QBManager

1 RBTS PAPER

160625 In three moles of ethane $(C_{2} H_{6})$ calculate the Number of hydrogen atoms and Number of carbon atoms respectively :

1

2 N_{0}

and

16 N_{0}

2

18 N_{0}

and

6 N_{0}

3

6 N_{0}

and

6 N_{0}

4

6 N_{0}

and

18 N_{0}

Explanation:

No. of $H$ atom
$\begin{aligned} = {nN}_{A} \times 6 \\ = 3 N_{A} \times 6 \\ = 18 N_{A} \\ = {nN}_{A} \times 2 \\ = 3 N_{A} \times 2 \\ = 6 N_{A} \end{aligned}$

NCERT 22

1 RBTS PAPER

160626 What is the weight of oxygen required for the complete combution of $2.8 g$ of ethylene :

1

2.8 g

2

6.4 g

3

9.6 g

4

96 g

Explanation:

Equal volumes contain equal no. of molecules.
Hence No. of atoms of $H_{2}, He, O_{2}$ and $O_{3}$ will be in the ratio $2 : 1 : 2 : 3$ .

CBSE 2004

1 RBTS PAPER

160627 $1000 g$ aqueous solution of ${CaCO}_{3}$ contains $10 g$ of calcium carbonate. Concentration of solution is :

1

10 ppm

2

100 ppm

3

1000 ppm

4

10000 ppm

Explanation:

Conc. of Solution $= \frac{wt of Solute (gm)}{wt of Solution (gm)} \times 10^{6}$
$\begin{aligned} = \frac{10}{1000} \times 10^{6} \\ = 10^{4} \end{aligned}$

NCERT 25

1 RBTS PAPER

160628 $10 g HCl$ is dissolved in $250 mL$ of its aqueous solution. If density of the solution is $1.2 g / mL$ . The molality of the solution will be :

1 1

2 0.34

3 0.945

4 3.4

Explanation:

wt. of solvent $= 300 - 10 = 290 gm$
$\begin{aligned} (m & = V \cdot D = 25 \times 1.2 = 300 gm) \\ m & = \frac{w}{GMM} \times \frac{1000}{w (solvent)} \\ = \frac{10}{36.5} \times \frac{1000}{290} = 0.945 \end{aligned}$

NCERT 20

1 RBTS PAPER

160631 The molecular weight of $O_{2}$ and ${SO}_{2}$ are 32 and 64 respectively. At $15^{\circ} C$ and $150 mmHg$ pressure, $1 L$ of $O_{2}$ contains ' $N$ ' molecules. The number of molecules in $2 L$ of ${SO}_{2}$ under the same conditions of temperature and pressure will be:

1

N / 2

2

N

3

2 N

4

4 N

NCERT-12

1 RBTS PAPER

160625 In three moles of ethane $(C_{2} H_{6})$ calculate the Number of hydrogen atoms and Number of carbon atoms respectively :

1

2 N_{0}

and

16 N_{0}

2

18 N_{0}

and

6 N_{0}

3

6 N_{0}

and

6 N_{0}

4

6 N_{0}

and

18 N_{0}

Explanation:

No. of $H$ atom
$\begin{aligned} = {nN}_{A} \times 6 \\ = 3 N_{A} \times 6 \\ = 18 N_{A} \\ = {nN}_{A} \times 2 \\ = 3 N_{A} \times 2 \\ = 6 N_{A} \end{aligned}$

NCERT 22

1 RBTS PAPER

160626 What is the weight of oxygen required for the complete combution of $2.8 g$ of ethylene :

1

2.8 g

2

6.4 g

3

9.6 g

4

96 g

Explanation:

Equal volumes contain equal no. of molecules.
Hence No. of atoms of $H_{2}, He, O_{2}$ and $O_{3}$ will be in the ratio $2 : 1 : 2 : 3$ .

CBSE 2004

1 RBTS PAPER

160627 $1000 g$ aqueous solution of ${CaCO}_{3}$ contains $10 g$ of calcium carbonate. Concentration of solution is :

1

10 ppm

2

100 ppm

3

1000 ppm

4

10000 ppm

Explanation:

Conc. of Solution $= \frac{wt of Solute (gm)}{wt of Solution (gm)} \times 10^{6}$
$\begin{aligned} = \frac{10}{1000} \times 10^{6} \\ = 10^{4} \end{aligned}$

NCERT 25

1 RBTS PAPER

160628 $10 g HCl$ is dissolved in $250 mL$ of its aqueous solution. If density of the solution is $1.2 g / mL$ . The molality of the solution will be :

