160783 A monkey of mass $\mathbf{2 0} \mathbf{~ k g}$ is holding a vertical rope. The rope will not break when a mass of $25 \mathbf{~ k g}$ is suspended from it but will break if the mass exceeds $25 \mathrm{~kg}$. What is the maximum acceleration with which the monkey can climb up along the rope? $\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)$
160785 A body of mass $\mathbf{1 0} \mathbf{~ k g}$ lies on a rough horizontal surface. When a horizontal force of $F$ Newtons acts on it, it gets an acceleration of $5 \mathrm{~m} / \mathrm{s}^2$ and when the horizontal force is doubled, it gets an acceleration of $18 \mathrm{~m} / \mathrm{s}^2$. The coefficient of friction between the body and the horizontal surface (assume $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ ) is
160783 A monkey of mass $\mathbf{2 0} \mathbf{~ k g}$ is holding a vertical rope. The rope will not break when a mass of $25 \mathbf{~ k g}$ is suspended from it but will break if the mass exceeds $25 \mathrm{~kg}$. What is the maximum acceleration with which the monkey can climb up along the rope? $\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)$
160785 A body of mass $\mathbf{1 0} \mathbf{~ k g}$ lies on a rough horizontal surface. When a horizontal force of $F$ Newtons acts on it, it gets an acceleration of $5 \mathrm{~m} / \mathrm{s}^2$ and when the horizontal force is doubled, it gets an acceleration of $18 \mathrm{~m} / \mathrm{s}^2$. The coefficient of friction between the body and the horizontal surface (assume $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ ) is
160783 A monkey of mass $\mathbf{2 0} \mathbf{~ k g}$ is holding a vertical rope. The rope will not break when a mass of $25 \mathbf{~ k g}$ is suspended from it but will break if the mass exceeds $25 \mathrm{~kg}$. What is the maximum acceleration with which the monkey can climb up along the rope? $\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)$
160785 A body of mass $\mathbf{1 0} \mathbf{~ k g}$ lies on a rough horizontal surface. When a horizontal force of $F$ Newtons acts on it, it gets an acceleration of $5 \mathrm{~m} / \mathrm{s}^2$ and when the horizontal force is doubled, it gets an acceleration of $18 \mathrm{~m} / \mathrm{s}^2$. The coefficient of friction between the body and the horizontal surface (assume $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ ) is
160783 A monkey of mass $\mathbf{2 0} \mathbf{~ k g}$ is holding a vertical rope. The rope will not break when a mass of $25 \mathbf{~ k g}$ is suspended from it but will break if the mass exceeds $25 \mathrm{~kg}$. What is the maximum acceleration with which the monkey can climb up along the rope? $\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right)$
160785 A body of mass $\mathbf{1 0} \mathbf{~ k g}$ lies on a rough horizontal surface. When a horizontal force of $F$ Newtons acts on it, it gets an acceleration of $5 \mathrm{~m} / \mathrm{s}^2$ and when the horizontal force is doubled, it gets an acceleration of $18 \mathrm{~m} / \mathrm{s}^2$. The coefficient of friction between the body and the horizontal surface (assume $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ ) is