147443
For a nucleus ${ }_{\mathrm{Z}}^{\mathrm{A}} \mathrm{X}$ having mass number $\mathrm{A}$ and atomic number $Z$
A. The surface energy per nucleon $\left(b_{s}\right)=$ $\mathrm{a}_{1} \mathrm{~A}^{2 / 3}$
B. The Coulomb contribution to the binding energy $b_{c}=-a_{2} \frac{Z(Z-1)}{A^{4 / 3}}$
C. The volume energy $b_{v}=a_{3} A$
D. Decrease in the binding energy is proportional to surface area
E. While estimating the surface energy, it is assumed that each nucleon interacts with 12 nucleons, ( $a_{1}, a_{2}$ and $a_{3}$ constants)
Choose the most appropriate answer from the options given below
147445
Given below are two statement : One is labelled as Assertion $A$ and the other is labelled as Reason R
Assertion A: The nuclear density of nuclides ${ }_{5}^{10} \mathrm{~B},{ }_{3}^{6} \mathrm{Li},{ }_{26}^{56} \mathrm{Fe},{ }_{10}^{20} \mathrm{Ne}$ and ${ }_{83}^{200} \mathrm{Bi}$ can be arranged as $\boldsymbol{\rho}_{\mathrm{Bi}}^{\mathrm{N}}>\boldsymbol{\rho}_{\mathrm{Fe}}^{\mathrm{N}}>\boldsymbol{\rho}_{\mathrm{Ne}}^{\mathrm{N}}>\boldsymbol{\rho}_{\mathrm{Li}}^{\mathrm{N}}$.
Reason : The redius $R$ of nucleus is related to its mass number $A$ as $R=R_{0} A^{1 / 3}$, where $R_{0}$ is a constant. In the light of the above statement, choose the correct answer from the options given below:
147443
For a nucleus ${ }_{\mathrm{Z}}^{\mathrm{A}} \mathrm{X}$ having mass number $\mathrm{A}$ and atomic number $Z$
A. The surface energy per nucleon $\left(b_{s}\right)=$ $\mathrm{a}_{1} \mathrm{~A}^{2 / 3}$
B. The Coulomb contribution to the binding energy $b_{c}=-a_{2} \frac{Z(Z-1)}{A^{4 / 3}}$
C. The volume energy $b_{v}=a_{3} A$
D. Decrease in the binding energy is proportional to surface area
E. While estimating the surface energy, it is assumed that each nucleon interacts with 12 nucleons, ( $a_{1}, a_{2}$ and $a_{3}$ constants)
Choose the most appropriate answer from the options given below
147445
Given below are two statement : One is labelled as Assertion $A$ and the other is labelled as Reason R
Assertion A: The nuclear density of nuclides ${ }_{5}^{10} \mathrm{~B},{ }_{3}^{6} \mathrm{Li},{ }_{26}^{56} \mathrm{Fe},{ }_{10}^{20} \mathrm{Ne}$ and ${ }_{83}^{200} \mathrm{Bi}$ can be arranged as $\boldsymbol{\rho}_{\mathrm{Bi}}^{\mathrm{N}}>\boldsymbol{\rho}_{\mathrm{Fe}}^{\mathrm{N}}>\boldsymbol{\rho}_{\mathrm{Ne}}^{\mathrm{N}}>\boldsymbol{\rho}_{\mathrm{Li}}^{\mathrm{N}}$.
Reason : The redius $R$ of nucleus is related to its mass number $A$ as $R=R_{0} A^{1 / 3}$, where $R_{0}$ is a constant. In the light of the above statement, choose the correct answer from the options given below:
147443
For a nucleus ${ }_{\mathrm{Z}}^{\mathrm{A}} \mathrm{X}$ having mass number $\mathrm{A}$ and atomic number $Z$
A. The surface energy per nucleon $\left(b_{s}\right)=$ $\mathrm{a}_{1} \mathrm{~A}^{2 / 3}$
B. The Coulomb contribution to the binding energy $b_{c}=-a_{2} \frac{Z(Z-1)}{A^{4 / 3}}$
C. The volume energy $b_{v}=a_{3} A$
D. Decrease in the binding energy is proportional to surface area
E. While estimating the surface energy, it is assumed that each nucleon interacts with 12 nucleons, ( $a_{1}, a_{2}$ and $a_{3}$ constants)
Choose the most appropriate answer from the options given below
147445
Given below are two statement : One is labelled as Assertion $A$ and the other is labelled as Reason R
Assertion A: The nuclear density of nuclides ${ }_{5}^{10} \mathrm{~B},{ }_{3}^{6} \mathrm{Li},{ }_{26}^{56} \mathrm{Fe},{ }_{10}^{20} \mathrm{Ne}$ and ${ }_{83}^{200} \mathrm{Bi}$ can be arranged as $\boldsymbol{\rho}_{\mathrm{Bi}}^{\mathrm{N}}>\boldsymbol{\rho}_{\mathrm{Fe}}^{\mathrm{N}}>\boldsymbol{\rho}_{\mathrm{Ne}}^{\mathrm{N}}>\boldsymbol{\rho}_{\mathrm{Li}}^{\mathrm{N}}$.
Reason : The redius $R$ of nucleus is related to its mass number $A$ as $R=R_{0} A^{1 / 3}$, where $R_{0}$ is a constant. In the light of the above statement, choose the correct answer from the options given below:
147443
For a nucleus ${ }_{\mathrm{Z}}^{\mathrm{A}} \mathrm{X}$ having mass number $\mathrm{A}$ and atomic number $Z$
A. The surface energy per nucleon $\left(b_{s}\right)=$ $\mathrm{a}_{1} \mathrm{~A}^{2 / 3}$
B. The Coulomb contribution to the binding energy $b_{c}=-a_{2} \frac{Z(Z-1)}{A^{4 / 3}}$
C. The volume energy $b_{v}=a_{3} A$
D. Decrease in the binding energy is proportional to surface area
E. While estimating the surface energy, it is assumed that each nucleon interacts with 12 nucleons, ( $a_{1}, a_{2}$ and $a_{3}$ constants)
Choose the most appropriate answer from the options given below
147445
Given below are two statement : One is labelled as Assertion $A$ and the other is labelled as Reason R
Assertion A: The nuclear density of nuclides ${ }_{5}^{10} \mathrm{~B},{ }_{3}^{6} \mathrm{Li},{ }_{26}^{56} \mathrm{Fe},{ }_{10}^{20} \mathrm{Ne}$ and ${ }_{83}^{200} \mathrm{Bi}$ can be arranged as $\boldsymbol{\rho}_{\mathrm{Bi}}^{\mathrm{N}}>\boldsymbol{\rho}_{\mathrm{Fe}}^{\mathrm{N}}>\boldsymbol{\rho}_{\mathrm{Ne}}^{\mathrm{N}}>\boldsymbol{\rho}_{\mathrm{Li}}^{\mathrm{N}}$.
Reason : The redius $R$ of nucleus is related to its mass number $A$ as $R=R_{0} A^{1 / 3}$, where $R_{0}$ is a constant. In the light of the above statement, choose the correct answer from the options given below: