147555 The half life of a radioactive substance is 20 minutes. In how much time, the activity of substance drops to $\left(\frac{1}{16}\right)^{\text {th }}$ of its initial value ?

147556 ${ }_{92}^{238} \mathrm{~A} \rightarrow{ }_{90}^{234} \mathrm{~B} \rightarrow{ }_{2}^{4} \mathrm{D}+\mathrm{Q}$
In the given nuclear reaction, the approximate amount of energy released will be :
[Given, mass of ${ }_{92}^{238} \mathrm{~A}=238.05079 \times 931.5$ $\mathrm{MeV} / \mathrm{c}^{2}$,
Mass of ${ }_{90}^{234} \mathrm{~B}=\mathbf{2 3 4 . 0 4 3 6 3} \times 931.5 \mathrm{MeV} / \mathrm{c}^{2}$,
Mass of $\left.{ }_{2}^{4} \mathrm{D}=\mathbf{4 . 0 0 2 6 0} \times \mathbf{9 3 1 . 5} \mathrm{MeV} / \mathrm{c}^{2}\right]$

147557 A radio-active material is reduced to $1 / 8$ of its original amount in 3 days. If $8 \times 10^{-3} \mathrm{~kg}$ of the material is left after 5 days. The initial amount of the material is

147559 The half-life of a radioactive substance is $T$. The time taken, for disintegrating $\frac{7}{8}$ th part of its original mass will be:

147560 The half-life of a radioactive nucleus is 5 years, The fraction of the original sample that would decay in $\mathbf{1 5}$ years is:

147555 The half life of a radioactive substance is 20 minutes. In how much time, the activity of substance drops to $\left(\frac{1}{16}\right)^{\text {th }}$ of its initial value ?

147556 ${ }_{92}^{238} \mathrm{~A} \rightarrow{ }_{90}^{234} \mathrm{~B} \rightarrow{ }_{2}^{4} \mathrm{D}+\mathrm{Q}$
In the given nuclear reaction, the approximate amount of energy released will be :
[Given, mass of ${ }_{92}^{238} \mathrm{~A}=238.05079 \times 931.5$ $\mathrm{MeV} / \mathrm{c}^{2}$,
Mass of ${ }_{90}^{234} \mathrm{~B}=\mathbf{2 3 4 . 0 4 3 6 3} \times 931.5 \mathrm{MeV} / \mathrm{c}^{2}$,
Mass of $\left.{ }_{2}^{4} \mathrm{D}=\mathbf{4 . 0 0 2 6 0} \times \mathbf{9 3 1 . 5} \mathrm{MeV} / \mathrm{c}^{2}\right]$

147557 A radio-active material is reduced to $1 / 8$ of its original amount in 3 days. If $8 \times 10^{-3} \mathrm{~kg}$ of the material is left after 5 days. The initial amount of the material is

147559 The half-life of a radioactive substance is $T$. The time taken, for disintegrating $\frac{7}{8}$ th part of its original mass will be:

147560 The half-life of a radioactive nucleus is 5 years, The fraction of the original sample that would decay in $\mathbf{1 5}$ years is:

147555 The half life of a radioactive substance is 20 minutes. In how much time, the activity of substance drops to $\left(\frac{1}{16}\right)^{\text {th }}$ of its initial value ?

147556 ${ }_{92}^{238} \mathrm{~A} \rightarrow{ }_{90}^{234} \mathrm{~B} \rightarrow{ }_{2}^{4} \mathrm{D}+\mathrm{Q}$
In the given nuclear reaction, the approximate amount of energy released will be :
[Given, mass of ${ }_{92}^{238} \mathrm{~A}=238.05079 \times 931.5$ $\mathrm{MeV} / \mathrm{c}^{2}$,
Mass of ${ }_{90}^{234} \mathrm{~B}=\mathbf{2 3 4 . 0 4 3 6 3} \times 931.5 \mathrm{MeV} / \mathrm{c}^{2}$,
Mass of $\left.{ }_{2}^{4} \mathrm{D}=\mathbf{4 . 0 0 2 6 0} \times \mathbf{9 3 1 . 5} \mathrm{MeV} / \mathrm{c}^{2}\right]$

