12. THERMODYNAMICS (HM)
Explanation:
Efficiency of carnot engine
\(\% \eta=\left(1-\frac{T_{\text {sink }}}{T_{\text {source }}}\right) \times 100\)
\(T_{\text {source }}=327^{\circ}\,C =600\,K\)
\(50=\left(1-\frac{T_{\text {sink }}}{600}\right) \times 100\)
\(\frac{1}{2}=1-\frac{T_{\text {sink }}}{600}\)
\(T _{\text {Sink }}=300\,K\)
So temp. of sink is \({ }^{\circ} C =300-2763=27^{\circ}\,C\)