1 a neutron in the nucleus decays emitting an electron
2 an atomic electron is ejected
3 an electron already present with in the nucleus is ejected
4 a part of the binding energy of the nucleus is converted into an electron
5 a proton in the nucleus decays emitting an electron
Explanation:
A Unstable nucleus undergoes radioactive decay to obtain a stable configuration. Radioactive decay of a nucleus is the process in which the nucleus losses energy in the form of radiations. Therefore, this kind of decay is also called nuclear decay. One type of the radioactive decay is beta decay in beta decay, a neutron of the nucleus is converted into a proton or an electron by emission of a beta particle. A beta particle can be an electron or a positron. When the neutron is converted into an electron the beta particle released is a positron. Along with the positron a neutrino is also released. This type of beta decay is called positive beta decay. It is denoted by $\beta^{+}$. The equation of positive decay is as for $\mathrm{p} \rightarrow \mathrm{n}+\mathrm{e}^{+}$ When the neutron is converted into a proton, the beta particle released is an electron. Along with the electron, an anti-neutrino is also released. This type of beta decay is called negative beta decay. It is denoted by $\beta$ The equation of negative decay is as follows, $\mathrm{p} \rightarrow \mathrm{n}+\mathrm{e}^{-}$ Therefore, negative beta decay involves decay of a neutron by emitting an electron.
Kerala CEE - 2016
NUCLEAR PHYSICS
147656
Select the wrong statement.
1 Radioactivity is a statistical process.
2 Radioactivity is a spontaneous process.
3 Radioactivity is neutral characteristic of few elements.
4 Radioactive elements cannot be produced in the laboratory.
Explanation:
A Radioactivity is not a statistical process.
CG PET- 2008
NUCLEAR PHYSICS
147682
The radioactive decay of thorium $(A=232, Z=$ 90) releases six alpha and four beta particles. The atomic number and mass number of the final product is
1 $Z=80, A=207$
2 $Z=82, A=208$
3 $Z=92, A=209$
4 $Z=90, A=207$
Explanation:
B ${ }_{90} \mathrm{Th}^{232} \stackrel{6 \alpha}{\longrightarrow} 78 \mathrm{X}^{208} \stackrel{4 \beta}{\longrightarrow} 82 \mathrm{y}^{208}$ $1 \alpha$-decay decrease in atomic number 2 and atomic mass 4. And $1 \beta$ - decay increase in atomic number 1 and atomic mass number change. Hence, ${ }_{90}{ }^{\text {Th2 } 232}$ decay $6 \alpha$ and $4 \beta$ then atomic number 82 and atomic mass 208.
J and K CET-2013
NUCLEAR PHYSICS
147713
When radioactive substance emits an $\alpha$ particle, then its position in the periodic table is lowered by ?
1 two places
2 three places
3 five places
4 one places
Explanation:
A When an $\alpha$-Particle is emitted from the nucleus of a radioactive atom the atomic number is reduced by 2 and mass number is reduced by 4 . $\mathrm{Z}^{\mathrm{A}} \stackrel{\alpha}{\longrightarrow}{ }_{\mathrm{Z}-2} \mathrm{Y}^{\mathrm{A}-4}+{ }_{2} \mathrm{He}^{4}(\alpha-\text { particle })$ So, the element is converted in to a new element which occurs 2 steps earlier in the periodic table.
1 a neutron in the nucleus decays emitting an electron
2 an atomic electron is ejected
3 an electron already present with in the nucleus is ejected
4 a part of the binding energy of the nucleus is converted into an electron
5 a proton in the nucleus decays emitting an electron
Explanation:
A Unstable nucleus undergoes radioactive decay to obtain a stable configuration. Radioactive decay of a nucleus is the process in which the nucleus losses energy in the form of radiations. Therefore, this kind of decay is also called nuclear decay. One type of the radioactive decay is beta decay in beta decay, a neutron of the nucleus is converted into a proton or an electron by emission of a beta particle. A beta particle can be an electron or a positron. When the neutron is converted into an electron the beta particle released is a positron. Along with the positron a neutrino is also released. This type of beta decay is called positive beta decay. It is denoted by $\beta^{+}$. The equation of positive decay is as for $\mathrm{p} \rightarrow \mathrm{n}+\mathrm{e}^{+}$ When the neutron is converted into a proton, the beta particle released is an electron. Along with the electron, an anti-neutrino is also released. This type of beta decay is called negative beta decay. It is denoted by $\beta$ The equation of negative decay is as follows, $\mathrm{p} \rightarrow \mathrm{n}+\mathrm{e}^{-}$ Therefore, negative beta decay involves decay of a neutron by emitting an electron.
Kerala CEE - 2016
NUCLEAR PHYSICS
147656
Select the wrong statement.
1 Radioactivity is a statistical process.
2 Radioactivity is a spontaneous process.
3 Radioactivity is neutral characteristic of few elements.
4 Radioactive elements cannot be produced in the laboratory.
Explanation:
A Radioactivity is not a statistical process.
CG PET- 2008
NUCLEAR PHYSICS
147682
The radioactive decay of thorium $(A=232, Z=$ 90) releases six alpha and four beta particles. The atomic number and mass number of the final product is
1 $Z=80, A=207$
2 $Z=82, A=208$
3 $Z=92, A=209$
4 $Z=90, A=207$
Explanation:
B ${ }_{90} \mathrm{Th}^{232} \stackrel{6 \alpha}{\longrightarrow} 78 \mathrm{X}^{208} \stackrel{4 \beta}{\longrightarrow} 82 \mathrm{y}^{208}$ $1 \alpha$-decay decrease in atomic number 2 and atomic mass 4. And $1 \beta$ - decay increase in atomic number 1 and atomic mass number change. Hence, ${ }_{90}{ }^{\text {Th2 } 232}$ decay $6 \alpha$ and $4 \beta$ then atomic number 82 and atomic mass 208.
J and K CET-2013
NUCLEAR PHYSICS
147713
When radioactive substance emits an $\alpha$ particle, then its position in the periodic table is lowered by ?
1 two places
2 three places
3 five places
4 one places
Explanation:
A When an $\alpha$-Particle is emitted from the nucleus of a radioactive atom the atomic number is reduced by 2 and mass number is reduced by 4 . $\mathrm{Z}^{\mathrm{A}} \stackrel{\alpha}{\longrightarrow}{ }_{\mathrm{Z}-2} \mathrm{Y}^{\mathrm{A}-4}+{ }_{2} \mathrm{He}^{4}(\alpha-\text { particle })$ So, the element is converted in to a new element which occurs 2 steps earlier in the periodic table.
1 a neutron in the nucleus decays emitting an electron
2 an atomic electron is ejected
3 an electron already present with in the nucleus is ejected
4 a part of the binding energy of the nucleus is converted into an electron
5 a proton in the nucleus decays emitting an electron
Explanation:
A Unstable nucleus undergoes radioactive decay to obtain a stable configuration. Radioactive decay of a nucleus is the process in which the nucleus losses energy in the form of radiations. Therefore, this kind of decay is also called nuclear decay. One type of the radioactive decay is beta decay in beta decay, a neutron of the nucleus is converted into a proton or an electron by emission of a beta particle. A beta particle can be an electron or a positron. When the neutron is converted into an electron the beta particle released is a positron. Along with the positron a neutrino is also released. This type of beta decay is called positive beta decay. It is denoted by $\beta^{+}$. The equation of positive decay is as for $\mathrm{p} \rightarrow \mathrm{n}+\mathrm{e}^{+}$ When the neutron is converted into a proton, the beta particle released is an electron. Along with the electron, an anti-neutrino is also released. This type of beta decay is called negative beta decay. It is denoted by $\beta$ The equation of negative decay is as follows, $\mathrm{p} \rightarrow \mathrm{n}+\mathrm{e}^{-}$ Therefore, negative beta decay involves decay of a neutron by emitting an electron.
Kerala CEE - 2016
NUCLEAR PHYSICS
147656
Select the wrong statement.
1 Radioactivity is a statistical process.
2 Radioactivity is a spontaneous process.
3 Radioactivity is neutral characteristic of few elements.
4 Radioactive elements cannot be produced in the laboratory.
Explanation:
A Radioactivity is not a statistical process.
CG PET- 2008
NUCLEAR PHYSICS
147682
The radioactive decay of thorium $(A=232, Z=$ 90) releases six alpha and four beta particles. The atomic number and mass number of the final product is
1 $Z=80, A=207$
2 $Z=82, A=208$
3 $Z=92, A=209$
4 $Z=90, A=207$
Explanation:
B ${ }_{90} \mathrm{Th}^{232} \stackrel{6 \alpha}{\longrightarrow} 78 \mathrm{X}^{208} \stackrel{4 \beta}{\longrightarrow} 82 \mathrm{y}^{208}$ $1 \alpha$-decay decrease in atomic number 2 and atomic mass 4. And $1 \beta$ - decay increase in atomic number 1 and atomic mass number change. Hence, ${ }_{90}{ }^{\text {Th2 } 232}$ decay $6 \alpha$ and $4 \beta$ then atomic number 82 and atomic mass 208.
