163817 The molarity of \(98 \%(\mathrm{w} / \mathrm{W}) \mathrm{H}_2 \mathrm{SO}_4\left(\mathrm{~d}=1.8 \mathrm{~g} \mathrm{~mL}^{-1}\right)\) is:

163818 \(1 \mathbf{m o l}\) of heptane (V. \(\mathrm{P} . \mathbf{=} \mathbf{9 2} \mathrm{mm}\) of \(\mathrm{Hg}\) ) was mixed with \(4 \mathrm{~mol}\) of octane (V. P. \(=31 \mathrm{~mm}\) of \(\mathrm{Hg}\) ). The vapour pressure of resulting ideal solution is:

163819 At \(88^{\circ} \mathrm{C}\) benzene has a vapour pressure of 900 torr and toluene has a vapour pressure of 360 torr. What is the mole fraction of benzene in the mixture with toluene that will boil at \(88^{\circ} \mathrm{C}\) at 1 atm. pressure, (benzene - toluene form an ideal solution):

163820 Among the following, that does not form an ideal solution is:

163817 The molarity of \(98 \%(\mathrm{w} / \mathrm{W}) \mathrm{H}_2 \mathrm{SO}_4\left(\mathrm{~d}=1.8 \mathrm{~g} \mathrm{~mL}^{-1}\right)\) is:

163818 \(1 \mathbf{m o l}\) of heptane (V. \(\mathrm{P} . \mathbf{=} \mathbf{9 2} \mathrm{mm}\) of \(\mathrm{Hg}\) ) was mixed with \(4 \mathrm{~mol}\) of octane (V. P. \(=31 \mathrm{~mm}\) of \(\mathrm{Hg}\) ). The vapour pressure of resulting ideal solution is:

163819 At \(88^{\circ} \mathrm{C}\) benzene has a vapour pressure of 900 torr and toluene has a vapour pressure of 360 torr. What is the mole fraction of benzene in the mixture with toluene that will boil at \(88^{\circ} \mathrm{C}\) at 1 atm. pressure, (benzene - toluene form an ideal solution):

163820 Among the following, that does not form an ideal solution is:

163817 The molarity of \(98 \%(\mathrm{w} / \mathrm{W}) \mathrm{H}_2 \mathrm{SO}_4\left(\mathrm{~d}=1.8 \mathrm{~g} \mathrm{~mL}^{-1}\right)\) is:

163818 \(1 \mathbf{m o l}\) of heptane (V. \(\mathrm{P} . \mathbf{=} \mathbf{9 2} \mathrm{mm}\) of \(\mathrm{Hg}\) ) was mixed with \(4 \mathrm{~mol}\) of octane (V. P. \(=31 \mathrm{~mm}\) of \(\mathrm{Hg}\) ). The vapour pressure of resulting ideal solution is:

163819 At \(88^{\circ} \mathrm{C}\) benzene has a vapour pressure of 900 torr and toluene has a vapour pressure of 360 torr. What is the mole fraction of benzene in the mixture with toluene that will boil at \(88^{\circ} \mathrm{C}\) at 1 atm. pressure, (benzene - toluene form an ideal solution):

163820 Among the following, that does not form an ideal solution is:

163817 The molarity of \(98 \%(\mathrm{w} / \mathrm{W}) \mathrm{H}_2 \mathrm{SO}_4\left(\mathrm{~d}=1.8 \mathrm{~g} \mathrm{~mL}^{-1}\right)\) is:

163818 \(1 \mathbf{m o l}\) of heptane (V. \(\mathrm{P} . \mathbf{=} \mathbf{9 2} \mathrm{mm}\) of \(\mathrm{Hg}\) ) was mixed with \(4 \mathrm{~mol}\) of octane (V. P. \(=31 \mathrm{~mm}\) of \(\mathrm{Hg}\) ). The vapour pressure of resulting ideal solution is:

163819 At \(88^{\circ} \mathrm{C}\) benzene has a vapour pressure of 900 torr and toluene has a vapour pressure of 360 torr. What is the mole fraction of benzene in the mixture with toluene that will boil at \(88^{\circ} \mathrm{C}\) at 1 atm. pressure, (benzene - toluene form an ideal solution):

163820 Among the following, that does not form an ideal solution is: