160834
In which of the following, bond angle is maximum:
1 $\mathrm{NH}_3$
2 $\mathrm{NH}_4^{+}$
3 $\mathrm{PCl}_3$
4 $\mathrm{SCl}_2$
Explanation:
nan
CBSE 2001
2 RBTS PAPER
160835
In the aqueous solution of orthoboric acid the anionic species present will be :
1 $\mathrm{BO}_3^{-3}$
2 $\left[\mathrm{B}(\mathrm{OH})_4\right]^{-}$
3 $\left[\mathrm{HBO}_3\right]^{-}$
4 All of these
Explanation:
Aqueous solution of orthoboric acid has $\mathrm{H}^{+}$and $\left[\mathrm{B}(\mathrm{OH})_4\right]^{-}$.
Module 171
2 RBTS PAPER
160836
Using MO theory predict which of the following species has the shortest bond length
1 $\mathrm{O}_2^{2+}$
2 $\mathrm{O}_2^{+}$
3 $\mathrm{O}_2^*$
4 $\mathrm{O}_2^{2-}$
Explanation:
Bond length $\propto \frac{1}{\text { Bond order }} ;$ B.O. of $\mathrm{O}_2^{2+}, \mathrm{O}_2^{+}, \mathrm{O}_2^{-}$ and $\mathrm{O}_2^{2-}$ are 3.0, 2.5, 1.5 and 1 respectively.
NCERT 126
2 RBTS PAPER
160837
Which of the following statement is not correct from the view point of molecular orbital theory?
1 $\mathrm{Be}_2$ is not a stable molecule.
2 $\mathrm{He}_2$ is not stable but $\mathrm{He}_2{ }^{+}$is expected to exist.
3 Bond strength of $\mathrm{N}_2$ is maximum amongst the homonuclear diatomic molecules belonging to the second period.
4 The order of energies of molecular orbitals in $\mathrm{N}_2$ molecule is $\sigma 2 s<\sigma^* 2 s<\sigma 2 p_z<\left(\pi 2 p_x=\pi 2 p_y\right)<\left(\pi^* 2 p_x=\pi^* 2 p_y\right)<\sigma^* 2 p_z$
Explanation:
The correct order of energies of molecular orbitals in $\mathrm{N}_2$ molecule is $\begin{aligned} & \mathrm{KK} \sigma 2 \mathrm{~s}<\sigma^{\star} 2 \mathrm{~s}<\left(\pi 2 \mathrm{p}_{\mathrm{x}}=\pi 2 \mathrm{p}_{\mathrm{y}}\right)<\sigma 2 \mathrm{p}_{\mathrm{z}}<\left(\pi^{\star} 2 \mathrm{p}_{\mathrm{x}}=\right. \\ & \left.\pi^{\star} 2 \mathrm{p}_{\mathrm{y}}\right)<\sigma^{\star} 2 \mathrm{p}_{\mathrm{z}} \end{aligned}$
160834
In which of the following, bond angle is maximum:
1 $\mathrm{NH}_3$
2 $\mathrm{NH}_4^{+}$
3 $\mathrm{PCl}_3$
4 $\mathrm{SCl}_2$
Explanation:
nan
CBSE 2001
2 RBTS PAPER
160835
In the aqueous solution of orthoboric acid the anionic species present will be :
1 $\mathrm{BO}_3^{-3}$
2 $\left[\mathrm{B}(\mathrm{OH})_4\right]^{-}$
3 $\left[\mathrm{HBO}_3\right]^{-}$
4 All of these
Explanation:
Aqueous solution of orthoboric acid has $\mathrm{H}^{+}$and $\left[\mathrm{B}(\mathrm{OH})_4\right]^{-}$.