1 1

2 0.34

3 0.945

4 3.4

Explanation:

wt. of solvent $= 300 - 10 = 290 gm$
$\begin{aligned} (m & = V \cdot D = 25 \times 1.2 = 300 gm) \\ m & = \frac{w}{GMM} \times \frac{1000}{w (solvent)} \\ = \frac{10}{36.5} \times \frac{1000}{290} = 0.945 \end{aligned}$

NCERT 20

1 RBTS PAPER

160631 The molecular weight of $O_{2}$ and ${SO}_{2}$ are 32 and 64 respectively. At $15^{\circ} C$ and $150 mmHg$ pressure, $1 L$ of $O_{2}$ contains ' $N$ ' molecules. The number of molecules in $2 L$ of ${SO}_{2}$ under the same conditions of temperature and pressure will be:

1

N / 2

2

N

3

2 N

4

4 N

NCERT-12

1 RBTS PAPER

160625 In three moles of ethane $(C_{2} H_{6})$ calculate the Number of hydrogen atoms and Number of carbon atoms respectively :

1

2 N_{0}

and

16 N_{0}

2

18 N_{0}

and

6 N_{0}

3

6 N_{0}

and

6 N_{0}

4

6 N_{0}

and

18 N_{0}

Explanation:

No. of $H$ atom
$\begin{aligned} = {nN}_{A} \times 6 \\ = 3 N_{A} \times 6 \\ = 18 N_{A} \\ = {nN}_{A} \times 2 \\ = 3 N_{A} \times 2 \\ = 6 N_{A} \end{aligned}$

NCERT 22

1 RBTS PAPER

160626 What is the weight of oxygen required for the complete combution of $2.8 g$ of ethylene :

1

2.8 g

2

6.4 g

3

9.6 g

4

96 g

Explanation:

Equal volumes contain equal no. of molecules.
Hence No. of atoms of $H_{2}, He, O_{2}$ and $O_{3}$ will be in the ratio $2 : 1 : 2 : 3$ .

CBSE 2004

1 RBTS PAPER

160627 $1000 g$ aqueous solution of ${CaCO}_{3}$ contains $10 g$ of calcium carbonate. Concentration of solution is :

1

10 ppm

2

100 ppm

3

1000 ppm

4

10000 ppm

Explanation:

Conc. of Solution $= \frac{wt of Solute (gm)}{wt of Solution (gm)} \times 10^{6}$
$\begin{aligned} = \frac{10}{1000} \times 10^{6} \\ = 10^{4} \end{aligned}$

NCERT 25

1 RBTS PAPER

160628 $10 g HCl$ is dissolved in $250 mL$ of its aqueous solution. If density of the solution is $1.2 g / mL$ . The molality of the solution will be :

1 1

2 0.34

3 0.945

4 3.4

Explanation:

wt. of solvent $= 300 - 10 = 290 gm$
$\begin{aligned} (m & = V \cdot D = 25 \times 1.2 = 300 gm) \\ m & = \frac{w}{GMM} \times \frac{1000}{w (solvent)} \\ = \frac{10}{36.5} \times \frac{1000}{290} = 0.945 \end{aligned}$

NCERT 20

1 RBTS PAPER

160631 The molecular weight of $O_{2}$ and ${SO}_{2}$ are 32 and 64 respectively. At $15^{\circ} C$ and $150 mmHg$ pressure, $1 L$ of $O_{2}$ contains ' $N$ ' molecules. The number of molecules in $2 L$ of ${SO}_{2}$ under the same conditions of temperature and pressure will be:

1

N / 2

2

N

3

2 N

4

4 N

NCERT-12

1 RBTS PAPER

160625 In three moles of ethane $(C_{2} H_{6})$ calculate the Number of hydrogen atoms and Number of carbon atoms respectively :

1

2 N_{0}

and

16 N_{0}

2

18 N_{0}

and

6 N_{0}

3

6 N_{0}

and

6 N_{0}

4

6 N_{0}

and

18 N_{0}

Explanation:

No. of $H$ atom
$\begin{aligned} = {nN}_{A} \times 6 \\ = 3 N_{A} \times 6 \\ = 18 N_{A} \\ = {nN}_{A} \times 2 \\ = 3 N_{A} \times 2 \\ = 6 N_{A} \end{aligned}$

NCERT 22

1 RBTS PAPER

160626 What is the weight of oxygen required for the complete combution of $2.8 g$ of ethylene :

1

2.8 g

2

6.4 g

3

9.6 g

4

96 g

Explanation:

Equal volumes contain equal no. of molecules.
Hence No. of atoms of $H_{2}, He, O_{2}$ and $O_{3}$ will be in the ratio $2 : 1 : 2 : 3$ .

