189213
Which of the following halides is least stable and has doubtful existence
1 \(C{I_4}\)
2 \(Ge{I_4}\)
3 \(Sn{I_4}\)
4 \(Pb{I_4}\)
Explanation:
(d) \(Pb{I_4}\) is least stable because of two reasons \((1)\) Size of iodine is biggest. \((2)\) \( + 2\) oxidation state of \(Pb\) is more stable than \( + 4\) state because of inert pair effect.
07. The p-BLOCK ELEMENTS (XII)
189214
Chlorine cannot displace
1 Fluorine from \(NaF\)
2 Iodine from \(NaI\)
3 Bromine from \(NaBr\)
4 None of these
Explanation:
(a) \(C{l_2} + NaF\, \to \,{\rm{No\, reaction}}\) Since \(C{l_2}\) is less electronegative then \({F_2}\). Therefore unable to displace fluorine from its salt.
07. The p-BLOCK ELEMENTS (XII)
189218
At room temperature \({H_2}O\) is a liquid while \({H_2}S\) is a gas. The reason is
1 Electronegativity of \(O\) is greater than \(S\)
2 Difference in the bond angles of both the molecules
3 Association takes place in \({H_2}O\) due to \(H\) - bonding while no \(H\) - bonding in \({H_2}S\)
4 \(O\) and \(S\) belong to different periods
Explanation:
(c) \({H_2}O\)contain hydrogen bond while no hydrogen bonding is present in \({H_2}S\).
189213
Which of the following halides is least stable and has doubtful existence
1 \(C{I_4}\)
2 \(Ge{I_4}\)
3 \(Sn{I_4}\)
4 \(Pb{I_4}\)
Explanation:
(d) \(Pb{I_4}\) is least stable because of two reasons \((1)\) Size of iodine is biggest. \((2)\) \( + 2\) oxidation state of \(Pb\) is more stable than \( + 4\) state because of inert pair effect.
07. The p-BLOCK ELEMENTS (XII)
189214
Chlorine cannot displace
1 Fluorine from \(NaF\)
2 Iodine from \(NaI\)
3 Bromine from \(NaBr\)
4 None of these
Explanation:
(a) \(C{l_2} + NaF\, \to \,{\rm{No\, reaction}}\) Since \(C{l_2}\) is less electronegative then \({F_2}\). Therefore unable to displace fluorine from its salt.
07. The p-BLOCK ELEMENTS (XII)
189218
At room temperature \({H_2}O\) is a liquid while \({H_2}S\) is a gas. The reason is
1 Electronegativity of \(O\) is greater than \(S\)
2 Difference in the bond angles of both the molecules
3 Association takes place in \({H_2}O\) due to \(H\) - bonding while no \(H\) - bonding in \({H_2}S\)
4 \(O\) and \(S\) belong to different periods
Explanation:
(c) \({H_2}O\)contain hydrogen bond while no hydrogen bonding is present in \({H_2}S\).
189213
Which of the following halides is least stable and has doubtful existence
1 \(C{I_4}\)
2 \(Ge{I_4}\)
3 \(Sn{I_4}\)
4 \(Pb{I_4}\)
Explanation:
(d) \(Pb{I_4}\) is least stable because of two reasons \((1)\) Size of iodine is biggest. \((2)\) \( + 2\) oxidation state of \(Pb\) is more stable than \( + 4\) state because of inert pair effect.
07. The p-BLOCK ELEMENTS (XII)
189214
Chlorine cannot displace
1 Fluorine from \(NaF\)
2 Iodine from \(NaI\)
3 Bromine from \(NaBr\)
4 None of these
Explanation:
(a) \(C{l_2} + NaF\, \to \,{\rm{No\, reaction}}\) Since \(C{l_2}\) is less electronegative then \({F_2}\). Therefore unable to displace fluorine from its salt.
07. The p-BLOCK ELEMENTS (XII)
189218
At room temperature \({H_2}O\) is a liquid while \({H_2}S\) is a gas. The reason is
1 Electronegativity of \(O\) is greater than \(S\)
2 Difference in the bond angles of both the molecules
3 Association takes place in \({H_2}O\) due to \(H\) - bonding while no \(H\) - bonding in \({H_2}S\)
4 \(O\) and \(S\) belong to different periods
Explanation:
(c) \({H_2}O\)contain hydrogen bond while no hydrogen bonding is present in \({H_2}S\).
189213
Which of the following halides is least stable and has doubtful existence
1 \(C{I_4}\)
2 \(Ge{I_4}\)
3 \(Sn{I_4}\)
4 \(Pb{I_4}\)
Explanation:
(d) \(Pb{I_4}\) is least stable because of two reasons \((1)\) Size of iodine is biggest. \((2)\) \( + 2\) oxidation state of \(Pb\) is more stable than \( + 4\) state because of inert pair effect.
07. The p-BLOCK ELEMENTS (XII)
189214
Chlorine cannot displace
1 Fluorine from \(NaF\)
2 Iodine from \(NaI\)
3 Bromine from \(NaBr\)
4 None of these
Explanation:
(a) \(C{l_2} + NaF\, \to \,{\rm{No\, reaction}}\) Since \(C{l_2}\) is less electronegative then \({F_2}\). Therefore unable to displace fluorine from its salt.
07. The p-BLOCK ELEMENTS (XII)
189218
At room temperature \({H_2}O\) is a liquid while \({H_2}S\) is a gas. The reason is
1 Electronegativity of \(O\) is greater than \(S\)
2 Difference in the bond angles of both the molecules
3 Association takes place in \({H_2}O\) due to \(H\) - bonding while no \(H\) - bonding in \({H_2}S\)
4 \(O\) and \(S\) belong to different periods
Explanation:
(c) \({H_2}O\)contain hydrogen bond while no hydrogen bonding is present in \({H_2}S\).
