NEET Test Series from KOTA - 10 Papers In MS WORD
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WAVES
172343
When a stationary wave is formed, then its frequency is
1 same as that of the individual waves
2 twice that of the individual waves
3 half that of the individual waves
4 $\sqrt{2}$ that of the individual waves
Explanation:
A Standing or stationary wave is formed due to superposition of two progressive waves of same nature, same frequency (or same wave length) same amplitude travelling with same speed in a bounded medium in mutually opposite direction. $Y_{1}=A \sin (\omega t-k x)$ $Y_{2}=A \sin (\omega t+k x)$ $Y=Y_{1}+Y_{2}=2 A \cos k x \sin \omega t$ Thus stationary wave has same frequency same as that of individuals waves.
UPSEE - 2014
WAVES
172344
The equation $y=A \cos ^{2}\left[2 \pi n t-2 \pi \frac{x}{\lambda}\right]$ represents a wave with:
1 amplitude $\mathrm{A} / 2$, frequency $2 \mathrm{n}$ and wavelength $\lambda$
2 amplitude $\mathrm{A} / 2$, frequency $2 \mathrm{n}$ and wavelength $\lambda / 2$
3 amplitude $\mathrm{A}$, frequency $\mathrm{n}$ and wavelength $\lambda$
4 amplitude $A$, frequency $2 n$ and wavelength $2 \lambda$
Explanation:
B Given equation can be written as, $\mathrm{y}=\frac{\mathrm{A}}{2} \cos \left(4 \pi \mathrm{nt}-\frac{4 \pi \mathrm{x}}{\lambda}\right)+\frac{\mathrm{A}}{2}\left(\because \cos ^{2} \theta=\frac{1+\cos 2 \theta}{2}\right)$ $\text { So, Amplitude }=\mathrm{A} / 2$ $\text { Frequency }=\frac{\omega}{2 \pi}=\frac{4 \pi \mathrm{n}}{2 \pi}=2 \mathrm{n}$ $\text { Wave length }=\frac{2 \pi}{\mathrm{k}}=\frac{2 \pi}{\frac{4 \pi}{\lambda}}=\frac{\lambda}{2}$
Karnataka CET-2002
WAVES
172346
The angle between particle velocity and wave velocity in a transverse wave is
1 zero
2 $\pi / 4$
3 $\pi / 2$
4 $\pi$
Explanation:
C In a transverse wave the particle of the medium vibrate about their mean position in a direction perpendicular to the direction of wave propagation. Here, the particle velocity is given by $\frac{\mathrm{dy}}{\mathrm{dt}}$ and wave velocity is given by $\frac{\mathrm{dx}}{\mathrm{dt}}$. Hence, the angle between particle velocity in a transverse wave is $\frac{\pi}{2}$.
MHT-CET 2008
WAVES
172348
The relationship between phase difference $\Delta \phi$ and the path difference $\Delta x$ between two interfering waves is given by ( $\lambda=$ wavelength)
A The relation between phase difference and path difference between two interfering wave is given by- Phase difference, $\Delta \phi=\frac{2 \pi}{\lambda} \times$ path difference $(\Delta \mathrm{x})$ Phase difference, $\Delta \phi=\frac{2 \pi}{\lambda} \times \Delta x$ or $\quad \Delta \mathrm{x}=\left(\frac{\lambda}{2 \pi}\right) \times \Delta \phi$
172343
When a stationary wave is formed, then its frequency is
1 same as that of the individual waves
2 twice that of the individual waves
3 half that of the individual waves
4 $\sqrt{2}$ that of the individual waves
Explanation:
A Standing or stationary wave is formed due to superposition of two progressive waves of same nature, same frequency (or same wave length) same amplitude travelling with same speed in a bounded medium in mutually opposite direction. $Y_{1}=A \sin (\omega t-k x)$ $Y_{2}=A \sin (\omega t+k x)$ $Y=Y_{1}+Y_{2}=2 A \cos k x \sin \omega t$ Thus stationary wave has same frequency same as that of individuals waves.
