147957 Nucleus $A$ is having mass number 220 and its binding energy per nucleon is $5.6 \mathrm{MeV}$. It splits in two fragments ' $B$ ' and ' $C$ ' of mass numbers 105. and 115. The binding energy of nucleons in ' $B$ ' and ' $C$ ' is $6.4 \mathrm{MeV}$ per nucleon. The energy $Q$ released per fission will be:

147958 What will be the energy released in joule, in the process of fission by $1 \mathrm{mg}$ of ${ }_{92}^{240} \mathrm{U}$. Assume energy release per fission is $200 \mathrm{MeV}$.
[use Avogadro's number as $6 \times 10^{23}$ and $\left.\mathrm{leV}=1.6 \times 10^{-19} \mathrm{~J}\right]$

147961 $200 \mathrm{MeV}$ energy is released when one nucleus of ${ }^{235} \mathrm{U}$ undergoes fission. The approximate energy released by fission of $\mathbf{2} \mathbf{~ k g}$ of uranium is

147963 A photon creates a pair of electron- positron with equal kinetic energy. Let kinetic energy of each particle is $0.29 \mathrm{Me} \mathrm{V}$. Then what should be energy of the photon?

147966 How many neutrons will produced for a given following nuclear fission reaction?
${ }_{0} \mathbf{n}^{1}+{ }_{92} \mathbf{U}^{235} \rightarrow{ }_{56} \mathbf{B a}^{144}+{ }_{36} \mathbf{k r}^{89}+\mathbf{x}_{0} \mathbf{n}^{1}$

147957 Nucleus $A$ is having mass number 220 and its binding energy per nucleon is $5.6 \mathrm{MeV}$. It splits in two fragments ' $B$ ' and ' $C$ ' of mass numbers 105. and 115. The binding energy of nucleons in ' $B$ ' and ' $C$ ' is $6.4 \mathrm{MeV}$ per nucleon. The energy $Q$ released per fission will be:

147958 What will be the energy released in joule, in the process of fission by $1 \mathrm{mg}$ of ${ }_{92}^{240} \mathrm{U}$. Assume energy release per fission is $200 \mathrm{MeV}$.
[use Avogadro's number as $6 \times 10^{23}$ and $\left.\mathrm{leV}=1.6 \times 10^{-19} \mathrm{~J}\right]$

147961 $200 \mathrm{MeV}$ energy is released when one nucleus of ${ }^{235} \mathrm{U}$ undergoes fission. The approximate energy released by fission of $\mathbf{2} \mathbf{~ k g}$ of uranium is

147963 A photon creates a pair of electron- positron with equal kinetic energy. Let kinetic energy of each particle is $0.29 \mathrm{Me} \mathrm{V}$. Then what should be energy of the photon?

147966 How many neutrons will produced for a given following nuclear fission reaction?
${ }_{0} \mathbf{n}^{1}+{ }_{92} \mathbf{U}^{235} \rightarrow{ }_{56} \mathbf{B a}^{144}+{ }_{36} \mathbf{k r}^{89}+\mathbf{x}_{0} \mathbf{n}^{1}$

147957 Nucleus $A$ is having mass number 220 and its binding energy per nucleon is $5.6 \mathrm{MeV}$. It splits in two fragments ' $B$ ' and ' $C$ ' of mass numbers 105. and 115. The binding energy of nucleons in ' $B$ ' and ' $C$ ' is $6.4 \mathrm{MeV}$ per nucleon. The energy $Q$ released per fission will be:

147958 What will be the energy released in joule, in the process of fission by $1 \mathrm{mg}$ of ${ }_{92}^{240} \mathrm{U}$. Assume energy release per fission is $200 \mathrm{MeV}$.
[use Avogadro's number as $6 \times 10^{23}$ and $\left.\mathrm{leV}=1.6 \times 10^{-19} \mathrm{~J}\right]$

147961 $200 \mathrm{MeV}$ energy is released when one nucleus of ${ }^{235} \mathrm{U}$ undergoes fission. The approximate energy released by fission of $\mathbf{2} \mathbf{~ k g}$ of uranium is

147963 A photon creates a pair of electron- positron with equal kinetic energy. Let kinetic energy of each particle is $0.29 \mathrm{Me} \mathrm{V}$. Then what should be energy of the photon?

147966 How many neutrons will produced for a given following nuclear fission reaction?
${ }_{0} \mathbf{n}^{1}+{ }_{92} \mathbf{U}^{235} \rightarrow{ }_{56} \mathbf{B a}^{144}+{ }_{36} \mathbf{k r}^{89}+\mathbf{x}_{0} \mathbf{n}^{1}$

147957 Nucleus $A$ is having mass number 220 and its binding energy per nucleon is $5.6 \mathrm{MeV}$. It splits in two fragments ' $B$ ' and ' $C$ ' of mass numbers 105. and 115. The binding energy of nucleons in ' $B$ ' and ' $C$ ' is $6.4 \mathrm{MeV}$ per nucleon. The energy $Q$ released per fission will be:

147958 What will be the energy released in joule, in the process of fission by $1 \mathrm{mg}$ of ${ }_{92}^{240} \mathrm{U}$. Assume energy release per fission is $200 \mathrm{MeV}$.
[use Avogadro's number as $6 \times 10^{23}$ and $\left.\mathrm{leV}=1.6 \times 10^{-19} \mathrm{~J}\right]$

147961 $200 \mathrm{MeV}$ energy is released when one nucleus of ${ }^{235} \mathrm{U}$ undergoes fission. The approximate energy released by fission of $\mathbf{2} \mathbf{~ k g}$ of uranium is

147963 A photon creates a pair of electron- positron with equal kinetic energy. Let kinetic energy of each particle is $0.29 \mathrm{Me} \mathrm{V}$. Then what should be energy of the photon?

147966 How many neutrons will produced for a given following nuclear fission reaction?
${ }_{0} \mathbf{n}^{1}+{ }_{92} \mathbf{U}^{235} \rightarrow{ }_{56} \mathbf{B a}^{144}+{ }_{36} \mathbf{k r}^{89}+\mathbf{x}_{0} \mathbf{n}^{1}$

147957 Nucleus $A$ is having mass number 220 and its binding energy per nucleon is $5.6 \mathrm{MeV}$. It splits in two fragments ' $B$ ' and ' $C$ ' of mass numbers 105. and 115. The binding energy of nucleons in ' $B$ ' and ' $C$ ' is $6.4 \mathrm{MeV}$ per nucleon. The energy $Q$ released per fission will be:

147958 What will be the energy released in joule, in the process of fission by $1 \mathrm{mg}$ of ${ }_{92}^{240} \mathrm{U}$. Assume energy release per fission is $200 \mathrm{MeV}$.
[use Avogadro's number as $6 \times 10^{23}$ and $\left.\mathrm{leV}=1.6 \times 10^{-19} \mathrm{~J}\right]$

147961 $200 \mathrm{MeV}$ energy is released when one nucleus of ${ }^{235} \mathrm{U}$ undergoes fission. The approximate energy released by fission of $\mathbf{2} \mathbf{~ k g}$ of uranium is

147963 A photon creates a pair of electron- positron with equal kinetic energy. Let kinetic energy of each particle is $0.29 \mathrm{Me} \mathrm{V}$. Then what should be energy of the photon?

147966 How many neutrons will produced for a given following nuclear fission reaction?
${ }_{0} \mathbf{n}^{1}+{ }_{92} \mathbf{U}^{235} \rightarrow{ }_{56} \mathbf{B a}^{144}+{ }_{36} \mathbf{k r}^{89}+\mathbf{x}_{0} \mathbf{n}^{1}$