5 RBTS PAPER
163982
If the radius of a planet is \(R\) and its density is \(\rho\), the escape velocity from its surface will be :
1 \(v_e \propto \rho R\)
2 \(v_e \propto R \sqrt{\rho}\)
3 \(v_e \propto \frac{\sqrt{\rho}}{R}\)
4 \(v_e \propto \frac{1}{\sqrt{\rho R}}\)
Explanation:
\( v_e=R \sqrt{\frac{8}{3} G \pi \rho} \)
\( v_e \propto R \sqrt{\rho} \)