NEET Test Series from KOTA - 10 Papers In MS WORD
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Dual nature of radiation and Matter
142341
A light of wavelength ' $\lambda$ ' and intensity ' $I$ ' falls on photosensitive material. If ' $N$ ' photoelectrons are emitted, each with kinetic energy $E$, then
B We know that, $\mathrm{E}=\frac{\mathrm{hc}}{\lambda}$ Then, $\mathrm{E} \propto \frac{1}{\lambda}$ $\mathrm{I} \propto\left(\frac{\mathrm{n}}{\mathrm{t}}\right) \propto \mathrm{N}$ $\mathrm{N} \propto \mathrm{I}$
MHT-CET 2020
Dual nature of radiation and Matter
142342
Photoelectrons are obtained by irradiating zinc with radiation of $3100 \mathrm{~A}$.U. In order to increase the K.E. of ejected photoelectrons
1 the intensity of incident radiation should be increased
2 both wavelength and intensity of incident radiation should be increased
3 the wavelength of incident radiation should be decreased
4 the wavelength of incident radiation should be increased
Explanation:
C We know that, from photoelectric effect $\mathrm{E}=\mathrm{K}_{\text {max }}+\phi$ $\frac{\mathrm{hc}}{\lambda}=\mathrm{K}_{\max }+\phi$ Then, $\quad \mathrm{K}_{\max } \propto \frac{1}{\lambda}$ So, wavelength of incident radiation should be decrease.
MHT-CET 2019
Dual nature of radiation and Matter
142344
In a photocell, frequency of incident radiation is increased by keeping other factors constant $\left(v>v_{0}\right)$, the stopping potential
1 decreases
2 increases
3 becomes zero
4 first decreases and then increases
Explanation:
B We know that, $\text { }$ $\mathrm{eV}_{0}=\mathrm{h} v-\phi$ Where, $\mathrm{V}_{0}$ gives the stopping potential, $v$ is the frequency and $\phi$ denotes the work function. $\therefore \mathrm{V}_{0}$ increases with an increase in $v$.
MHT-CET 2018
Dual nature of radiation and Matter
142348
A photoelectric cell is illuminated by a point source of light $1 \mathrm{~m}$ away. When the source is shifted to $2 \mathrm{~m}$, then
1 each emitted electron carries half the initial energy
2 number of electrons emitted is a quarter of the initial number
3 each emitted electron carries one quarter of the initial energy
4 number of electrons emitted is half the initial number
Explanation:
B We know that, intensity is define as $\mathrm{I} \propto\left(\frac{\mathrm{n}}{\mathrm{t}}\right) \propto \mathrm{N} \propto \frac{1}{\mathrm{~d}^{2}}$ So, $\quad \mathrm{I} \propto \frac{1}{\mathrm{~d}^{2}}$ Therefore, $\frac{\mathrm{N}_{1}}{\mathrm{~N}_{2}}=\left(\frac{\mathrm{d}_{2}}{\mathrm{~d}_{1}}\right)^{2}=\left(\frac{2}{1}\right)^{2}=4$ $\mathrm{N}_{2}=\mathrm{N}_{1} / 4$
142341
A light of wavelength ' $\lambda$ ' and intensity ' $I$ ' falls on photosensitive material. If ' $N$ ' photoelectrons are emitted, each with kinetic energy $E$, then
B We know that, $\mathrm{E}=\frac{\mathrm{hc}}{\lambda}$ Then, $\mathrm{E} \propto \frac{1}{\lambda}$ $\mathrm{I} \propto\left(\frac{\mathrm{n}}{\mathrm{t}}\right) \propto \mathrm{N}$ $\mathrm{N} \propto \mathrm{I}$
MHT-CET 2020
Dual nature of radiation and Matter
142342
Photoelectrons are obtained by irradiating zinc with radiation of $3100 \mathrm{~A}$.U. In order to increase the K.E. of ejected photoelectrons
1 the intensity of incident radiation should be increased
2 both wavelength and intensity of incident radiation should be increased
3 the wavelength of incident radiation should be decreased
4 the wavelength of incident radiation should be increased
Explanation:
C We know that, from photoelectric effect $\mathrm{E}=\mathrm{K}_{\text {max }}+\phi$ $\frac{\mathrm{hc}}{\lambda}=\mathrm{K}_{\max }+\phi$ Then, $\quad \mathrm{K}_{\max } \propto \frac{1}{\lambda}$ So, wavelength of incident radiation should be decrease.
