NEET Test Series from KOTA - 10 Papers In MS WORD
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Semiconductor Electronics Material Devices and Simple Circuits
151371 For the given logic circuit, the output \(Y\) for inputs \((A=0, B=1)\) and \((A=0, B=0)\) respectively are
1 \((0,0)\)
2 \((0,1)\)
3 \((1,0)\)
4 \((1,1)\)
Explanation:
C If input \(A=0, B=1\) \(\therefore \quad \mathrm{Y}_1=\mathrm{A} . \mathrm{B}\) \(\quad\)\(\mathrm{Y}=0 \times 0=0\) \(\quad\)\(\mathrm{Y}_2=\mathrm{A} \cdot \mathrm{B}=1 \times 1=1\) \(\quad\)\(\mathrm{Y}=\mathrm{Y}_1+\mathrm{Y}_2\) \(\quad\)\(\mathrm{Y}=0+1=1\) \(\quad\)\(\mathrm{Y}=1\) For input \(\mathrm{A}=0, \mathrm{~B}=0\) \(\quad\)\(\mathrm{Y}_1=\mathrm{A} \cdot \mathrm{B}=0.1=0\) \(\quad\)\(\mathrm{Y}_2=\mathrm{A} \cdot \mathrm{B}=1.0=0\) \(\therefore \quad \mathrm{Y}=\mathrm{Y}_1+\mathrm{Y}_2=0+0=0\) Hence, the output is \((1,0)\)
WB JEE 2021
Semiconductor Electronics Material Devices and Simple Circuits
151373
In the circuit shown, inputs \(A\) and \(B\) are in states 1 and 0 respectively. What is the only possible stable state of the outputs \(X\) and \(Y\) ?
1 \(X=1, Y=1\)
2 \(X=1, Y=0\)
3 \(X=0, Y=1\)
4 \(\mathrm{X}=0, \mathrm{Y}=0\)
Explanation:
C Given that, \(\mathrm{A}=1, \mathrm{~B}=0\) Let, \(\mathrm{X}=0 \text { then } \mathrm{Y}=\overline{\mathrm{X} . \mathrm{B}}=\overline{0.0}=\overline{0}=1\)the possible stable state of output \(\mathrm{x}\) and \(\mathrm{y}\) respectively are 0,1 .
WB JEE 2018
Semiconductor Electronics Material Devices and Simple Circuits
151374 In the given circuit, the binary inputs at \(A\) and \(B\) are both 1 in one case and both 0 in the next case. The respective outputs at \(Y\) in these two cases will be
Semiconductor Electronics Material Devices and Simple Circuits
151371 For the given logic circuit, the output \(Y\) for inputs \((A=0, B=1)\) and \((A=0, B=0)\) respectively are
1 \((0,0)\)
2 \((0,1)\)
3 \((1,0)\)
4 \((1,1)\)
Explanation:
C If input \(A=0, B=1\) \(\therefore \quad \mathrm{Y}_1=\mathrm{A} . \mathrm{B}\) \(\quad\)\(\mathrm{Y}=0 \times 0=0\) \(\quad\)\(\mathrm{Y}_2=\mathrm{A} \cdot \mathrm{B}=1 \times 1=1\) \(\quad\)\(\mathrm{Y}=\mathrm{Y}_1+\mathrm{Y}_2\) \(\quad\)\(\mathrm{Y}=0+1=1\) \(\quad\)\(\mathrm{Y}=1\) For input \(\mathrm{A}=0, \mathrm{~B}=0\) \(\quad\)\(\mathrm{Y}_1=\mathrm{A} \cdot \mathrm{B}=0.1=0\) \(\quad\)\(\mathrm{Y}_2=\mathrm{A} \cdot \mathrm{B}=1.0=0\) \(\therefore \quad \mathrm{Y}=\mathrm{Y}_1+\mathrm{Y}_2=0+0=0\) Hence, the output is \((1,0)\)
WB JEE 2021
Semiconductor Electronics Material Devices and Simple Circuits
151373
In the circuit shown, inputs \(A\) and \(B\) are in states 1 and 0 respectively. What is the only possible stable state of the outputs \(X\) and \(Y\) ?
1 \(X=1, Y=1\)
2 \(X=1, Y=0\)
3 \(X=0, Y=1\)
4 \(\mathrm{X}=0, \mathrm{Y}=0\)
Explanation:
C Given that, \(\mathrm{A}=1, \mathrm{~B}=0\) Let, \(\mathrm{X}=0 \text { then } \mathrm{Y}=\overline{\mathrm{X} . \mathrm{B}}=\overline{0.0}=\overline{0}=1\)the possible stable state of output \(\mathrm{x}\) and \(\mathrm{y}\) respectively are 0,1 .