UPSEE - 2014
WAVES
172344
The equation $y=A \cos ^{2}\left[2 \pi n t-2 \pi \frac{x}{\lambda}\right]$ represents a wave with:
1 amplitude $\mathrm{A} / 2$, frequency $2 \mathrm{n}$ and wavelength $\lambda$
2 amplitude $\mathrm{A} / 2$, frequency $2 \mathrm{n}$ and wavelength $\lambda / 2$
3 amplitude $\mathrm{A}$, frequency $\mathrm{n}$ and wavelength $\lambda$
4 amplitude $A$, frequency $2 n$ and wavelength $2 \lambda$
Explanation:
B Given equation can be written as, $\mathrm{y}=\frac{\mathrm{A}}{2} \cos \left(4 \pi \mathrm{nt}-\frac{4 \pi \mathrm{x}}{\lambda}\right)+\frac{\mathrm{A}}{2}\left(\because \cos ^{2} \theta=\frac{1+\cos 2 \theta}{2}\right)$ $\text { So, Amplitude }=\mathrm{A} / 2$ $\text { Frequency }=\frac{\omega}{2 \pi}=\frac{4 \pi \mathrm{n}}{2 \pi}=2 \mathrm{n}$ $\text { Wave length }=\frac{2 \pi}{\mathrm{k}}=\frac{2 \pi}{\frac{4 \pi}{\lambda}}=\frac{\lambda}{2}$
Karnataka CET-2002
WAVES
172346
The angle between particle velocity and wave velocity in a transverse wave is
1 zero
2 $\pi / 4$
3 $\pi / 2$
4 $\pi$
Explanation:
C In a transverse wave the particle of the medium vibrate about their mean position in a direction perpendicular to the direction of wave propagation. Here, the particle velocity is given by $\frac{\mathrm{dy}}{\mathrm{dt}}$ and wave velocity is given by $\frac{\mathrm{dx}}{\mathrm{dt}}$. Hence, the angle between particle velocity in a transverse wave is $\frac{\pi}{2}$.
MHT-CET 2008
WAVES
172348
The relationship between phase difference $\Delta \phi$ and the path difference $\Delta x$ between two interfering waves is given by ( $\lambda=$ wavelength)
A The relation between phase difference and path difference between two interfering wave is given by- Phase difference, $\Delta \phi=\frac{2 \pi}{\lambda} \times$ path difference $(\Delta \mathrm{x})$ Phase difference, $\Delta \phi=\frac{2 \pi}{\lambda} \times \Delta x$ or $\quad \Delta \mathrm{x}=\left(\frac{\lambda}{2 \pi}\right) \times \Delta \phi$
172343
When a stationary wave is formed, then its frequency is
1 same as that of the individual waves
2 twice that of the individual waves
3 half that of the individual waves
4 $\sqrt{2}$ that of the individual waves
Explanation:
A Standing or stationary wave is formed due to superposition of two progressive waves of same nature, same frequency (or same wave length) same amplitude travelling with same speed in a bounded medium in mutually opposite direction. $Y_{1}=A \sin (\omega t-k x)$ $Y_{2}=A \sin (\omega t+k x)$ $Y=Y_{1}+Y_{2}=2 A \cos k x \sin \omega t$ Thus stationary wave has same frequency same as that of individuals waves.
UPSEE - 2014
WAVES
172344
The equation $y=A \cos ^{2}\left[2 \pi n t-2 \pi \frac{x}{\lambda}\right]$ represents a wave with:
1 amplitude $\mathrm{A} / 2$, frequency $2 \mathrm{n}$ and wavelength $\lambda$
2 amplitude $\mathrm{A} / 2$, frequency $2 \mathrm{n}$ and wavelength $\lambda / 2$
3 amplitude $\mathrm{A}$, frequency $\mathrm{n}$ and wavelength $\lambda$
4 amplitude $A$, frequency $2 n$ and wavelength $2 \lambda$
Explanation:
B Given equation can be written as, $\mathrm{y}=\frac{\mathrm{A}}{2} \cos \left(4 \pi \mathrm{nt}-\frac{4 \pi \mathrm{x}}{\lambda}\right)+\frac{\mathrm{A}}{2}\left(\because \cos ^{2} \theta=\frac{1+\cos 2 \theta}{2}\right)$ $\text { So, Amplitude }=\mathrm{A} / 2$ $\text { Frequency }=\frac{\omega}{2 \pi}=\frac{4 \pi \mathrm{n}}{2 \pi}=2 \mathrm{n}$ $\text { Wave length }=\frac{2 \pi}{\mathrm{k}}=\frac{2 \pi}{\frac{4 \pi}{\lambda}}=\frac{\lambda}{2}$
Karnataka CET-2002
WAVES
172346
The angle between particle velocity and wave velocity in a transverse wave is
1 zero
2 $\pi / 4$
3 $\pi / 2$
4 $\pi$
Explanation:
C In a transverse wave the particle of the medium vibrate about their mean position in a direction perpendicular to the direction of wave propagation. Here, the particle velocity is given by $\frac{\mathrm{dy}}{\mathrm{dt}}$ and wave velocity is given by $\frac{\mathrm{dx}}{\mathrm{dt}}$. Hence, the angle between particle velocity in a transverse wave is $\frac{\pi}{2}$.
