B Equation of stationary wave $\mathrm{y}=2 \mathrm{~A} \sin \omega \mathrm{t} \cdot \cos \mathrm{kx}$
AP EAMCET(Medical)-1999
WAVES
172310
Two waves of same frequency and intensity superimpose on each other in opposite phases. After the superposition, the intensity and frequency of waves will
1 increase
2 decrease
3 remain constant
4 become zero
Explanation:
D When the two waves of same frequency and intensity superimpose on each other in opposite phase destructive interference takes place. So the intensity become zero and same goes for frequency.
AIPMT-1996
WAVES
172333
A uniform rope of mass $0.1 \mathrm{~kg}$ and length 2.45 $m$ hangs from a ceiling. The time taken by a transverse wave to travel the full length of the rope is
1 $1.2 \mathrm{~s}$
2 $1.0 \mathrm{~s}$
3 $2.2 \mathrm{~s}$
4 $3.1 \mathrm{~s}$
Explanation:
B Given that $\begin{aligned} \mathrm{m}= 0.1 \mathrm{~kg} \quad l=2.45 \mathrm{~m} \\ \int_{\mathrm{o}}^{\mathrm{T}} \mathrm{dt} =\int_{0}^{l} \frac{\mathrm{dx}}{\sqrt{\mathrm{gx}}} \\ \text { Time taken }(\mathrm{T}) =2 \sqrt{\frac{l}{\mathrm{~g}}} \\ \mathrm{~T} =2 \sqrt{\frac{2.45}{9.8}} \\ \mathrm{~T} =1 \mathrm{sec}\end{aligned}$
B Equation of stationary wave $\mathrm{y}=2 \mathrm{~A} \sin \omega \mathrm{t} \cdot \cos \mathrm{kx}$
AP EAMCET(Medical)-1999
WAVES
172310
Two waves of same frequency and intensity superimpose on each other in opposite phases. After the superposition, the intensity and frequency of waves will
1 increase
2 decrease
3 remain constant
4 become zero
Explanation:
D When the two waves of same frequency and intensity superimpose on each other in opposite phase destructive interference takes place. So the intensity become zero and same goes for frequency.
AIPMT-1996
WAVES
172333
A uniform rope of mass $0.1 \mathrm{~kg}$ and length 2.45 $m$ hangs from a ceiling. The time taken by a transverse wave to travel the full length of the rope is
1 $1.2 \mathrm{~s}$
2 $1.0 \mathrm{~s}$
3 $2.2 \mathrm{~s}$
4 $3.1 \mathrm{~s}$
Explanation:
B Given that $\begin{aligned} \mathrm{m}= 0.1 \mathrm{~kg} \quad l=2.45 \mathrm{~m} \\ \int_{\mathrm{o}}^{\mathrm{T}} \mathrm{dt} =\int_{0}^{l} \frac{\mathrm{dx}}{\sqrt{\mathrm{gx}}} \\ \text { Time taken }(\mathrm{T}) =2 \sqrt{\frac{l}{\mathrm{~g}}} \\ \mathrm{~T} =2 \sqrt{\frac{2.45}{9.8}} \\ \mathrm{~T} =1 \mathrm{sec}\end{aligned}$
B Equation of stationary wave $\mathrm{y}=2 \mathrm{~A} \sin \omega \mathrm{t} \cdot \cos \mathrm{kx}$
AP EAMCET(Medical)-1999
WAVES
172310
Two waves of same frequency and intensity superimpose on each other in opposite phases. After the superposition, the intensity and frequency of waves will
1 increase
2 decrease
3 remain constant
4 become zero
Explanation:
D When the two waves of same frequency and intensity superimpose on each other in opposite phase destructive interference takes place. So the intensity become zero and same goes for frequency.
AIPMT-1996
WAVES
172333
A uniform rope of mass $0.1 \mathrm{~kg}$ and length 2.45 $m$ hangs from a ceiling. The time taken by a transverse wave to travel the full length of the rope is
1 $1.2 \mathrm{~s}$
2 $1.0 \mathrm{~s}$
3 $2.2 \mathrm{~s}$
4 $3.1 \mathrm{~s}$
Explanation:
B Given that $\begin{aligned} \mathrm{m}= 0.1 \mathrm{~kg} \quad l=2.45 \mathrm{~m} \\ \int_{\mathrm{o}}^{\mathrm{T}} \mathrm{dt} =\int_{0}^{l} \frac{\mathrm{dx}}{\sqrt{\mathrm{gx}}} \\ \text { Time taken }(\mathrm{T}) =2 \sqrt{\frac{l}{\mathrm{~g}}} \\ \mathrm{~T} =2 \sqrt{\frac{2.45}{9.8}} \\ \mathrm{~T} =1 \mathrm{sec}\end{aligned}$
B Equation of stationary wave $\mathrm{y}=2 \mathrm{~A} \sin \omega \mathrm{t} \cdot \cos \mathrm{kx}$
AP EAMCET(Medical)-1999
WAVES
172310
Two waves of same frequency and intensity superimpose on each other in opposite phases. After the superposition, the intensity and frequency of waves will
1 increase
2 decrease
3 remain constant
4 become zero
Explanation:
D When the two waves of same frequency and intensity superimpose on each other in opposite phase destructive interference takes place. So the intensity become zero and same goes for frequency.
AIPMT-1996
WAVES
172333
A uniform rope of mass $0.1 \mathrm{~kg}$ and length 2.45 $m$ hangs from a ceiling. The time taken by a transverse wave to travel the full length of the rope is
1 $1.2 \mathrm{~s}$
2 $1.0 \mathrm{~s}$
3 $2.2 \mathrm{~s}$
4 $3.1 \mathrm{~s}$
Explanation:
B Given that $\begin{aligned} \mathrm{m}= 0.1 \mathrm{~kg} \quad l=2.45 \mathrm{~m} \\ \int_{\mathrm{o}}^{\mathrm{T}} \mathrm{dt} =\int_{0}^{l} \frac{\mathrm{dx}}{\sqrt{\mathrm{gx}}} \\ \text { Time taken }(\mathrm{T}) =2 \sqrt{\frac{l}{\mathrm{~g}}} \\ \mathrm{~T} =2 \sqrt{\frac{2.45}{9.8}} \\ \mathrm{~T} =1 \mathrm{sec}\end{aligned}$