J and K CET-2013
NUCLEAR PHYSICS
147713
When radioactive substance emits an $\alpha$ particle, then its position in the periodic table is lowered by ?
1 two places
2 three places
3 five places
4 one places
Explanation:
A When an $\alpha$-Particle is emitted from the nucleus of a radioactive atom the atomic number is reduced by 2 and mass number is reduced by 4 . $\mathrm{Z}^{\mathrm{A}} \stackrel{\alpha}{\longrightarrow}{ }_{\mathrm{Z}-2} \mathrm{Y}^{\mathrm{A}-4}+{ }_{2} \mathrm{He}^{4}(\alpha-\text { particle })$ So, the element is converted in to a new element which occurs 2 steps earlier in the periodic table.
1 a neutron in the nucleus decays emitting an electron
2 an atomic electron is ejected
3 an electron already present with in the nucleus is ejected
4 a part of the binding energy of the nucleus is converted into an electron
5 a proton in the nucleus decays emitting an electron
Explanation:
A Unstable nucleus undergoes radioactive decay to obtain a stable configuration. Radioactive decay of a nucleus is the process in which the nucleus losses energy in the form of radiations. Therefore, this kind of decay is also called nuclear decay. One type of the radioactive decay is beta decay in beta decay, a neutron of the nucleus is converted into a proton or an electron by emission of a beta particle. A beta particle can be an electron or a positron. When the neutron is converted into an electron the beta particle released is a positron. Along with the positron a neutrino is also released. This type of beta decay is called positive beta decay. It is denoted by $\beta^{+}$. The equation of positive decay is as for $\mathrm{p} \rightarrow \mathrm{n}+\mathrm{e}^{+}$ When the neutron is converted into a proton, the beta particle released is an electron. Along with the electron, an anti-neutrino is also released. This type of beta decay is called negative beta decay. It is denoted by $\beta$ The equation of negative decay is as follows, $\mathrm{p} \rightarrow \mathrm{n}+\mathrm{e}^{-}$ Therefore, negative beta decay involves decay of a neutron by emitting an electron.
Kerala CEE - 2016
NUCLEAR PHYSICS
147656
Select the wrong statement.
1 Radioactivity is a statistical process.
2 Radioactivity is a spontaneous process.
3 Radioactivity is neutral characteristic of few elements.
4 Radioactive elements cannot be produced in the laboratory.
Explanation:
A Radioactivity is not a statistical process.
CG PET- 2008
NUCLEAR PHYSICS
147682
The radioactive decay of thorium $(A=232, Z=$ 90) releases six alpha and four beta particles. The atomic number and mass number of the final product is
1 $Z=80, A=207$
2 $Z=82, A=208$
3 $Z=92, A=209$
4 $Z=90, A=207$
Explanation:
B ${ }_{90} \mathrm{Th}^{232} \stackrel{6 \alpha}{\longrightarrow} 78 \mathrm{X}^{208} \stackrel{4 \beta}{\longrightarrow} 82 \mathrm{y}^{208}$ $1 \alpha$-decay decrease in atomic number 2 and atomic mass 4. And $1 \beta$ - decay increase in atomic number 1 and atomic mass number change. Hence, ${ }_{90}{ }^{\text {Th2 } 232}$ decay $6 \alpha$ and $4 \beta$ then atomic number 82 and atomic mass 208.
J and K CET-2013
NUCLEAR PHYSICS
147713
When radioactive substance emits an $\alpha$ particle, then its position in the periodic table is lowered by ?
1 two places
2 three places
3 five places
4 one places
Explanation:
A When an $\alpha$-Particle is emitted from the nucleus of a radioactive atom the atomic number is reduced by 2 and mass number is reduced by 4 . $\mathrm{Z}^{\mathrm{A}} \stackrel{\alpha}{\longrightarrow}{ }_{\mathrm{Z}-2} \mathrm{Y}^{\mathrm{A}-4}+{ }_{2} \mathrm{He}^{4}(\alpha-\text { particle })$ So, the element is converted in to a new element which occurs 2 steps earlier in the periodic table.