Module 171
2 RBTS PAPER
160836
Using MO theory predict which of the following species has the shortest bond length
1 $\mathrm{O}_2^{2+}$
2 $\mathrm{O}_2^{+}$
3 $\mathrm{O}_2^*$
4 $\mathrm{O}_2^{2-}$
Explanation:
Bond length $\propto \frac{1}{\text { Bond order }} ;$ B.O. of $\mathrm{O}_2^{2+}, \mathrm{O}_2^{+}, \mathrm{O}_2^{-}$ and $\mathrm{O}_2^{2-}$ are 3.0, 2.5, 1.5 and 1 respectively.
NCERT 126
2 RBTS PAPER
160837
Which of the following statement is not correct from the view point of molecular orbital theory?
1 $\mathrm{Be}_2$ is not a stable molecule.
2 $\mathrm{He}_2$ is not stable but $\mathrm{He}_2{ }^{+}$is expected to exist.
3 Bond strength of $\mathrm{N}_2$ is maximum amongst the homonuclear diatomic molecules belonging to the second period.
4 The order of energies of molecular orbitals in $\mathrm{N}_2$ molecule is $\sigma 2 s<\sigma^* 2 s<\sigma 2 p_z<\left(\pi 2 p_x=\pi 2 p_y\right)<\left(\pi^* 2 p_x=\pi^* 2 p_y\right)<\sigma^* 2 p_z$
Explanation:
The correct order of energies of molecular orbitals in $\mathrm{N}_2$ molecule is $\begin{aligned} & \mathrm{KK} \sigma 2 \mathrm{~s}<\sigma^{\star} 2 \mathrm{~s}<\left(\pi 2 \mathrm{p}_{\mathrm{x}}=\pi 2 \mathrm{p}_{\mathrm{y}}\right)<\sigma 2 \mathrm{p}_{\mathrm{z}}<\left(\pi^{\star} 2 \mathrm{p}_{\mathrm{x}}=\right. \\ & \left.\pi^{\star} 2 \mathrm{p}_{\mathrm{y}}\right)<\sigma^{\star} 2 \mathrm{p}_{\mathrm{z}} \end{aligned}$
160834
In which of the following, bond angle is maximum:
1 $\mathrm{NH}_3$
2 $\mathrm{NH}_4^{+}$
3 $\mathrm{PCl}_3$
4 $\mathrm{SCl}_2$
Explanation:
nan
CBSE 2001
2 RBTS PAPER
160835
In the aqueous solution of orthoboric acid the anionic species present will be :
1 $\mathrm{BO}_3^{-3}$
2 $\left[\mathrm{B}(\mathrm{OH})_4\right]^{-}$
3 $\left[\mathrm{HBO}_3\right]^{-}$
4 All of these
Explanation:
Aqueous solution of orthoboric acid has $\mathrm{H}^{+}$and $\left[\mathrm{B}(\mathrm{OH})_4\right]^{-}$.
Module 171
2 RBTS PAPER
160836
Using MO theory predict which of the following species has the shortest bond length
1 $\mathrm{O}_2^{2+}$
2 $\mathrm{O}_2^{+}$
3 $\mathrm{O}_2^*$
4 $\mathrm{O}_2^{2-}$
Explanation:
Bond length $\propto \frac{1}{\text { Bond order }} ;$ B.O. of $\mathrm{O}_2^{2+}, \mathrm{O}_2^{+}, \mathrm{O}_2^{-}$ and $\mathrm{O}_2^{2-}$ are 3.0, 2.5, 1.5 and 1 respectively.
NCERT 126
2 RBTS PAPER
160837
Which of the following statement is not correct from the view point of molecular orbital theory?
1 $\mathrm{Be}_2$ is not a stable molecule.
2 $\mathrm{He}_2$ is not stable but $\mathrm{He}_2{ }^{+}$is expected to exist.