MHT-CET 2019
Dual nature of radiation and Matter
142344
In a photocell, frequency of incident radiation is increased by keeping other factors constant $\left(v>v_{0}\right)$, the stopping potential
1 decreases
2 increases
3 becomes zero
4 first decreases and then increases
Explanation:
B We know that, $\text { }$ $\mathrm{eV}_{0}=\mathrm{h} v-\phi$ Where, $\mathrm{V}_{0}$ gives the stopping potential, $v$ is the frequency and $\phi$ denotes the work function. $\therefore \mathrm{V}_{0}$ increases with an increase in $v$.
MHT-CET 2018
Dual nature of radiation and Matter
142348
A photoelectric cell is illuminated by a point source of light $1 \mathrm{~m}$ away. When the source is shifted to $2 \mathrm{~m}$, then
1 each emitted electron carries half the initial energy
2 number of electrons emitted is a quarter of the initial number
3 each emitted electron carries one quarter of the initial energy
4 number of electrons emitted is half the initial number
Explanation:
B We know that, intensity is define as $\mathrm{I} \propto\left(\frac{\mathrm{n}}{\mathrm{t}}\right) \propto \mathrm{N} \propto \frac{1}{\mathrm{~d}^{2}}$ So, $\quad \mathrm{I} \propto \frac{1}{\mathrm{~d}^{2}}$ Therefore, $\frac{\mathrm{N}_{1}}{\mathrm{~N}_{2}}=\left(\frac{\mathrm{d}_{2}}{\mathrm{~d}_{1}}\right)^{2}=\left(\frac{2}{1}\right)^{2}=4$ $\mathrm{N}_{2}=\mathrm{N}_{1} / 4$
142341
A light of wavelength ' $\lambda$ ' and intensity ' $I$ ' falls on photosensitive material. If ' $N$ ' photoelectrons are emitted, each with kinetic energy $E$, then
B We know that, $\mathrm{E}=\frac{\mathrm{hc}}{\lambda}$ Then, $\mathrm{E} \propto \frac{1}{\lambda}$ $\mathrm{I} \propto\left(\frac{\mathrm{n}}{\mathrm{t}}\right) \propto \mathrm{N}$ $\mathrm{N} \propto \mathrm{I}$
MHT-CET 2020
Dual nature of radiation and Matter
142342
Photoelectrons are obtained by irradiating zinc with radiation of $3100 \mathrm{~A}$.U. In order to increase the K.E. of ejected photoelectrons
1 the intensity of incident radiation should be increased
2 both wavelength and intensity of incident radiation should be increased
3 the wavelength of incident radiation should be decreased
4 the wavelength of incident radiation should be increased
Explanation:
C We know that, from photoelectric effect $\mathrm{E}=\mathrm{K}_{\text {max }}+\phi$ $\frac{\mathrm{hc}}{\lambda}=\mathrm{K}_{\max }+\phi$ Then, $\quad \mathrm{K}_{\max } \propto \frac{1}{\lambda}$ So, wavelength of incident radiation should be decrease.
MHT-CET 2019
Dual nature of radiation and Matter
142344
In a photocell, frequency of incident radiation is increased by keeping other factors constant $\left(v>v_{0}\right)$, the stopping potential
1 decreases
2 increases
3 becomes zero
4 first decreases and then increases
Explanation:
B We know that, $\text { }$ $\mathrm{eV}_{0}=\mathrm{h} v-\phi$ Where, $\mathrm{V}_{0}$ gives the stopping potential, $v$ is the frequency and $\phi$ denotes the work function. $\therefore \mathrm{V}_{0}$ increases with an increase in $v$.