CBSE 2004

1 RBTS PAPER

160627 $1000 g$ aqueous solution of ${CaCO}_{3}$ contains $10 g$ of calcium carbonate. Concentration of solution is :

1

10 ppm

2

100 ppm

3

1000 ppm

4

10000 ppm

Explanation:

Conc. of Solution $= \frac{wt of Solute (gm)}{wt of Solution (gm)} \times 10^{6}$
$\begin{aligned} = \frac{10}{1000} \times 10^{6} \\ = 10^{4} \end{aligned}$

NCERT 25

1 RBTS PAPER

160628 $10 g HCl$ is dissolved in $250 mL$ of its aqueous solution. If density of the solution is $1.2 g / mL$ . The molality of the solution will be :

1 1

2 0.34

3 0.945

4 3.4

Explanation:

wt. of solvent $= 300 - 10 = 290 gm$
$\begin{aligned} (m & = V \cdot D = 25 \times 1.2 = 300 gm) \\ m & = \frac{w}{GMM} \times \frac{1000}{w (solvent)} \\ = \frac{10}{36.5} \times \frac{1000}{290} = 0.945 \end{aligned}$

NCERT 20

1 RBTS PAPER

160631 The molecular weight of $O_{2}$ and ${SO}_{2}$ are 32 and 64 respectively. At $15^{\circ} C$ and $150 mmHg$ pressure, $1 L$ of $O_{2}$ contains ' $N$ ' molecules. The number of molecules in $2 L$ of ${SO}_{2}$ under the same conditions of temperature and pressure will be:

1

N / 2

2

N

3

2 N

4

4 N

NCERT-12

1 RBTS PAPER

160625 In three moles of ethane $(C_{2} H_{6})$ calculate the Number of hydrogen atoms and Number of carbon atoms respectively :

1

2 N_{0}

and

16 N_{0}

2

18 N_{0}

and

6 N_{0}

3

6 N_{0}

and

6 N_{0}

4

6 N_{0}

and

18 N_{0}

Explanation:

No. of $H$ atom
$\begin{aligned} = {nN}_{A} \times 6 \\ = 3 N_{A} \times 6 \\ = 18 N_{A} \\ = {nN}_{A} \times 2 \\ = 3 N_{A} \times 2 \\ = 6 N_{A} \end{aligned}$

NCERT 22

1 RBTS PAPER

160626 What is the weight of oxygen required for the complete combution of $2.8 g$ of ethylene :

1

2.8 g

2

6.4 g

3

9.6 g

4

96 g

Explanation:

Equal volumes contain equal no. of molecules.
Hence No. of atoms of $H_{2}, He, O_{2}$ and $O_{3}$ will be in the ratio $2 : 1 : 2 : 3$ .

CBSE 2004

1 RBTS PAPER

160627 $1000 g$ aqueous solution of ${CaCO}_{3}$ contains $10 g$ of calcium carbonate. Concentration of solution is :

1

10 ppm

2

100 ppm

3

1000 ppm

4

10000 ppm

Explanation:

Conc. of Solution $= \frac{wt of Solute (gm)}{wt of Solution (gm)} \times 10^{6}$
$\begin{aligned} = \frac{10}{1000} \times 10^{6} \\ = 10^{4} \end{aligned}$

NCERT 25

1 RBTS PAPER

160628 $10 g HCl$ is dissolved in $250 mL$ of its aqueous solution. If density of the solution is $1.2 g / mL$ . The molality of the solution will be :

1 1

2 0.34

3 0.945

4 3.4

Explanation:

wt. of solvent $= 300 - 10 = 290 gm$
$\begin{aligned} (m & = V \cdot D = 25 \times 1.2 = 300 gm) \\ m & = \frac{w}{GMM} \times \frac{1000}{w (solvent)} \\ = \frac{10}{36.5} \times \frac{1000}{290} = 0.945 \end{aligned}$

NCERT 20

1 RBTS PAPER

160631 The molecular weight of $O_{2}$ and ${SO}_{2}$ are 32 and 64 respectively. At $15^{\circ} C$ and $150 mmHg$ pressure, $1 L$ of $O_{2}$ contains ' $N$ ' molecules. The number of molecules in $2 L$ of ${SO}_{2}$ under the same conditions of temperature and pressure will be:

1

N / 2

2

N

3

2 N

4

4 N

NCERT-12

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