147557 A radio-active material is reduced to $1 / 8$ of its original amount in 3 days. If $8 \times 10^{-3} \mathrm{~kg}$ of the material is left after 5 days. The initial amount of the material is

147559 The half-life of a radioactive substance is $T$. The time taken, for disintegrating $\frac{7}{8}$ th part of its original mass will be:

147560 The half-life of a radioactive nucleus is 5 years, The fraction of the original sample that would decay in $\mathbf{1 5}$ years is:

147555 The half life of a radioactive substance is 20 minutes. In how much time, the activity of substance drops to $\left(\frac{1}{16}\right)^{\text {th }}$ of its initial value ?

147556 ${ }_{92}^{238} \mathrm{~A} \rightarrow{ }_{90}^{234} \mathrm{~B} \rightarrow{ }_{2}^{4} \mathrm{D}+\mathrm{Q}$
In the given nuclear reaction, the approximate amount of energy released will be :
[Given, mass of ${ }_{92}^{238} \mathrm{~A}=238.05079 \times 931.5$ $\mathrm{MeV} / \mathrm{c}^{2}$,
Mass of ${ }_{90}^{234} \mathrm{~B}=\mathbf{2 3 4 . 0 4 3 6 3} \times 931.5 \mathrm{MeV} / \mathrm{c}^{2}$,
Mass of $\left.{ }_{2}^{4} \mathrm{D}=\mathbf{4 . 0 0 2 6 0} \times \mathbf{9 3 1 . 5} \mathrm{MeV} / \mathrm{c}^{2}\right]$

147557 A radio-active material is reduced to $1 / 8$ of its original amount in 3 days. If $8 \times 10^{-3} \mathrm{~kg}$ of the material is left after 5 days. The initial amount of the material is

147559 The half-life of a radioactive substance is $T$. The time taken, for disintegrating $\frac{7}{8}$ th part of its original mass will be:

147560 The half-life of a radioactive nucleus is 5 years, The fraction of the original sample that would decay in $\mathbf{1 5}$ years is:

147555 The half life of a radioactive substance is 20 minutes. In how much time, the activity of substance drops to $\left(\frac{1}{16}\right)^{\text {th }}$ of its initial value ?

147556 ${ }_{92}^{238} \mathrm{~A} \rightarrow{ }_{90}^{234} \mathrm{~B} \rightarrow{ }_{2}^{4} \mathrm{D}+\mathrm{Q}$
In the given nuclear reaction, the approximate amount of energy released will be :
[Given, mass of ${ }_{92}^{238} \mathrm{~A}=238.05079 \times 931.5$ $\mathrm{MeV} / \mathrm{c}^{2}$,
Mass of ${ }_{90}^{234} \mathrm{~B}=\mathbf{2 3 4 . 0 4 3 6 3} \times 931.5 \mathrm{MeV} / \mathrm{c}^{2}$,
Mass of $\left.{ }_{2}^{4} \mathrm{D}=\mathbf{4 . 0 0 2 6 0} \times \mathbf{9 3 1 . 5} \mathrm{MeV} / \mathrm{c}^{2}\right]$

147557 A radio-active material is reduced to $1 / 8$ of its original amount in 3 days. If $8 \times 10^{-3} \mathrm{~kg}$ of the material is left after 5 days. The initial amount of the material is

147559 The half-life of a radioactive substance is $T$. The time taken, for disintegrating $\frac{7}{8}$ th part of its original mass will be:

147560 The half-life of a radioactive nucleus is 5 years, The fraction of the original sample that would decay in $\mathbf{1 5}$ years is: