139060
One mole of a van der Waal's gas obeying the equation
$\left(\mathbf{p}+\frac{a}{\mathbf{V}^{2}}\right)(\mathbf{V}-\mathbf{b})=\mathbf{R T}$
undergoes the quasi-static cyclic process which is shown in the $\mathrm{p}-\mathrm{V}$ diagram. The net heat absorbed by the gas in this process is
139060
One mole of a van der Waal's gas obeying the equation
$\left(\mathbf{p}+\frac{a}{\mathbf{V}^{2}}\right)(\mathbf{V}-\mathbf{b})=\mathbf{R T}$
undergoes the quasi-static cyclic process which is shown in the $\mathrm{p}-\mathrm{V}$ diagram. The net heat absorbed by the gas in this process is
139060
One mole of a van der Waal's gas obeying the equation
$\left(\mathbf{p}+\frac{a}{\mathbf{V}^{2}}\right)(\mathbf{V}-\mathbf{b})=\mathbf{R T}$
undergoes the quasi-static cyclic process which is shown in the $\mathrm{p}-\mathrm{V}$ diagram. The net heat absorbed by the gas in this process is
139060
One mole of a van der Waal's gas obeying the equation
$\left(\mathbf{p}+\frac{a}{\mathbf{V}^{2}}\right)(\mathbf{V}-\mathbf{b})=\mathbf{R T}$
undergoes the quasi-static cyclic process which is shown in the $\mathrm{p}-\mathrm{V}$ diagram. The net heat absorbed by the gas in this process is