^{-1}\) formed in rectangular frame, can support a straw. The length of the film is 10 cm . Mass fo the straw the film can support is
1 0.06 gm
2 0.6 gm
3 6 gm
4 60 gm
Explanation:
b The weight of straw will be balanced by the force of surface tension \(\therefore \mathrm{mg}=2 \mathrm{TI} \Rightarrow \mathrm{m}=\frac{2 \mathrm{~T}}{\mathrm{~g}}\) \[ =\frac{2 \times 3 \times 10^{-2} \times 10 \times 10^{-2}}{9.8} \mathrm{~kg}=0.6 \mathrm{ggm} \] 1.\(\mathrm{PCl}_5\) - (iv) Trigonal bi pyramidal, (a) \(120^{\circ}, 90^{\circ}\)
**NCERT-XI-II-182**
TEST SERIES (PHYSICS FST)
266409
In the hydrogen atom, the electron is making \(6.6 \times 10^{15}\) r.p.s. If the radius of the orbit is \(0.53 \times 10^{-10}\) metre then magnetic field produced at the centre of the orbit is
266417
The charge stored on the capacitor shown in the circuit diagram at steady state is :
1 zero
2 \(250 \mu \mathrm{C}\)
3 \(750 \mu \mathrm{C}\)
4 \(1200 \mu \mathrm{C}\)
Explanation:
a
**NCERT-XII-I-85**
TEST SERIES (PHYSICS FST)
266448
An organ pipe \(P_1\) closed at one end vibrating in its first overtone and another pipe \(P_2\) open at both ends vibrating in its third overtone are in resonance with a given tunning fork. The ratio of the length of \(P_1\) to that of \(P_2\) is
266449
Find the angular frequency of particle from given equation : Where \(y=\) displacement and \(t=\) time \(\frac{4 d^2 y}{d t^2}+9 y=0\)
1 \(9 / 4\)
2 419
3 \(3 / 2\)
4 213
Explanation:
c \[ \begin{aligned} & m \frac{d^2 y}{d t^2}+k y=0 \\ & \omega^2=\frac{k}{m} \\ & \omega=\sqrt{\frac{k}{m}}=\sqrt{\frac{9}{4}} \\ & \omega=\frac{3}{2} \end{aligned} \]
**NCERT-XI-I-267**
TEST SERIES (PHYSICS FST)
266408
A soap film of surface tension \(3 \times 10^{-2} \mathrm{Nm}^{-1}\) formed in rectangular frame, can support a straw. The length of the film is 10 cm . Mass fo the straw the film can support is
1 0.06 gm
2 0.6 gm
3 6 gm
4 60 gm
Explanation:
b The weight of straw will be balanced by the force of surface tension \(\therefore \mathrm{mg}=2 \mathrm{TI} \Rightarrow \mathrm{m}=\frac{2 \mathrm{~T}}{\mathrm{~g}}\) \[ =\frac{2 \times 3 \times 10^{-2} \times 10 \times 10^{-2}}{9.8} \mathrm{~kg}=0.6 \mathrm{ggm} \] 1.\(\mathrm{PCl}_5\) - (iv) Trigonal bi pyramidal, (a) \(120^{\circ}, 90^{\circ}\)
**NCERT-XI-II-182**
TEST SERIES (PHYSICS FST)
266409
In the hydrogen atom, the electron is making \(6.6 \times 10^{15}\) r.p.s. If the radius of the orbit is \(0.53 \times 10^{-10}\) metre then magnetic field produced at the centre of the orbit is
266417
The charge stored on the capacitor shown in the circuit diagram at steady state is :
1 zero
2 \(250 \mu \mathrm{C}\)
3 \(750 \mu \mathrm{C}\)
4 \(1200 \mu \mathrm{C}\)
Explanation:
a
**NCERT-XII-I-85**
TEST SERIES (PHYSICS FST)
266448
An organ pipe \(P_1\) closed at one end vibrating in its first overtone and another pipe \(P_2\) open at both ends vibrating in its third overtone are in resonance with a given tunning fork. The ratio of the length of \(P_1\) to that of \(P_2\) is
266449
Find the angular frequency of particle from given equation : Where \(y=\) displacement and \(t=\) time \(\frac{4 d^2 y}{d t^2}+9 y=0\)
1 \(9 / 4\)
2 419
3 \(3 / 2\)
4 213
Explanation:
c \[ \begin{aligned} & m \frac{d^2 y}{d t^2}+k y=0 \\ & \omega^2=\frac{k}{m} \\ & \omega=\sqrt{\frac{k}{m}}=\sqrt{\frac{9}{4}} \\ & \omega=\frac{3}{2} \end{aligned} \]
**NCERT-XI-I-267**
TEST SERIES (PHYSICS FST)
266408
A soap film of surface tension \(3 \times 10^{-2} \mathrm{Nm}^{-1}\) formed in rectangular frame, can support a straw. The length of the film is 10 cm . Mass fo the straw the film can support is
1 0.06 gm
2 0.6 gm
3 6 gm
4 60 gm
Explanation:
b The weight of straw will be balanced by the force of surface tension \(\therefore \mathrm{mg}=2 \mathrm{TI} \Rightarrow \mathrm{m}=\frac{2 \mathrm{~T}}{\mathrm{~g}}\) \[ =\frac{2 \times 3 \times 10^{-2} \times 10 \times 10^{-2}}{9.8} \mathrm{~kg}=0.6 \mathrm{ggm} \] 1.\(\mathrm{PCl}_5\) - (iv) Trigonal bi pyramidal, (a) \(120^{\circ}, 90^{\circ}\)
