162640
Which equation is correct for adiabatic process :
1 \(Q=+w\)
2 \(\Delta \mathrm{Q}=0\)
3 \(\Delta \mathrm{E}=\mathrm{Q}\)
4 \(P+\Delta V=0\)
Explanation:
There is no exchange of heat in adiabatic process so \(\Delta Q=0\)
NCERT-XI-142
3 RBTS PAPER
162641
For the precipitation of \(\mathrm{AgCl}\) by \(\mathrm{Ag}^{+}\)ions and \(\mathrm{HCl}\)
1 \(\Delta \mathrm{H}=0\)
2 \(\Delta \mathrm{G}=0\)
3 \(\Delta \mathrm{G}=-\mathrm{ve}\)
4 \(\Delta \mathrm{H}=\Delta \mathrm{G}\)
Explanation:
\(\mathrm{Ag}^{+}+\mathrm{HCl}(\mathrm{aq}) \longrightarrow \mathrm{AgCl}(\mathrm{s}) \downarrow\) It is a spontaneous process so, \(\Delta \mathrm{G}=-\mathrm{ve}\).
NCERT-XI-157
3 RBTS PAPER
162642
Hess law is used to calculate :
1 enthalpy of reaction
2 entropy of reaction
3 work done in reaction
4 all of these
Explanation:
Hess law is used to calculate enthalpy of reaction
NCERT-XI-151
3 RBTS PAPER
162643
The process of evaporation of a liquid is accompanied by :
1 Increase in enthalpy
2 Decrease in free energy
3 Increase in entropy
4 All
Explanation:
Evaporation of liquid is endothermic process and we know entropy of gas is more than liquid. Also overall process is feasible in nature So, \(\Delta \mathrm{H}=+\mathrm{ve}, \Delta \mathrm{S}=+\mathrm{ve}, \Delta \mathrm{G}=-\mathrm{ve}\).
162640
Which equation is correct for adiabatic process :
1 \(Q=+w\)
2 \(\Delta \mathrm{Q}=0\)
3 \(\Delta \mathrm{E}=\mathrm{Q}\)
4 \(P+\Delta V=0\)
Explanation:
There is no exchange of heat in adiabatic process so \(\Delta Q=0\)
NCERT-XI-142
3 RBTS PAPER
162641
For the precipitation of \(\mathrm{AgCl}\) by \(\mathrm{Ag}^{+}\)ions and \(\mathrm{HCl}\)
1 \(\Delta \mathrm{H}=0\)
2 \(\Delta \mathrm{G}=0\)
3 \(\Delta \mathrm{G}=-\mathrm{ve}\)
4 \(\Delta \mathrm{H}=\Delta \mathrm{G}\)
Explanation:
\(\mathrm{Ag}^{+}+\mathrm{HCl}(\mathrm{aq}) \longrightarrow \mathrm{AgCl}(\mathrm{s}) \downarrow\) It is a spontaneous process so, \(\Delta \mathrm{G}=-\mathrm{ve}\).
NCERT-XI-157
3 RBTS PAPER
162642
Hess law is used to calculate :
1 enthalpy of reaction
2 entropy of reaction
3 work done in reaction
4 all of these
Explanation:
Hess law is used to calculate enthalpy of reaction
NCERT-XI-151
3 RBTS PAPER
162643
The process of evaporation of a liquid is accompanied by :
1 Increase in enthalpy
2 Decrease in free energy
3 Increase in entropy
4 All
Explanation:
Evaporation of liquid is endothermic process and we know entropy of gas is more than liquid. Also overall process is feasible in nature So, \(\Delta \mathrm{H}=+\mathrm{ve}, \Delta \mathrm{S}=+\mathrm{ve}, \Delta \mathrm{G}=-\mathrm{ve}\).
162640
Which equation is correct for adiabatic process :
1 \(Q=+w\)
2 \(\Delta \mathrm{Q}=0\)
3 \(\Delta \mathrm{E}=\mathrm{Q}\)
4 \(P+\Delta V=0\)
Explanation:
There is no exchange of heat in adiabatic process so \(\Delta Q=0\)
NCERT-XI-142
3 RBTS PAPER
162641
For the precipitation of \(\mathrm{AgCl}\) by \(\mathrm{Ag}^{+}\)ions and \(\mathrm{HCl}\)
1 \(\Delta \mathrm{H}=0\)
2 \(\Delta \mathrm{G}=0\)
3 \(\Delta \mathrm{G}=-\mathrm{ve}\)
4 \(\Delta \mathrm{H}=\Delta \mathrm{G}\)
Explanation:
\(\mathrm{Ag}^{+}+\mathrm{HCl}(\mathrm{aq}) \longrightarrow \mathrm{AgCl}(\mathrm{s}) \downarrow\) It is a spontaneous process so, \(\Delta \mathrm{G}=-\mathrm{ve}\).
NCERT-XI-157
3 RBTS PAPER
162642
Hess law is used to calculate :
1 enthalpy of reaction
2 entropy of reaction
3 work done in reaction
4 all of these
Explanation:
Hess law is used to calculate enthalpy of reaction
NCERT-XI-151
3 RBTS PAPER
162643
The process of evaporation of a liquid is accompanied by :
1 Increase in enthalpy
2 Decrease in free energy
3 Increase in entropy
4 All
Explanation:
Evaporation of liquid is endothermic process and we know entropy of gas is more than liquid. Also overall process is feasible in nature So, \(\Delta \mathrm{H}=+\mathrm{ve}, \Delta \mathrm{S}=+\mathrm{ve}, \Delta \mathrm{G}=-\mathrm{ve}\).
162640
Which equation is correct for adiabatic process :
1 \(Q=+w\)
2 \(\Delta \mathrm{Q}=0\)
3 \(\Delta \mathrm{E}=\mathrm{Q}\)
4 \(P+\Delta V=0\)
Explanation:
There is no exchange of heat in adiabatic process so \(\Delta Q=0\)
NCERT-XI-142
3 RBTS PAPER
162641
For the precipitation of \(\mathrm{AgCl}\) by \(\mathrm{Ag}^{+}\)ions and \(\mathrm{HCl}\)
1 \(\Delta \mathrm{H}=0\)
2 \(\Delta \mathrm{G}=0\)
3 \(\Delta \mathrm{G}=-\mathrm{ve}\)
4 \(\Delta \mathrm{H}=\Delta \mathrm{G}\)
Explanation:
\(\mathrm{Ag}^{+}+\mathrm{HCl}(\mathrm{aq}) \longrightarrow \mathrm{AgCl}(\mathrm{s}) \downarrow\) It is a spontaneous process so, \(\Delta \mathrm{G}=-\mathrm{ve}\).
NCERT-XI-157
3 RBTS PAPER
162642
Hess law is used to calculate :
1 enthalpy of reaction
2 entropy of reaction
3 work done in reaction
4 all of these
Explanation:
Hess law is used to calculate enthalpy of reaction
NCERT-XI-151
3 RBTS PAPER
162643
The process of evaporation of a liquid is accompanied by :
1 Increase in enthalpy
2 Decrease in free energy
3 Increase in entropy
4 All
Explanation:
Evaporation of liquid is endothermic process and we know entropy of gas is more than liquid. Also overall process is feasible in nature So, \(\Delta \mathrm{H}=+\mathrm{ve}, \Delta \mathrm{S}=+\mathrm{ve}, \Delta \mathrm{G}=-\mathrm{ve}\).