3 Bond strength of $\mathrm{N}_2$ is maximum amongst the homonuclear diatomic molecules belonging to the second period.
4 The order of energies of molecular orbitals in $\mathrm{N}_2$ molecule is $\sigma 2 s<\sigma^* 2 s<\sigma 2 p_z<\left(\pi 2 p_x=\pi 2 p_y\right)<\left(\pi^* 2 p_x=\pi^* 2 p_y\right)<\sigma^* 2 p_z$
Explanation:
The correct order of energies of molecular orbitals in $\mathrm{N}_2$ molecule is $\begin{aligned} & \mathrm{KK} \sigma 2 \mathrm{~s}<\sigma^{\star} 2 \mathrm{~s}<\left(\pi 2 \mathrm{p}_{\mathrm{x}}=\pi 2 \mathrm{p}_{\mathrm{y}}\right)<\sigma 2 \mathrm{p}_{\mathrm{z}}<\left(\pi^{\star} 2 \mathrm{p}_{\mathrm{x}}=\right. \\ & \left.\pi^{\star} 2 \mathrm{p}_{\mathrm{y}}\right)<\sigma^{\star} 2 \mathrm{p}_{\mathrm{z}} \end{aligned}$
160834
In which of the following, bond angle is maximum:
1 $\mathrm{NH}_3$
2 $\mathrm{NH}_4^{+}$
3 $\mathrm{PCl}_3$
4 $\mathrm{SCl}_2$
Explanation:
nan
CBSE 2001
2 RBTS PAPER
160835
In the aqueous solution of orthoboric acid the anionic species present will be :
1 $\mathrm{BO}_3^{-3}$
2 $\left[\mathrm{B}(\mathrm{OH})_4\right]^{-}$
3 $\left[\mathrm{HBO}_3\right]^{-}$
4 All of these
Explanation:
Aqueous solution of orthoboric acid has $\mathrm{H}^{+}$and $\left[\mathrm{B}(\mathrm{OH})_4\right]^{-}$.
Module 171
2 RBTS PAPER
160836
Using MO theory predict which of the following species has the shortest bond length
1 $\mathrm{O}_2^{2+}$
2 $\mathrm{O}_2^{+}$
3 $\mathrm{O}_2^*$
4 $\mathrm{O}_2^{2-}$
Explanation:
Bond length $\propto \frac{1}{\text { Bond order }} ;$ B.O. of $\mathrm{O}_2^{2+}, \mathrm{O}_2^{+}, \mathrm{O}_2^{-}$ and $\mathrm{O}_2^{2-}$ are 3.0, 2.5, 1.5 and 1 respectively.
NCERT 126
2 RBTS PAPER
160837
Which of the following statement is not correct from the view point of molecular orbital theory?
1 $\mathrm{Be}_2$ is not a stable molecule.
2 $\mathrm{He}_2$ is not stable but $\mathrm{He}_2{ }^{+}$is expected to exist.
3 Bond strength of $\mathrm{N}_2$ is maximum amongst the homonuclear diatomic molecules belonging to the second period.
4 The order of energies of molecular orbitals in $\mathrm{N}_2$ molecule is $\sigma 2 s<\sigma^* 2 s<\sigma 2 p_z<\left(\pi 2 p_x=\pi 2 p_y\right)<\left(\pi^* 2 p_x=\pi^* 2 p_y\right)<\sigma^* 2 p_z$
Explanation:
The correct order of energies of molecular orbitals in $\mathrm{N}_2$ molecule is $\begin{aligned} & \mathrm{KK} \sigma 2 \mathrm{~s}<\sigma^{\star} 2 \mathrm{~s}<\left(\pi 2 \mathrm{p}_{\mathrm{x}}=\pi 2 \mathrm{p}_{\mathrm{y}}\right)<\sigma 2 \mathrm{p}_{\mathrm{z}}<\left(\pi^{\star} 2 \mathrm{p}_{\mathrm{x}}=\right. \\ & \left.\pi^{\star} 2 \mathrm{p}_{\mathrm{y}}\right)<\sigma^{\star} 2 \mathrm{p}_{\mathrm{z}} \end{aligned}$