MHT-CET 2008
WAVES
172348
The relationship between phase difference $\Delta \phi$ and the path difference $\Delta x$ between two interfering waves is given by ( $\lambda=$ wavelength)
A The relation between phase difference and path difference between two interfering wave is given by- Phase difference, $\Delta \phi=\frac{2 \pi}{\lambda} \times$ path difference $(\Delta \mathrm{x})$ Phase difference, $\Delta \phi=\frac{2 \pi}{\lambda} \times \Delta x$ or $\quad \Delta \mathrm{x}=\left(\frac{\lambda}{2 \pi}\right) \times \Delta \phi$
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
WAVES
172343
When a stationary wave is formed, then its frequency is
1 same as that of the individual waves
2 twice that of the individual waves
3 half that of the individual waves
4 $\sqrt{2}$ that of the individual waves
Explanation:
A Standing or stationary wave is formed due to superposition of two progressive waves of same nature, same frequency (or same wave length) same amplitude travelling with same speed in a bounded medium in mutually opposite direction. $Y_{1}=A \sin (\omega t-k x)$ $Y_{2}=A \sin (\omega t+k x)$ $Y=Y_{1}+Y_{2}=2 A \cos k x \sin \omega t$ Thus stationary wave has same frequency same as that of individuals waves.
UPSEE - 2014
WAVES
172344
The equation $y=A \cos ^{2}\left[2 \pi n t-2 \pi \frac{x}{\lambda}\right]$ represents a wave with:
1 amplitude $\mathrm{A} / 2$, frequency $2 \mathrm{n}$ and wavelength $\lambda$
2 amplitude $\mathrm{A} / 2$, frequency $2 \mathrm{n}$ and wavelength $\lambda / 2$
3 amplitude $\mathrm{A}$, frequency $\mathrm{n}$ and wavelength $\lambda$
4 amplitude $A$, frequency $2 n$ and wavelength $2 \lambda$
Explanation:
B Given equation can be written as, $\mathrm{y}=\frac{\mathrm{A}}{2} \cos \left(4 \pi \mathrm{nt}-\frac{4 \pi \mathrm{x}}{\lambda}\right)+\frac{\mathrm{A}}{2}\left(\because \cos ^{2} \theta=\frac{1+\cos 2 \theta}{2}\right)$ $\text { So, Amplitude }=\mathrm{A} / 2$ $\text { Frequency }=\frac{\omega}{2 \pi}=\frac{4 \pi \mathrm{n}}{2 \pi}=2 \mathrm{n}$ $\text { Wave length }=\frac{2 \pi}{\mathrm{k}}=\frac{2 \pi}{\frac{4 \pi}{\lambda}}=\frac{\lambda}{2}$
Karnataka CET-2002
WAVES
172346
The angle between particle velocity and wave velocity in a transverse wave is
1 zero
2 $\pi / 4$
3 $\pi / 2$
4 $\pi$
Explanation:
C In a transverse wave the particle of the medium vibrate about their mean position in a direction perpendicular to the direction of wave propagation. Here, the particle velocity is given by $\frac{\mathrm{dy}}{\mathrm{dt}}$ and wave velocity is given by $\frac{\mathrm{dx}}{\mathrm{dt}}$. Hence, the angle between particle velocity in a transverse wave is $\frac{\pi}{2}$.
MHT-CET 2008
WAVES
172348
The relationship between phase difference $\Delta \phi$ and the path difference $\Delta x$ between two interfering waves is given by ( $\lambda=$ wavelength)
A The relation between phase difference and path difference between two interfering wave is given by- Phase difference, $\Delta \phi=\frac{2 \pi}{\lambda} \times$ path difference $(\Delta \mathrm{x})$ Phase difference, $\Delta \phi=\frac{2 \pi}{\lambda} \times \Delta x$ or $\quad \Delta \mathrm{x}=\left(\frac{\lambda}{2 \pi}\right) \times \Delta \phi$
