Capacitance
Capacitance

165614 The $90 \mathrm{pF}$ capacitor is connected to a $12 \mathrm{~V}$ battery. How many electrons are transferred from one plate to another?

1 $1.1 \times 10^{9}$
2 $6.7 \times 10^{9}$
3 $4 \times 10^{19}$
4 $5 \times 10^{19}$
Capacitance

165615 A $6 \times 10^{-4} \mathrm{~F}$ parallel plate air capacitor is connected to a $500 \mathrm{~V}$ battery. When air is replaced by another dielectric material, $7.5 \times 10^{-}$ ${ }^{4} \mathrm{C}$ charge flows into the capacitor. The value of the dielectric constant of the material is-

1 1.5
2 2.0
3 1.0025
4 3.5
Capacitance

165616 The numerical value of charge on either plate of capacitor $C$ shown in figure-

1 $\mathrm{CE}$
2 $\frac{\mathrm{CER}_{1}}{\mathrm{R}_{1}+\mathrm{r}}$
3 $\frac{\mathrm{CER}_{2}}{\mathrm{R}_{2}+\mathrm{r}}$
4 $\frac{\mathrm{CER}_{1}}{\mathrm{R}_{2}+\mathrm{r}}$
Capacitance

165617 In a parallel plate air capacitor the distance between plates is reduced to one forth and the space between them is filled with a dielectric medium of constant 2 . If the initial capacity of the capacitor is $4 \mu \mathrm{F}$, then its new capacity is

1 $8 \mu \mathrm{F}$
2 $18 \mu \mathrm{F}$
3 $44 \mu \mathrm{F}$
4 $32 \mu \mathrm{F}$
Capacitance

165614 The $90 \mathrm{pF}$ capacitor is connected to a $12 \mathrm{~V}$ battery. How many electrons are transferred from one plate to another?

1 $1.1 \times 10^{9}$
2 $6.7 \times 10^{9}$
3 $4 \times 10^{19}$
4 $5 \times 10^{19}$
Capacitance

165615 A $6 \times 10^{-4} \mathrm{~F}$ parallel plate air capacitor is connected to a $500 \mathrm{~V}$ battery. When air is replaced by another dielectric material, $7.5 \times 10^{-}$ ${ }^{4} \mathrm{C}$ charge flows into the capacitor. The value of the dielectric constant of the material is-

1 1.5
2 2.0
3 1.0025
4 3.5
Capacitance

165616 The numerical value of charge on either plate of capacitor $C$ shown in figure-

1 $\mathrm{CE}$
2 $\frac{\mathrm{CER}_{1}}{\mathrm{R}_{1}+\mathrm{r}}$
3 $\frac{\mathrm{CER}_{2}}{\mathrm{R}_{2}+\mathrm{r}}$
4 $\frac{\mathrm{CER}_{1}}{\mathrm{R}_{2}+\mathrm{r}}$
Capacitance

165617 In a parallel plate air capacitor the distance between plates is reduced to one forth and the space between them is filled with a dielectric medium of constant 2 . If the initial capacity of the capacitor is $4 \mu \mathrm{F}$, then its new capacity is

1 $8 \mu \mathrm{F}$
2 $18 \mu \mathrm{F}$
3 $44 \mu \mathrm{F}$
4 $32 \mu \mathrm{F}$
Capacitance

165614 The $90 \mathrm{pF}$ capacitor is connected to a $12 \mathrm{~V}$ battery. How many electrons are transferred from one plate to another?

1 $1.1 \times 10^{9}$
2 $6.7 \times 10^{9}$
3 $4 \times 10^{19}$
4 $5 \times 10^{19}$
Capacitance

165615 A $6 \times 10^{-4} \mathrm{~F}$ parallel plate air capacitor is connected to a $500 \mathrm{~V}$ battery. When air is replaced by another dielectric material, $7.5 \times 10^{-}$ ${ }^{4} \mathrm{C}$ charge flows into the capacitor. The value of the dielectric constant of the material is-

1 1.5
2 2.0
3 1.0025
4 3.5
Capacitance

165616 The numerical value of charge on either plate of capacitor $C$ shown in figure-

1 $\mathrm{CE}$
2 $\frac{\mathrm{CER}_{1}}{\mathrm{R}_{1}+\mathrm{r}}$
3 $\frac{\mathrm{CER}_{2}}{\mathrm{R}_{2}+\mathrm{r}}$
4 $\frac{\mathrm{CER}_{1}}{\mathrm{R}_{2}+\mathrm{r}}$
Capacitance

165617 In a parallel plate air capacitor the distance between plates is reduced to one forth and the space between them is filled with a dielectric medium of constant 2 . If the initial capacity of the capacitor is $4 \mu \mathrm{F}$, then its new capacity is

1 $8 \mu \mathrm{F}$
2 $18 \mu \mathrm{F}$
3 $44 \mu \mathrm{F}$
4 $32 \mu \mathrm{F}$
Capacitance

165614 The $90 \mathrm{pF}$ capacitor is connected to a $12 \mathrm{~V}$ battery. How many electrons are transferred from one plate to another?

1 $1.1 \times 10^{9}$
2 $6.7 \times 10^{9}$
3 $4 \times 10^{19}$
4 $5 \times 10^{19}$
Capacitance

165615 A $6 \times 10^{-4} \mathrm{~F}$ parallel plate air capacitor is connected to a $500 \mathrm{~V}$ battery. When air is replaced by another dielectric material, $7.5 \times 10^{-}$ ${ }^{4} \mathrm{C}$ charge flows into the capacitor. The value of the dielectric constant of the material is-

1 1.5
2 2.0
3 1.0025
4 3.5
Capacitance

165616 The numerical value of charge on either plate of capacitor $C$ shown in figure-

1 $\mathrm{CE}$
2 $\frac{\mathrm{CER}_{1}}{\mathrm{R}_{1}+\mathrm{r}}$
3 $\frac{\mathrm{CER}_{2}}{\mathrm{R}_{2}+\mathrm{r}}$
4 $\frac{\mathrm{CER}_{1}}{\mathrm{R}_{2}+\mathrm{r}}$
Capacitance

165617 In a parallel plate air capacitor the distance between plates is reduced to one forth and the space between them is filled with a dielectric medium of constant 2 . If the initial capacity of the capacitor is $4 \mu \mathrm{F}$, then its new capacity is

1 $8 \mu \mathrm{F}$
2 $18 \mu \mathrm{F}$
3 $44 \mu \mathrm{F}$
4 $32 \mu \mathrm{F}$