9 RBTS PAPER(PHYSICS)
9 RBTS PAPER

162371 A regular hexagon of side \(\mathbf{1 0} \mathrm{cm}\) has a charge \(5 \mu \mathrm{C}\) at each of its vertices. Calculate the potential at the centre of the hexagon.

1 \(9.3 \times 10^6 \mathrm{~V}\)
2 \(5.4 \times 10^6 \mathrm{~V}\)
3 \(8.1 \times 10^6 \mathrm{~V}\)
4 \(2.7 \times 10^6 \mathrm{~V}\)
9 RBTS PAPER

162401 The potential difference between points \(A\) and \(B\) \(\left(V_B-V_A\right)\) in the figure if \(R=0.7 \Omega\) is :

1 \(3 \mathrm{~V}\)
2 \(15 \mathrm{~V}\)
3 \(-5.1 \mathrm{~V}\)
4 +5.1 V.
9 RBTS PAPER

162369 A molecule of a substance has a permanent electric dipole moment of magnitude \(10^{-29} \mathrm{~cm}\). A mole of this substance is polarised (at low temperature) by applying a strong electrostatic field of magnitude \(10^6 \mathrm{~V} \mathrm{~m}^{-1}\). The direction of the field is suddenly changed by an angle of \(60^{\circ}\). Estimate the heat released by the substance in aligning its dipoles along the new direction of the field (only magnitude). For simplicity, assume \(100 \%\) polarisation of the sample.

1 \(6 \mathrm{~J}\)
2 \(18 \mathrm{~J}\)
3 \(3 \mathrm{~J}\)
4 \(12 \mathrm{~J}\)
9 RBTS PAPER

162365 Calculate the potential at a point \(P\) due to a charge of \(4 \times 10^{-7} \mathrm{C}\) located \(9 \mathrm{~cm}\) away.

1 \(4 \times 10^4 \mathrm{~V}\)
2 \(8 \times 10^4 \mathrm{~V}\)
3 \(10 \times 10^4 \mathrm{~V}\)
4 \(12 \times 10^4 \mathrm{~V}\)
9 RBTS PAPER

162366 Two charges \(3 \times 10^{-8} \mathrm{C}\) and \(-2 \times 10^{-8} \mathrm{C}\) are located \(15 \mathrm{~cm}\) apart. At what point on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

1 Electric potential is zero at \(5 \mathrm{~cm}\) and \(35 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
2 Electric potential is zero at \(9 \mathrm{~cm}\) and \(45 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
3 Electric potential is zero at \(10 \mathrm{~cm}\) and \(45 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
4 Electric potential is zero at \(9 \mathrm{~cm}\) and \(30 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
9 RBTS PAPER

162371 A regular hexagon of side \(\mathbf{1 0} \mathrm{cm}\) has a charge \(5 \mu \mathrm{C}\) at each of its vertices. Calculate the potential at the centre of the hexagon.

1 \(9.3 \times 10^6 \mathrm{~V}\)
2 \(5.4 \times 10^6 \mathrm{~V}\)
3 \(8.1 \times 10^6 \mathrm{~V}\)
4 \(2.7 \times 10^6 \mathrm{~V}\)
9 RBTS PAPER

162401 The potential difference between points \(A\) and \(B\) \(\left(V_B-V_A\right)\) in the figure if \(R=0.7 \Omega\) is :

1 \(3 \mathrm{~V}\)
2 \(15 \mathrm{~V}\)
3 \(-5.1 \mathrm{~V}\)
4 +5.1 V.
9 RBTS PAPER

162369 A molecule of a substance has a permanent electric dipole moment of magnitude \(10^{-29} \mathrm{~cm}\). A mole of this substance is polarised (at low temperature) by applying a strong electrostatic field of magnitude \(10^6 \mathrm{~V} \mathrm{~m}^{-1}\). The direction of the field is suddenly changed by an angle of \(60^{\circ}\). Estimate the heat released by the substance in aligning its dipoles along the new direction of the field (only magnitude). For simplicity, assume \(100 \%\) polarisation of the sample.

1 \(6 \mathrm{~J}\)
2 \(18 \mathrm{~J}\)
3 \(3 \mathrm{~J}\)
4 \(12 \mathrm{~J}\)
9 RBTS PAPER

162365 Calculate the potential at a point \(P\) due to a charge of \(4 \times 10^{-7} \mathrm{C}\) located \(9 \mathrm{~cm}\) away.