MHT-CET 2018
Dual nature of radiation and Matter
142348
A photoelectric cell is illuminated by a point source of light $1 \mathrm{~m}$ away. When the source is shifted to $2 \mathrm{~m}$, then
1 each emitted electron carries half the initial energy
2 number of electrons emitted is a quarter of the initial number
3 each emitted electron carries one quarter of the initial energy
4 number of electrons emitted is half the initial number
Explanation:
B We know that, intensity is define as $\mathrm{I} \propto\left(\frac{\mathrm{n}}{\mathrm{t}}\right) \propto \mathrm{N} \propto \frac{1}{\mathrm{~d}^{2}}$ So, $\quad \mathrm{I} \propto \frac{1}{\mathrm{~d}^{2}}$ Therefore, $\frac{\mathrm{N}_{1}}{\mathrm{~N}_{2}}=\left(\frac{\mathrm{d}_{2}}{\mathrm{~d}_{1}}\right)^{2}=\left(\frac{2}{1}\right)^{2}=4$ $\mathrm{N}_{2}=\mathrm{N}_{1} / 4$
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Dual nature of radiation and Matter
142341
A light of wavelength ' $\lambda$ ' and intensity ' $I$ ' falls on photosensitive material. If ' $N$ ' photoelectrons are emitted, each with kinetic energy $E$, then
B We know that, $\mathrm{E}=\frac{\mathrm{hc}}{\lambda}$ Then, $\mathrm{E} \propto \frac{1}{\lambda}$ $\mathrm{I} \propto\left(\frac{\mathrm{n}}{\mathrm{t}}\right) \propto \mathrm{N}$ $\mathrm{N} \propto \mathrm{I}$
MHT-CET 2020
Dual nature of radiation and Matter
142342
Photoelectrons are obtained by irradiating zinc with radiation of $3100 \mathrm{~A}$.U. In order to increase the K.E. of ejected photoelectrons
1 the intensity of incident radiation should be increased
2 both wavelength and intensity of incident radiation should be increased
3 the wavelength of incident radiation should be decreased
4 the wavelength of incident radiation should be increased
Explanation:
C We know that, from photoelectric effect $\mathrm{E}=\mathrm{K}_{\text {max }}+\phi$ $\frac{\mathrm{hc}}{\lambda}=\mathrm{K}_{\max }+\phi$ Then, $\quad \mathrm{K}_{\max } \propto \frac{1}{\lambda}$ So, wavelength of incident radiation should be decrease.
MHT-CET 2019
Dual nature of radiation and Matter
142344
In a photocell, frequency of incident radiation is increased by keeping other factors constant $\left(v>v_{0}\right)$, the stopping potential
1 decreases
2 increases
3 becomes zero
4 first decreases and then increases
Explanation:
B We know that, $\text { }$ $\mathrm{eV}_{0}=\mathrm{h} v-\phi$ Where, $\mathrm{V}_{0}$ gives the stopping potential, $v$ is the frequency and $\phi$ denotes the work function. $\therefore \mathrm{V}_{0}$ increases with an increase in $v$.
MHT-CET 2018
Dual nature of radiation and Matter
142348
A photoelectric cell is illuminated by a point source of light $1 \mathrm{~m}$ away. When the source is shifted to $2 \mathrm{~m}$, then
1 each emitted electron carries half the initial energy
2 number of electrons emitted is a quarter of the initial number
3 each emitted electron carries one quarter of the initial energy
4 number of electrons emitted is half the initial number
Explanation:
B We know that, intensity is define as $\mathrm{I} \propto\left(\frac{\mathrm{n}}{\mathrm{t}}\right) \propto \mathrm{N} \propto \frac{1}{\mathrm{~d}^{2}}$ So, $\quad \mathrm{I} \propto \frac{1}{\mathrm{~d}^{2}}$ Therefore, $\frac{\mathrm{N}_{1}}{\mathrm{~N}_{2}}=\left(\frac{\mathrm{d}_{2}}{\mathrm{~d}_{1}}\right)^{2}=\left(\frac{2}{1}\right)^{2}=4$ $\mathrm{N}_{2}=\mathrm{N}_{1} / 4$