Explanation:
B ${ }_{92} \mathrm{U}^{238} \rightarrow{ }_{85} \mathrm{At}^{210}$
Let, number of $\alpha$ - decays are $\mathrm{x}$ and number of $\beta$ - decay are $y$.
$92-2 \mathrm{x}-\mathrm{y}=85$
$2 \mathrm{x}-\mathrm{y}=7$
And, $\quad 238-4 x=210$
$x=7$
Substituting the value of $x$ in equation (i), we get
$2 \times 7-y=7$
$y=7$
So, number of $\alpha$ and $\beta$ - decays are respectively 7, 7