Law of Radioactive decay
« Previous Topic: Radioactivity Next Topic: Nuclear Fission, Fusion, Nuclear Energy »
NUCLEAR PHYSICS

147889 Mean life of a radioactive sample is 100 seconds. Then its half-life (in minutes) is :

1 0.693
2 1
3 $10^{-4}$
4 1.1555
Karnataka CET-2005
NUCLEAR PHYSICS

147890 Half-life of a radioactive substance is 20 minutes. The time between $20 \%$ and $80 \%$ decay will be :

1 40 minutes
2 20 minutes
3 25 minutes
4 30 minutes
Karnataka CET-2003
NUCLEAR PHYSICS

147893 A radioactive isotope $A$ with a half life of $1.25 \times$ $10^{10}$ years decays into $B$ which is stable. A sample of rock from a planet is found to contain both $A$ and $B$ present in the ratio $1: 15$. The age of the rock is (in years)

1 $9.6 \times 10^{10}$
2 $4.2 \times 10^{10}$
3 $5 \times 10^{10}$
4 $1.95 \times 10^{10}$
J and K CET- 2009
NUCLEAR PHYSICS

147894 The ratio of half-life times of two elements $A$ and $B$ is $\frac{T_{A}}{T_{B}}$. The ratio of respective decay constant $\frac{\lambda_{A}}{\lambda_{B}}$ is

1 $\frac{T_{B}}{T_{A}}$
2 $\frac{T_{A}}{T_{B}}$
3 $\frac{T_{A}+T_{B}}{T_{A}}$
4 $\frac{T_{A}-T_{B}}{T_{A}}$
J and K CET- 2008
For More Updates join with Us
NUCLEAR PHYSICS

147889 Mean life of a radioactive sample is 100 seconds. Then its half-life (in minutes) is :

1 0.693
2 1
3 $10^{-4}$
4 1.1555
Karnataka CET-2005
NUCLEAR PHYSICS

147890 Half-life of a radioactive substance is 20 minutes. The time between $20 \%$ and $80 \%$ decay will be :

1 40 minutes
2 20 minutes
3 25 minutes
4 30 minutes
Karnataka CET-2003
NUCLEAR PHYSICS

147893 A radioactive isotope $A$ with a half life of $1.25 \times$ $10^{10}$ years decays into $B$ which is stable. A sample of rock from a planet is found to contain both $A$ and $B$ present in the ratio $1: 15$. The age of the rock is (in years)

1 $9.6 \times 10^{10}$
2 $4.2 \times 10^{10}$
3 $5 \times 10^{10}$
4 $1.95 \times 10^{10}$
J and K CET- 2009
NUCLEAR PHYSICS

147894 The ratio of half-life times of two elements $A$ and $B$ is $\frac{T_{A}}{T_{B}}$. The ratio of respective decay constant $\frac{\lambda_{A}}{\lambda_{B}}$ is

1 $\frac{T_{B}}{T_{A}}$
2 $\frac{T_{A}}{T_{B}}$
3 $\frac{T_{A}+T_{B}}{T_{A}}$
4 $\frac{T_{A}-T_{B}}{T_{A}}$
J and K CET- 2008
NEET DIGITAL LIBRARY
NUCLEAR PHYSICS

147889 Mean life of a radioactive sample is 100 seconds. Then its half-life (in minutes) is :

1 0.693
2 1
3 $10^{-4}$
4 1.1555
Karnataka CET-2005
NUCLEAR PHYSICS

147890 Half-life of a radioactive substance is 20 minutes. The time between $20 \%$ and $80 \%$ decay will be :

1 40 minutes
2 20 minutes
3 25 minutes
4 30 minutes
Karnataka CET-2003
NUCLEAR PHYSICS

147893 A radioactive isotope $A$ with a half life of $1.25 \times$ $10^{10}$ years decays into $B$ which is stable. A sample of rock from a planet is found to contain both $A$ and $B$ present in the ratio $1: 15$. The age of the rock is (in years)

1 $9.6 \times 10^{10}$
2 $4.2 \times 10^{10}$
3 $5 \times 10^{10}$
4 $1.95 \times 10^{10}$
J and K CET- 2009
NUCLEAR PHYSICS

147894 The ratio of half-life times of two elements $A$ and $B$ is $\frac{T_{A}}{T_{B}}$. The ratio of respective decay constant $\frac{\lambda_{A}}{\lambda_{B}}$ is

1 $\frac{T_{B}}{T_{A}}$
2 $\frac{T_{A}}{T_{B}}$
3 $\frac{T_{A}+T_{B}}{T_{A}}$
4 $\frac{T_{A}-T_{B}}{T_{A}}$
J and K CET- 2008
Join With Us for More Updates
NUCLEAR PHYSICS

147889 Mean life of a radioactive sample is 100 seconds. Then its half-life (in minutes) is :

1 0.693
2 1
3 $10^{-4}$
4 1.1555
Karnataka CET-2005
NUCLEAR PHYSICS

147890 Half-life of a radioactive substance is 20 minutes. The time between $20 \%$ and $80 \%$ decay will be :

1 40 minutes
2 20 minutes
3 25 minutes
4 30 minutes
Karnataka CET-2003
NUCLEAR PHYSICS

147893 A radioactive isotope $A$ with a half life of $1.25 \times$ $10^{10}$ years decays into $B$ which is stable. A sample of rock from a planet is found to contain both $A$ and $B$ present in the ratio $1: 15$. The age of the rock is (in years)

1 $9.6 \times 10^{10}$
2 $4.2 \times 10^{10}$
3 $5 \times 10^{10}$
4 $1.95 \times 10^{10}$
J and K CET- 2009
NUCLEAR PHYSICS

147894 The ratio of half-life times of two elements $A$ and $B$ is $\frac{T_{A}}{T_{B}}$. The ratio of respective decay constant $\frac{\lambda_{A}}{\lambda_{B}}$ is

1 $\frac{T_{B}}{T_{A}}$
2 $\frac{T_{A}}{T_{B}}$
3 $\frac{T_{A}+T_{B}}{T_{A}}$
4 $\frac{T_{A}-T_{B}}{T_{A}}$
J and K CET- 2008
For More Updates join with Us