1 \(4 \times 10^4 \mathrm{~V}\)
2 \(8 \times 10^4 \mathrm{~V}\)
3 \(10 \times 10^4 \mathrm{~V}\)
4 \(12 \times 10^4 \mathrm{~V}\)
9 RBTS PAPER

162366 Two charges \(3 \times 10^{-8} \mathrm{C}\) and \(-2 \times 10^{-8} \mathrm{C}\) are located \(15 \mathrm{~cm}\) apart. At what point on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

1 Electric potential is zero at \(5 \mathrm{~cm}\) and \(35 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
2 Electric potential is zero at \(9 \mathrm{~cm}\) and \(45 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
3 Electric potential is zero at \(10 \mathrm{~cm}\) and \(45 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
4 Electric potential is zero at \(9 \mathrm{~cm}\) and \(30 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
9 RBTS PAPER

162371 A regular hexagon of side \(\mathbf{1 0} \mathrm{cm}\) has a charge \(5 \mu \mathrm{C}\) at each of its vertices. Calculate the potential at the centre of the hexagon.

1 \(9.3 \times 10^6 \mathrm{~V}\)
2 \(5.4 \times 10^6 \mathrm{~V}\)
3 \(8.1 \times 10^6 \mathrm{~V}\)
4 \(2.7 \times 10^6 \mathrm{~V}\)
9 RBTS PAPER

162401 The potential difference between points \(A\) and \(B\) \(\left(V_B-V_A\right)\) in the figure if \(R=0.7 \Omega\) is :

1 \(3 \mathrm{~V}\)
2 \(15 \mathrm{~V}\)
3 \(-5.1 \mathrm{~V}\)
4 +5.1 V.
9 RBTS PAPER

162369 A molecule of a substance has a permanent electric dipole moment of magnitude \(10^{-29} \mathrm{~cm}\). A mole of this substance is polarised (at low temperature) by applying a strong electrostatic field of magnitude \(10^6 \mathrm{~V} \mathrm{~m}^{-1}\). The direction of the field is suddenly changed by an angle of \(60^{\circ}\). Estimate the heat released by the substance in aligning its dipoles along the new direction of the field (only magnitude). For simplicity, assume \(100 \%\) polarisation of the sample.

1 \(6 \mathrm{~J}\)
2 \(18 \mathrm{~J}\)
3 \(3 \mathrm{~J}\)
4 \(12 \mathrm{~J}\)
9 RBTS PAPER

162365 Calculate the potential at a point \(P\) due to a charge of \(4 \times 10^{-7} \mathrm{C}\) located \(9 \mathrm{~cm}\) away.

1 \(4 \times 10^4 \mathrm{~V}\)
2 \(8 \times 10^4 \mathrm{~V}\)
3 \(10 \times 10^4 \mathrm{~V}\)
4 \(12 \times 10^4 \mathrm{~V}\)
9 RBTS PAPER

162366 Two charges \(3 \times 10^{-8} \mathrm{C}\) and \(-2 \times 10^{-8} \mathrm{C}\) are located \(15 \mathrm{~cm}\) apart. At what point on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

1 Electric potential is zero at \(5 \mathrm{~cm}\) and \(35 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
2 Electric potential is zero at \(9 \mathrm{~cm}\) and \(45 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
3 Electric potential is zero at \(10 \mathrm{~cm}\) and \(45 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
4 Electric potential is zero at \(9 \mathrm{~cm}\) and \(30 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
9 RBTS PAPER

162371 A regular hexagon of side \(\mathbf{1 0} \mathrm{cm}\) has a charge \(5 \mu \mathrm{C}\) at each of its vertices. Calculate the potential at the centre of the hexagon.

1 \(9.3 \times 10^6 \mathrm{~V}\)
2 \(5.4 \times 10^6 \mathrm{~V}\)
3 \(8.1 \times 10^6 \mathrm{~V}\)
4 \(2.7 \times 10^6 \mathrm{~V}\)
9 RBTS PAPER

162401 The potential difference between points \(A\) and \(B\) \(\left(V_B-V_A\right)\) in the figure if \(R=0.7 \Omega\) is :

1 \(3 \mathrm{~V}\)
2 \(15 \mathrm{~V}\)
3 \(-5.1 \mathrm{~V}\)
4 +5.1 V.
9 RBTS PAPER

162369 A molecule of a substance has a permanent electric dipole moment of magnitude \(10^{-29} \mathrm{~cm}\). A mole of this substance is polarised (at low temperature) by applying a strong electrostatic field of magnitude \(10^6 \mathrm{~V} \mathrm{~m}^{-1}\). The direction of the field is suddenly changed by an angle of \(60^{\circ}\). Estimate the heat released by the substance in aligning its dipoles along the new direction of the field (only magnitude). For simplicity, assume \(100 \%\) polarisation of the sample.

