172557 A cylindrical tube open at both ends has a fundamental frequency ' $f$ ' in air. The tube is dipped vertically in water so that half of it is in water. The new fundamental frequency is

172558 An open air pipe of length \(80 \mathrm{~cm}\) has the second harmonic frequency equal to the fundamental frequency of a closed organ air pipe. The length of the closed pipe is-

172559 If $\lambda_{1}, \lambda_{2}, \lambda_{3}$ are the wavelengths of the waves giving resonance with the fundamental, first, second overtones respectively of a closed organ pipe, then the ratio $\lambda_{1}: \lambda_{2}: \lambda_{3}=$

172560 The frequency of a tuning fork is $220 \mathrm{~Hz}$ and the velocity of sound in air is $330 \mathrm{~m} / \mathrm{s}$. When the tuning fork completes 80 vibrations, the distance travelled by the

172561 An organ pipe with both ends open has a length $L=25 \mathrm{~cm}$. An extra hole is created at position $\frac{L}{2}$. The lowest frequency of sound produced is (assume, speed of sound $=\mathbf{3 4 0} \mathrm{m} / \mathrm{s}$ )

172557 A cylindrical tube open at both ends has a fundamental frequency ' $f$ ' in air. The tube is dipped vertically in water so that half of it is in water. The new fundamental frequency is

172558 An open air pipe of length \(80 \mathrm{~cm}\) has the second harmonic frequency equal to the fundamental frequency of a closed organ air pipe. The length of the closed pipe is-

172559 If $\lambda_{1}, \lambda_{2}, \lambda_{3}$ are the wavelengths of the waves giving resonance with the fundamental, first, second overtones respectively of a closed organ pipe, then the ratio $\lambda_{1}: \lambda_{2}: \lambda_{3}=$

172560 The frequency of a tuning fork is $220 \mathrm{~Hz}$ and the velocity of sound in air is $330 \mathrm{~m} / \mathrm{s}$. When the tuning fork completes 80 vibrations, the distance travelled by the

172561 An organ pipe with both ends open has a length $L=25 \mathrm{~cm}$. An extra hole is created at position $\frac{L}{2}$. The lowest frequency of sound produced is (assume, speed of sound $=\mathbf{3 4 0} \mathrm{m} / \mathrm{s}$ )

172557 A cylindrical tube open at both ends has a fundamental frequency ' $f$ ' in air. The tube is dipped vertically in water so that half of it is in water. The new fundamental frequency is

172558 An open air pipe of length \(80 \mathrm{~cm}\) has the second harmonic frequency equal to the fundamental frequency of a closed organ air pipe. The length of the closed pipe is-

172559 If $\lambda_{1}, \lambda_{2}, \lambda_{3}$ are the wavelengths of the waves giving resonance with the fundamental, first, second overtones respectively of a closed organ pipe, then the ratio $\lambda_{1}: \lambda_{2}: \lambda_{3}=$

172560 The frequency of a tuning fork is $220 \mathrm{~Hz}$ and the velocity of sound in air is $330 \mathrm{~m} / \mathrm{s}$. When the tuning fork completes 80 vibrations, the distance travelled by the

172561 An organ pipe with both ends open has a length $L=25 \mathrm{~cm}$. An extra hole is created at position $\frac{L}{2}$. The lowest frequency of sound produced is (assume, speed of sound $=\mathbf{3 4 0} \mathrm{m} / \mathrm{s}$ )

172557 A cylindrical tube open at both ends has a fundamental frequency ' $f$ ' in air. The tube is dipped vertically in water so that half of it is in water. The new fundamental frequency is

172558 An open air pipe of length \(80 \mathrm{~cm}\) has the second harmonic frequency equal to the fundamental frequency of a closed organ air pipe. The length of the closed pipe is-

172559 If $\lambda_{1}, \lambda_{2}, \lambda_{3}$ are the wavelengths of the waves giving resonance with the fundamental, first, second overtones respectively of a closed organ pipe, then the ratio $\lambda_{1}: \lambda_{2}: \lambda_{3}=$

172560 The frequency of a tuning fork is $220 \mathrm{~Hz}$ and the velocity of sound in air is $330 \mathrm{~m} / \mathrm{s}$. When the tuning fork completes 80 vibrations, the distance travelled by the

172561 An organ pipe with both ends open has a length $L=25 \mathrm{~cm}$. An extra hole is created at position $\frac{L}{2}$. The lowest frequency of sound produced is (assume, speed of sound $=\mathbf{3 4 0} \mathrm{m} / \mathrm{s}$ )

172557 A cylindrical tube open at both ends has a fundamental frequency ' $f$ ' in air. The tube is dipped vertically in water so that half of it is in water. The new fundamental frequency is

172558 An open air pipe of length \(80 \mathrm{~cm}\) has the second harmonic frequency equal to the fundamental frequency of a closed organ air pipe. The length of the closed pipe is-

172559 If $\lambda_{1}, \lambda_{2}, \lambda_{3}$ are the wavelengths of the waves giving resonance with the fundamental, first, second overtones respectively of a closed organ pipe, then the ratio $\lambda_{1}: \lambda_{2}: \lambda_{3}=$

172560 The frequency of a tuning fork is $220 \mathrm{~Hz}$ and the velocity of sound in air is $330 \mathrm{~m} / \mathrm{s}$. When the tuning fork completes 80 vibrations, the distance travelled by the

172561 An organ pipe with both ends open has a length $L=25 \mathrm{~cm}$. An extra hole is created at position $\frac{L}{2}$. The lowest frequency of sound produced is (assume, speed of sound $=\mathbf{3 4 0} \mathrm{m} / \mathrm{s}$ )