An equimolar mixture of the enantiomers (dextro or laevo froms) is called racemic mixture. It is represented as dl-form or \pm form and is optically inactive due to external compensation separation of racemic mixture into d- and l- forms is called resolution. Example :
UPTU/ UPSEE-2009
GENERAL ORGANIC CHEMISTRY
232244
$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}$ and $\mathrm{CH}_{3} \mathrm{OCH}_{3}$ are the, examples of
1 chain isomerism
2 functional isomerism
3 position isomerism
4 metamerism
Explanation:
$\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{OH}$ and $\mathrm{CH}_{3}-\mathrm{O}-\mathrm{CH}_{3}$ are the example of functional group isomer in which $-\mathrm{OH}$ group attached in ethanol while -o- group is attached in ether.
UPTU/ UPSEE-2008
GENERAL ORGANIC CHEMISTRY
232249
Which one of the following will show optical isomerism
1
2
3
4
Explanation:
Compound to optical isomer is $\mathrm{m}$ it must have at least one Asymmetric center. Asymmetric center, a center which an atom (carbon) is $\mathrm{SP}^{3}$ hybridised and attached to 4 different substituent. Compound $\mathrm{C} \& \mathrm{~d}$ does not show optical isomer due to obsence of chiral center or Asymmetric center
WB JEET-2011
GENERAL ORGANIC CHEMISTRY
232250
The most contributing tautomeric enol from of $\mathrm{MeCOCH}_{2} \mathrm{CO}_{2} \mathrm{Et}$ is
Tautomerism-Tautomer are isomer of a compound which differ only in the position of electron and proton. The carbon skelton of a compound does not change.
An equimolar mixture of the enantiomers (dextro or laevo froms) is called racemic mixture. It is represented as dl-form or \pm form and is optically inactive due to external compensation separation of racemic mixture into d- and l- forms is called resolution. Example :
UPTU/ UPSEE-2009
GENERAL ORGANIC CHEMISTRY
232244
$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}$ and $\mathrm{CH}_{3} \mathrm{OCH}_{3}$ are the, examples of
1 chain isomerism
2 functional isomerism
3 position isomerism
4 metamerism
Explanation:
$\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{OH}$ and $\mathrm{CH}_{3}-\mathrm{O}-\mathrm{CH}_{3}$ are the example of functional group isomer in which $-\mathrm{OH}$ group attached in ethanol while -o- group is attached in ether.
UPTU/ UPSEE-2008
GENERAL ORGANIC CHEMISTRY
232249
Which one of the following will show optical isomerism
1
2
3
4
Explanation:
Compound to optical isomer is $\mathrm{m}$ it must have at least one Asymmetric center. Asymmetric center, a center which an atom (carbon) is $\mathrm{SP}^{3}$ hybridised and attached to 4 different substituent. Compound $\mathrm{C} \& \mathrm{~d}$ does not show optical isomer due to obsence of chiral center or Asymmetric center
WB JEET-2011
GENERAL ORGANIC CHEMISTRY
232250
The most contributing tautomeric enol from of $\mathrm{MeCOCH}_{2} \mathrm{CO}_{2} \mathrm{Et}$ is
Tautomerism-Tautomer are isomer of a compound which differ only in the position of electron and proton. The carbon skelton of a compound does not change.
An equimolar mixture of the enantiomers (dextro or laevo froms) is called racemic mixture. It is represented as dl-form or \pm form and is optically inactive due to external compensation separation of racemic mixture into d- and l- forms is called resolution. Example :
UPTU/ UPSEE-2009
GENERAL ORGANIC CHEMISTRY
232244
$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}$ and $\mathrm{CH}_{3} \mathrm{OCH}_{3}$ are the, examples of
1 chain isomerism
2 functional isomerism
3 position isomerism
4 metamerism
Explanation:
$\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{OH}$ and $\mathrm{CH}_{3}-\mathrm{O}-\mathrm{CH}_{3}$ are the example of functional group isomer in which $-\mathrm{OH}$ group attached in ethanol while -o- group is attached in ether.
UPTU/ UPSEE-2008
GENERAL ORGANIC CHEMISTRY
232249
Which one of the following will show optical isomerism
1
2
3
4
Explanation:
Compound to optical isomer is $\mathrm{m}$ it must have at least one Asymmetric center. Asymmetric center, a center which an atom (carbon) is $\mathrm{SP}^{3}$ hybridised and attached to 4 different substituent. Compound $\mathrm{C} \& \mathrm{~d}$ does not show optical isomer due to obsence of chiral center or Asymmetric center
WB JEET-2011
GENERAL ORGANIC CHEMISTRY
232250
The most contributing tautomeric enol from of $\mathrm{MeCOCH}_{2} \mathrm{CO}_{2} \mathrm{Et}$ is
Tautomerism-Tautomer are isomer of a compound which differ only in the position of electron and proton. The carbon skelton of a compound does not change.
An equimolar mixture of the enantiomers (dextro or laevo froms) is called racemic mixture. It is represented as dl-form or \pm form and is optically inactive due to external compensation separation of racemic mixture into d- and l- forms is called resolution. Example :
UPTU/ UPSEE-2009
GENERAL ORGANIC CHEMISTRY
232244
$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}$ and $\mathrm{CH}_{3} \mathrm{OCH}_{3}$ are the, examples of
1 chain isomerism
2 functional isomerism
3 position isomerism
4 metamerism
Explanation:
$\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{OH}$ and $\mathrm{CH}_{3}-\mathrm{O}-\mathrm{CH}_{3}$ are the example of functional group isomer in which $-\mathrm{OH}$ group attached in ethanol while -o- group is attached in ether.
UPTU/ UPSEE-2008
GENERAL ORGANIC CHEMISTRY
232249
Which one of the following will show optical isomerism
1
2
3
4
Explanation:
Compound to optical isomer is $\mathrm{m}$ it must have at least one Asymmetric center. Asymmetric center, a center which an atom (carbon) is $\mathrm{SP}^{3}$ hybridised and attached to 4 different substituent. Compound $\mathrm{C} \& \mathrm{~d}$ does not show optical isomer due to obsence of chiral center or Asymmetric center
WB JEET-2011
GENERAL ORGANIC CHEMISTRY
232250
The most contributing tautomeric enol from of $\mathrm{MeCOCH}_{2} \mathrm{CO}_{2} \mathrm{Et}$ is
Tautomerism-Tautomer are isomer of a compound which differ only in the position of electron and proton. The carbon skelton of a compound does not change.
