Einstein s Photo Electric Equation and Energy Quantity Of Radiation (KE, Vmax, Work Function)
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Dual nature of radiation and Matter

142165 In photo electric effect
A. The Photocurrent is proportional to the intensity of the incident radiation.
B. Maximum Kinetic energy with which photoelectrons are emitted depends on the intensity of incident light.
C. Max. K.E with which photoelectrons are emitted depends on the frequency of incident light.
D. The emission of photoelectrons require a minimum threshold intensity of incident radiation.
E. Max. K.E of the photoelectrons is independent of the frequency of the incident light.
Choose the correct answer from the options given below :

1 A and C only
2 A and E only
3 B and C only
4 A and B only
Shift-II
Dual nature of radiation and Matter

142169 Given below are two statements
Statement I : Stopping potential in photoelectric effect does not depend on the power of the light source.
Statement II : For a given metal, the maximum kinetic energy of the photoelectron depends on the wavelength of the incident light.
In the light of above statements, choose the most appropriate answer from the options given below

1 Both Statement I and Statement II are incorrect
2 Statement I is correct but statement II is incorrect
3 Both Statement I and statement II are correct
4 Statement I is incorrect but statement II is correct
Shift-II
Dual nature of radiation and Matter

142173 Given below are two statements: one is labeled as
Assertion A and the other is labeled as Reason R.
Assertion A : The photoelectric effect does not takes place, if the energy of the incident radiation is less than the work function of metal.
Reason $R$ : Kinetic energy of the photoelectrons is zero, if the energy of the incident radiation is equal to the work function of a metal.
In the light of the above statements, choose the most appropriate answer from the options given below.

1 Both A and R are correct and R is the correct explanation of $A$
2 Both $\mathrm{A}$ and $\mathrm{R}$ are correct and $\mathrm{R}$ is not the correct explanation of $\mathrm{A}$
3 A is correct but $\mathrm{R}$ is not correct
4 A is not correct but $\mathrm{R}$ is correct
Shift-I
Dual nature of radiation and Matter

142209 Photoelectric emission takes place from a certain metal of threshold frequency ' $v$ '. If the radiation of frequency ' $2 v$ ' is incident on the metal plate, the maximum velocity of the emitted photoelectron will be $[h=$ Planck's constant, $m=$ mass of electron]

1 $\sqrt{\frac{2 h v}{m}}$
2 $\sqrt{\frac{h v}{3 m}}$
3 $\sqrt{\frac{h v}{2 m}}$
4 $\sqrt{\frac{h v}{m}}$
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Dual nature of radiation and Matter

142165 In photo electric effect
A. The Photocurrent is proportional to the intensity of the incident radiation.
B. Maximum Kinetic energy with which photoelectrons are emitted depends on the intensity of incident light.
C. Max. K.E with which photoelectrons are emitted depends on the frequency of incident light.
D. The emission of photoelectrons require a minimum threshold intensity of incident radiation.
E. Max. K.E of the photoelectrons is independent of the frequency of the incident light.
Choose the correct answer from the options given below :

1 A and C only
2 A and E only
3 B and C only
4 A and B only
Shift-II
Dual nature of radiation and Matter

142169 Given below are two statements
Statement I : Stopping potential in photoelectric effect does not depend on the power of the light source.
Statement II : For a given metal, the maximum kinetic energy of the photoelectron depends on the wavelength of the incident light.
In the light of above statements, choose the most appropriate answer from the options given below

1 Both Statement I and Statement II are incorrect
2 Statement I is correct but statement II is incorrect
3 Both Statement I and statement II are correct
4 Statement I is incorrect but statement II is correct
Shift-II
Dual nature of radiation and Matter

142173 Given below are two statements: one is labeled as
Assertion A and the other is labeled as Reason R.
Assertion A : The photoelectric effect does not takes place, if the energy of the incident radiation is less than the work function of metal.
Reason $R$ : Kinetic energy of the photoelectrons is zero, if the energy of the incident radiation is equal to the work function of a metal.
In the light of the above statements, choose the most appropriate answer from the options given below.

1 Both A and R are correct and R is the correct explanation of $A$
2 Both $\mathrm{A}$ and $\mathrm{R}$ are correct and $\mathrm{R}$ is not the correct explanation of $\mathrm{A}$
3 A is correct but $\mathrm{R}$ is not correct
4 A is not correct but $\mathrm{R}$ is correct
Shift-I
Dual nature of radiation and Matter

142209 Photoelectric emission takes place from a certain metal of threshold frequency ' $v$ '. If the radiation of frequency ' $2 v$ ' is incident on the metal plate, the maximum velocity of the emitted photoelectron will be $[h=$ Planck's constant, $m=$ mass of electron]

1 $\sqrt{\frac{2 h v}{m}}$
2 $\sqrt{\frac{h v}{3 m}}$
3 $\sqrt{\frac{h v}{2 m}}$
4 $\sqrt{\frac{h v}{m}}$
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NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Dual nature of radiation and Matter