1 \(6 \mathrm{~J}\)
2 \(18 \mathrm{~J}\)
3 \(3 \mathrm{~J}\)
4 \(12 \mathrm{~J}\)
9 RBTS PAPER

162365 Calculate the potential at a point \(P\) due to a charge of \(4 \times 10^{-7} \mathrm{C}\) located \(9 \mathrm{~cm}\) away.

1 \(4 \times 10^4 \mathrm{~V}\)
2 \(8 \times 10^4 \mathrm{~V}\)
3 \(10 \times 10^4 \mathrm{~V}\)
4 \(12 \times 10^4 \mathrm{~V}\)
9 RBTS PAPER

162366 Two charges \(3 \times 10^{-8} \mathrm{C}\) and \(-2 \times 10^{-8} \mathrm{C}\) are located \(15 \mathrm{~cm}\) apart. At what point on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

1 Electric potential is zero at \(5 \mathrm{~cm}\) and \(35 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
2 Electric potential is zero at \(9 \mathrm{~cm}\) and \(45 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
3 Electric potential is zero at \(10 \mathrm{~cm}\) and \(45 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
4 Electric potential is zero at \(9 \mathrm{~cm}\) and \(30 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
9 RBTS PAPER

162371 A regular hexagon of side \(\mathbf{1 0} \mathrm{cm}\) has a charge \(5 \mu \mathrm{C}\) at each of its vertices. Calculate the potential at the centre of the hexagon.

1 \(9.3 \times 10^6 \mathrm{~V}\)
2 \(5.4 \times 10^6 \mathrm{~V}\)
3 \(8.1 \times 10^6 \mathrm{~V}\)
4 \(2.7 \times 10^6 \mathrm{~V}\)
9 RBTS PAPER

162401 The potential difference between points \(A\) and \(B\) \(\left(V_B-V_A\right)\) in the figure if \(R=0.7 \Omega\) is :

1 \(3 \mathrm{~V}\)
2 \(15 \mathrm{~V}\)
3 \(-5.1 \mathrm{~V}\)
4 +5.1 V.
9 RBTS PAPER

162369 A molecule of a substance has a permanent electric dipole moment of magnitude \(10^{-29} \mathrm{~cm}\). A mole of this substance is polarised (at low temperature) by applying a strong electrostatic field of magnitude \(10^6 \mathrm{~V} \mathrm{~m}^{-1}\). The direction of the field is suddenly changed by an angle of \(60^{\circ}\). Estimate the heat released by the substance in aligning its dipoles along the new direction of the field (only magnitude). For simplicity, assume \(100 \%\) polarisation of the sample.

1 \(6 \mathrm{~J}\)
2 \(18 \mathrm{~J}\)
3 \(3 \mathrm{~J}\)
4 \(12 \mathrm{~J}\)
9 RBTS PAPER

162365 Calculate the potential at a point \(P\) due to a charge of \(4 \times 10^{-7} \mathrm{C}\) located \(9 \mathrm{~cm}\) away.

1 \(4 \times 10^4 \mathrm{~V}\)
2 \(8 \times 10^4 \mathrm{~V}\)
3 \(10 \times 10^4 \mathrm{~V}\)
4 \(12 \times 10^4 \mathrm{~V}\)
9 RBTS PAPER

162366 Two charges \(3 \times 10^{-8} \mathrm{C}\) and \(-2 \times 10^{-8} \mathrm{C}\) are located \(15 \mathrm{~cm}\) apart. At what point on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

1 Electric potential is zero at \(5 \mathrm{~cm}\) and \(35 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
2 Electric potential is zero at \(9 \mathrm{~cm}\) and \(45 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
3 Electric potential is zero at \(10 \mathrm{~cm}\) and \(45 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.
4 Electric potential is zero at \(9 \mathrm{~cm}\) and \(30 \mathrm{~cm}\) away from the positive charge on the side of the negative charge.