Reflection of Waves Strings
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NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
WAVES

172397 A string of length $1 \mathrm{~m}$ and mass $490 \mathrm{~g}$ is put under a tension of $25 \mathrm{~N}$. A wave of frequency $120 \mathrm{~Hz}$ is sent along it. The speed of this wave is

1 $7.14 \mathrm{~ms}^{-1}$
2 $0.71 \mathrm{~ms}^{-1}$
3 $0.51 \mathrm{~ms}^{-1}$
4 $51.0 \mathrm{~ms}^{-1}$
AP EAMCET-06.07.2022
WAVES

172398 A wire of length $0.4 \mathrm{~m}$ stretched at both ends vibrates 250 times per second. If the length of the wire is increased by $0.1 \mathrm{~m}$ and the stretching force is reduced to $1 / 4^{\text {th }}$ of its original value then the new frequency is

1 $50 \mathrm{~Hz}$
2 $75 \mathrm{~Hz}$
3 $100 \mathrm{~Hz}$
4 $150 \mathrm{~Hz}$
TS EAMCET 19.07.2022
WAVES

172399 Calculate the fundamental frequency of a sonometer wire of length $=20 \mathrm{~cm}$, tension $25 \mathrm{~N}$, cross sectional area $10^{-2} \mathrm{~cm}^{2}$ and density of the material of wire $=10^{4} \mathrm{~kg} / \mathrm{m}^{3}$

1 $75 \mathrm{~Hz}$
2 $100 \mathrm{~Hz}$
3 $125 \mathrm{~Hz}$
4 $150 \mathrm{~Hz}$
Assam CEE-31.07.2022
WAVES

172401 Phase difference between two particles of a medium lying between two consecutive nodes is

1 0
2 $\frac{\pi}{4}$
3 $\frac{\pi}{2}$
4 $\pi$
Shift-II]
NEET DIGITAL LIBRARY
WAVES

172397 A string of length $1 \mathrm{~m}$ and mass $490 \mathrm{~g}$ is put under a tension of $25 \mathrm{~N}$. A wave of frequency $120 \mathrm{~Hz}$ is sent along it. The speed of this wave is

1 $7.14 \mathrm{~ms}^{-1}$
2 $0.71 \mathrm{~ms}^{-1}$
3 $0.51 \mathrm{~ms}^{-1}$
4 $51.0 \mathrm{~ms}^{-1}$
AP EAMCET-06.07.2022
WAVES

172398 A wire of length $0.4 \mathrm{~m}$ stretched at both ends vibrates 250 times per second. If the length of the wire is increased by $0.1 \mathrm{~m}$ and the stretching force is reduced to $1 / 4^{\text {th }}$ of its original value then the new frequency is

1 $50 \mathrm{~Hz}$
2 $75 \mathrm{~Hz}$
3 $100 \mathrm{~Hz}$
4 $150 \mathrm{~Hz}$
TS EAMCET 19.07.2022
WAVES

172399 Calculate the fundamental frequency of a sonometer wire of length $=20 \mathrm{~cm}$, tension $25 \mathrm{~N}$, cross sectional area $10^{-2} \mathrm{~cm}^{2}$ and density of the material of wire $=10^{4} \mathrm{~kg} / \mathrm{m}^{3}$

1 $75 \mathrm{~Hz}$
2 $100 \mathrm{~Hz}$
3 $125 \mathrm{~Hz}$
4 $150 \mathrm{~Hz}$
Assam CEE-31.07.2022
WAVES

172401 Phase difference between two particles of a medium lying between two consecutive nodes is

1 0
2 $\frac{\pi}{4}$
3 $\frac{\pi}{2}$
4 $\pi$
Shift-II]
Join With Us for More Updates
WAVES

172397 A string of length $1 \mathrm{~m}$ and mass $490 \mathrm{~g}$ is put under a tension of $25 \mathrm{~N}$. A wave of frequency $120 \mathrm{~Hz}$ is sent along it. The speed of this wave is

1 $7.14 \mathrm{~ms}^{-1}$
2 $0.71 \mathrm{~ms}^{-1}$
3 $0.51 \mathrm{~ms}^{-1}$
4 $51.0 \mathrm{~ms}^{-1}$
AP EAMCET-06.07.2022
WAVES

172398 A wire of length $0.4 \mathrm{~m}$ stretched at both ends vibrates 250 times per second. If the length of the wire is increased by $0.1 \mathrm{~m}$ and the stretching force is reduced to $1 / 4^{\text {th }}$ of its original value then the new frequency is

1 $50 \mathrm{~Hz}$
2 $75 \mathrm{~Hz}$
3 $100 \mathrm{~Hz}$
4 $150 \mathrm{~Hz}$
TS EAMCET 19.07.2022
WAVES

172399 Calculate the fundamental frequency of a sonometer wire of length $=20 \mathrm{~cm}$, tension $25 \mathrm{~N}$, cross sectional area $10^{-2} \mathrm{~cm}^{2}$ and density of the material of wire $=10^{4} \mathrm{~kg} / \mathrm{m}^{3}$

1 $75 \mathrm{~Hz}$
2 $100 \mathrm{~Hz}$
3 $125 \mathrm{~Hz}$
4 $150 \mathrm{~Hz}$
Assam CEE-31.07.2022
WAVES

172401 Phase difference between two particles of a medium lying between two consecutive nodes is

1 0
2 $\frac{\pi}{4}$
3 $\frac{\pi}{2}$
4 $\pi$
Shift-II]
For More Updates join with Us
WAVES

172397 A string of length $1 \mathrm{~m}$ and mass $490 \mathrm{~g}$ is put under a tension of $25 \mathrm{~N}$. A wave of frequency $120 \mathrm{~Hz}$ is sent along it. The speed of this wave is

1 $7.14 \mathrm{~ms}^{-1}$
2 $0.71 \mathrm{~ms}^{-1}$
3 $0.51 \mathrm{~ms}^{-1}$
4 $51.0 \mathrm{~ms}^{-1}$
AP EAMCET-06.07.2022
WAVES

172398 A wire of length $0.4 \mathrm{~m}$ stretched at both ends vibrates 250 times per second. If the length of the wire is increased by $0.1 \mathrm{~m}$ and the stretching force is reduced to $1 / 4^{\text {th }}$ of its original value then the new frequency is

1 $50 \mathrm{~Hz}$
2 $75 \mathrm{~Hz}$
3 $100 \mathrm{~Hz}$
4 $150 \mathrm{~Hz}$
TS EAMCET 19.07.2022
WAVES

172399 Calculate the fundamental frequency of a sonometer wire of length $=20 \mathrm{~cm}$, tension $25 \mathrm{~N}$, cross sectional area $10^{-2} \mathrm{~cm}^{2}$ and density of the material of wire $=10^{4} \mathrm{~kg} / \mathrm{m}^{3}$

1 $75 \mathrm{~Hz}$
2 $100 \mathrm{~Hz}$
3 $125 \mathrm{~Hz}$
4 $150 \mathrm{~Hz}$
Assam CEE-31.07.2022
WAVES

172401 Phase difference between two particles of a medium lying between two consecutive nodes is

1 0
2 $\frac{\pi}{4}$
3 $\frac{\pi}{2}$
4 $\pi$
Shift-II]
NEET DIGITAL LIBRARY