**NCERT-XI-II-182**
TEST SERIES (PHYSICS FST)
266409
In the hydrogen atom, the electron is making \(6.6 \times 10^{15}\) r.p.s. If the radius of the orbit is \(0.53 \times 10^{-10}\) metre then magnetic field produced at the centre of the orbit is
NEET Test Series from KOTA - 10 Papers In MS WORD
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TEST SERIES (PHYSICS FST)
266417
The charge stored on the capacitor shown in the circuit diagram at steady state is :
1 zero
2 \(250 \mu \mathrm{C}\)
3 \(750 \mu \mathrm{C}\)
4 \(1200 \mu \mathrm{C}\)
Explanation:
a
**NCERT-XII-I-85**
TEST SERIES (PHYSICS FST)
266448
An organ pipe \(P_1\) closed at one end vibrating in its first overtone and another pipe \(P_2\) open at both ends vibrating in its third overtone are in resonance with a given tunning fork. The ratio of the length of \(P_1\) to that of \(P_2\) is
266449
Find the angular frequency of particle from given equation : Where \(y=\) displacement and \(t=\) time \(\frac{4 d^2 y}{d t^2}+9 y=0\)
1 \(9 / 4\)
2 419
3 \(3 / 2\)
4 213
Explanation:
c \[ \begin{aligned} & m \frac{d^2 y}{d t^2}+k y=0 \\ & \omega^2=\frac{k}{m} \\ & \omega=\sqrt{\frac{k}{m}}=\sqrt{\frac{9}{4}} \\ & \omega=\frac{3}{2} \end{aligned} \]
**NCERT-XI-I-267**
TEST SERIES (PHYSICS FST)
266408
A soap film of surface tension \(3 \times 10^{-2} \mathrm{Nm}^{-1}\) formed in rectangular frame, can support a straw. The length of the film is 10 cm . Mass fo the straw the film can support is
1 0.06 gm
2 0.6 gm
3 6 gm
4 60 gm
Explanation:
b The weight of straw will be balanced by the force of surface tension \(\therefore \mathrm{mg}=2 \mathrm{TI} \Rightarrow \mathrm{m}=\frac{2 \mathrm{~T}}{\mathrm{~g}}\) \[ =\frac{2 \times 3 \times 10^{-2} \times 10 \times 10^{-2}}{9.8} \mathrm{~kg}=0.6 \mathrm{ggm} \] 1.\(\mathrm{PCl}_5\) - (iv) Trigonal bi pyramidal, (a) \(120^{\circ}, 90^{\circ}\)
**NCERT-XI-II-182**
TEST SERIES (PHYSICS FST)
266409
In the hydrogen atom, the electron is making \(6.6 \times 10^{15}\) r.p.s. If the radius of the orbit is \(0.53 \times 10^{-10}\) metre then magnetic field produced at the centre of the orbit is
266417
The charge stored on the capacitor shown in the circuit diagram at steady state is :
1 zero
2 \(250 \mu \mathrm{C}\)
3 \(750 \mu \mathrm{C}\)
4 \(1200 \mu \mathrm{C}\)
Explanation:
a
**NCERT-XII-I-85**
TEST SERIES (PHYSICS FST)
266448
An organ pipe \(P_1\) closed at one end vibrating in its first overtone and another pipe \(P_2\) open at both ends vibrating in its third overtone are in resonance with a given tunning fork. The ratio of the length of \(P_1\) to that of \(P_2\) is
266449
Find the angular frequency of particle from given equation : Where \(y=\) displacement and \(t=\) time \(\frac{4 d^2 y}{d t^2}+9 y=0\)
1 \(9 / 4\)
2 419
3 \(3 / 2\)
4 213
Explanation:
c \[ \begin{aligned} & m \frac{d^2 y}{d t^2}+k y=0 \\ & \omega^2=\frac{k}{m} \\ & \omega=\sqrt{\frac{k}{m}}=\sqrt{\frac{9}{4}} \\ & \omega=\frac{3}{2} \end{aligned} \]
**NCERT-XI-I-267**
TEST SERIES (PHYSICS FST)
266408
A soap film of surface tension \(3 \times 10^{-2} \mathrm{Nm}^{-1}\) formed in rectangular frame, can support a straw. The length of the film is 10 cm . Mass fo the straw the film can support is
1 0.06 gm
2 0.6 gm
3 6 gm
4 60 gm
Explanation:
b The weight of straw will be balanced by the force of surface tension \(\therefore \mathrm{mg}=2 \mathrm{TI} \Rightarrow \mathrm{m}=\frac{2 \mathrm{~T}}{\mathrm{~g}}\) \[ =\frac{2 \times 3 \times 10^{-2} \times 10 \times 10^{-2}}{9.8} \mathrm{~kg}=0.6 \mathrm{ggm} \] 1.\(\mathrm{PCl}_5\) - (iv) Trigonal bi pyramidal, (a) \(120^{\circ}, 90^{\circ}\)
**NCERT-XI-II-182**
TEST SERIES (PHYSICS FST)
266409
In the hydrogen atom, the electron is making \(6.6 \times 10^{15}\) r.p.s. If the radius of the orbit is \(0.53 \times 10^{-10}\) metre then magnetic field produced at the centre of the orbit is