142165 In photo electric effect
A. The Photocurrent is proportional to the intensity of the incident radiation.
B. Maximum Kinetic energy with which photoelectrons are emitted depends on the intensity of incident light.
C. Max. K.E with which photoelectrons are emitted depends on the frequency of incident light.
D. The emission of photoelectrons require a minimum threshold intensity of incident radiation.
E. Max. K.E of the photoelectrons is independent of the frequency of the incident light.
Choose the correct answer from the options given below :

1 A and C only
2 A and E only
3 B and C only
4 A and B only
Shift-II
Dual nature of radiation and Matter

142169 Given below are two statements
Statement I : Stopping potential in photoelectric effect does not depend on the power of the light source.
Statement II : For a given metal, the maximum kinetic energy of the photoelectron depends on the wavelength of the incident light.
In the light of above statements, choose the most appropriate answer from the options given below

1 Both Statement I and Statement II are incorrect
2 Statement I is correct but statement II is incorrect
3 Both Statement I and statement II are correct
4 Statement I is incorrect but statement II is correct
Shift-II
Dual nature of radiation and Matter

142173 Given below are two statements: one is labeled as
Assertion A and the other is labeled as Reason R.
Assertion A : The photoelectric effect does not takes place, if the energy of the incident radiation is less than the work function of metal.
Reason $R$ : Kinetic energy of the photoelectrons is zero, if the energy of the incident radiation is equal to the work function of a metal.
In the light of the above statements, choose the most appropriate answer from the options given below.

1 Both A and R are correct and R is the correct explanation of $A$
2 Both $\mathrm{A}$ and $\mathrm{R}$ are correct and $\mathrm{R}$ is not the correct explanation of $\mathrm{A}$
3 A is correct but $\mathrm{R}$ is not correct
4 A is not correct but $\mathrm{R}$ is correct
Shift-I
Dual nature of radiation and Matter

142209 Photoelectric emission takes place from a certain metal of threshold frequency ' $v$ '. If the radiation of frequency ' $2 v$ ' is incident on the metal plate, the maximum velocity of the emitted photoelectron will be $[h=$ Planck's constant, $m=$ mass of electron]

1 $\sqrt{\frac{2 h v}{m}}$
2 $\sqrt{\frac{h v}{3 m}}$
3 $\sqrt{\frac{h v}{2 m}}$
4 $\sqrt{\frac{h v}{m}}$
MHT-CET 2020
NEET DIGITAL LIBRARY
Dual nature of radiation and Matter

142165 In photo electric effect
A. The Photocurrent is proportional to the intensity of the incident radiation.
B. Maximum Kinetic energy with which photoelectrons are emitted depends on the intensity of incident light.
C. Max. K.E with which photoelectrons are emitted depends on the frequency of incident light.
D. The emission of photoelectrons require a minimum threshold intensity of incident radiation.
E. Max. K.E of the photoelectrons is independent of the frequency of the incident light.
Choose the correct answer from the options given below :

1 A and C only
2 A and E only
3 B and C only
4 A and B only
Shift-II
Dual nature of radiation and Matter

142169 Given below are two statements
Statement I : Stopping potential in photoelectric effect does not depend on the power of the light source.
Statement II : For a given metal, the maximum kinetic energy of the photoelectron depends on the wavelength of the incident light.
In the light of above statements, choose the most appropriate answer from the options given below

1 Both Statement I and Statement II are incorrect
2 Statement I is correct but statement II is incorrect
3 Both Statement I and statement II are correct
4 Statement I is incorrect but statement II is correct
Shift-II
Dual nature of radiation and Matter

142173 Given below are two statements: one is labeled as
Assertion A and the other is labeled as Reason R.
Assertion A : The photoelectric effect does not takes place, if the energy of the incident radiation is less than the work function of metal.
Reason $R$ : Kinetic energy of the photoelectrons is zero, if the energy of the incident radiation is equal to the work function of a metal.
In the light of the above statements, choose the most appropriate answer from the options given below.

1 Both A and R are correct and R is the correct explanation of $A$
2 Both $\mathrm{A}$ and $\mathrm{R}$ are correct and $\mathrm{R}$ is not the correct explanation of $\mathrm{A}$
3 A is correct but $\mathrm{R}$ is not correct
4 A is not correct but $\mathrm{R}$ is correct
Shift-I
Dual nature of radiation and Matter

142209 Photoelectric emission takes place from a certain metal of threshold frequency ' $v$ '. If the radiation of frequency ' $2 v$ ' is incident on the metal plate, the maximum velocity of the emitted photoelectron will be $[h=$ Planck's constant, $m=$ mass of electron]

1 $\sqrt{\frac{2 h v}{m}}$
2 $\sqrt{\frac{h v}{3 m}}$
3 $\sqrt{\frac{h v}{2 m}}$
4 $\sqrt{\frac{h v}{m}}$
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Join With Us for More Updates