WB JEE 2018
Semiconductor Electronics Material Devices and Simple Circuits
151374 In the given circuit, the binary inputs at \(A\) and \(B\) are both 1 in one case and both 0 in the next case. The respective outputs at \(Y\) in these two cases will be
Semiconductor Electronics Material Devices and Simple Circuits
151371 For the given logic circuit, the output \(Y\) for inputs \((A=0, B=1)\) and \((A=0, B=0)\) respectively are
1 \((0,0)\)
2 \((0,1)\)
3 \((1,0)\)
4 \((1,1)\)
Explanation:
C If input \(A=0, B=1\) \(\therefore \quad \mathrm{Y}_1=\mathrm{A} . \mathrm{B}\) \(\quad\)\(\mathrm{Y}=0 \times 0=0\) \(\quad\)\(\mathrm{Y}_2=\mathrm{A} \cdot \mathrm{B}=1 \times 1=1\) \(\quad\)\(\mathrm{Y}=\mathrm{Y}_1+\mathrm{Y}_2\) \(\quad\)\(\mathrm{Y}=0+1=1\) \(\quad\)\(\mathrm{Y}=1\) For input \(\mathrm{A}=0, \mathrm{~B}=0\) \(\quad\)\(\mathrm{Y}_1=\mathrm{A} \cdot \mathrm{B}=0.1=0\) \(\quad\)\(\mathrm{Y}_2=\mathrm{A} \cdot \mathrm{B}=1.0=0\) \(\therefore \quad \mathrm{Y}=\mathrm{Y}_1+\mathrm{Y}_2=0+0=0\) Hence, the output is \((1,0)\)
WB JEE 2021
Semiconductor Electronics Material Devices and Simple Circuits
151373
In the circuit shown, inputs \(A\) and \(B\) are in states 1 and 0 respectively. What is the only possible stable state of the outputs \(X\) and \(Y\) ?
1 \(X=1, Y=1\)
2 \(X=1, Y=0\)
3 \(X=0, Y=1\)
4 \(\mathrm{X}=0, \mathrm{Y}=0\)
Explanation:
C Given that, \(\mathrm{A}=1, \mathrm{~B}=0\) Let, \(\mathrm{X}=0 \text { then } \mathrm{Y}=\overline{\mathrm{X} . \mathrm{B}}=\overline{0.0}=\overline{0}=1\)the possible stable state of output \(\mathrm{x}\) and \(\mathrm{y}\) respectively are 0,1 .
WB JEE 2018
Semiconductor Electronics Material Devices and Simple Circuits
151374 In the given circuit, the binary inputs at \(A\) and \(B\) are both 1 in one case and both 0 in the next case. The respective outputs at \(Y\) in these two cases will be
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Semiconductor Electronics Material Devices and Simple Circuits
151371 For the given logic circuit, the output \(Y\) for inputs \((A=0, B=1)\) and \((A=0, B=0)\) respectively are
1 \((0,0)\)
2 \((0,1)\)
3 \((1,0)\)
4 \((1,1)\)
Explanation:
C If input \(A=0, B=1\) \(\therefore \quad \mathrm{Y}_1=\mathrm{A} . \mathrm{B}\) \(\quad\)\(\mathrm{Y}=0 \times 0=0\) \(\quad\)\(\mathrm{Y}_2=\mathrm{A} \cdot \mathrm{B}=1 \times 1=1\) \(\quad\)\(\mathrm{Y}=\mathrm{Y}_1+\mathrm{Y}_2\) \(\quad\)\(\mathrm{Y}=0+1=1\) \(\quad\)\(\mathrm{Y}=1\) For input \(\mathrm{A}=0, \mathrm{~B}=0\) \(\quad\)\(\mathrm{Y}_1=\mathrm{A} \cdot \mathrm{B}=0.1=0\) \(\quad\)\(\mathrm{Y}_2=\mathrm{A} \cdot \mathrm{B}=1.0=0\) \(\therefore \quad \mathrm{Y}=\mathrm{Y}_1+\mathrm{Y}_2=0+0=0\) Hence, the output is \((1,0)\)
WB JEE 2021
Semiconductor Electronics Material Devices and Simple Circuits
151373
In the circuit shown, inputs \(A\) and \(B\) are in states 1 and 0 respectively. What is the only possible stable state of the outputs \(X\) and \(Y\) ?
1 \(X=1, Y=1\)
2 \(X=1, Y=0\)
3 \(X=0, Y=1\)
4 \(\mathrm{X}=0, \mathrm{Y}=0\)
Explanation:
C Given that, \(\mathrm{A}=1, \mathrm{~B}=0\) Let, \(\mathrm{X}=0 \text { then } \mathrm{Y}=\overline{\mathrm{X} . \mathrm{B}}=\overline{0.0}=\overline{0}=1\)the possible stable state of output \(\mathrm{x}\) and \(\mathrm{y}\) respectively are 0,1 .
WB JEE 2018
Semiconductor Electronics Material Devices and Simple Circuits
151374 In the given circuit, the binary inputs at \(A\) and \(B\) are both 1 in one case and both 0 in the next case. The respective outputs at \(Y\) in these two cases will be
