90665
Choose the correct answer from the given four options: In triangles ABC and DEF, \(\angle\text{B}=\angle\text{E},\angle\text{F}=\angle\text{C}\ \text{and}\text{ AB}=3\text{ DE}. \) Then, the two triangles are:
1 Congruent but not similar.
2 Similar but not congruent.
3 Neither congruent nor similar.
4 Congruent as well as similar.
Explanation:
BSimilar but not congruent. \(\text{In}\ \triangle\text{ABC}\text{ and}\ \triangle\text{DEF}, \angle\text{B}=\angle\text{E}=\angle\text{F}\ \text{and}=\text{AB}=3\text{DE} \)
We know that, if in two triangles corresponding two angles are same, then they are similar by AAA similarity criterion. Also \(\triangle\text{ABC}\text{ and}\ \triangle\text{DEF} \) do not satisfy any rule of congruency, (SAS, ASA, SSS), so both are not congruent. Understanding
TRIANGLES
90666
A man goes 24m due west and then 10m due north. How far is he from the starting point?
1 34m
2 17m
3 26m
4 28m
Explanation:
C26m
Let O be the starting point. From O the man goes west that is towards, W till point A. He then moves 10m due nirth, that is towards N to point B. \(\triangle\text{OAB} \) forms a right - angled triangle. By Pythagoras theorem, OB\(^{2}\) = OA\(^{2}\) + AB\(^{2}\) OB\(^{2 }\)=\(^{ }\)24\(^{2 }\)+ 10\(^{2}\) OB\(^{2 }\)= 576 + 100 OB\(^{2 }\)= 676 OB = 26m So, the man is 26m away from the the starting point.
TRIANGLES
90685
If \(\triangle\text{ABC}\sim\triangle\text{QRP},\frac{\text{ar}(\triangle\text{ABC})}{\text{ar}(\triangle\text{PQR})}=\frac{9}{4},\text{AB}=18\text{cm} \) and \(\text{BC}=15\text{cm} \) then \(\text{PR}=? \)
90668
In the figure, RS || DB || PQ. If CP = PD = 11cm and DR = RA = 3cm. Then the values of x and y are respectively:
1 12, 10.
2 14, 6.
3 10, 7
4 16, 8.
Explanation:
D16, 8. the figure RS || DB || PQ CP = PD = 11cm DR = RA = 3cm In \(\triangle\text{ABD} \) RS || BD and AR = RD \(\text{RS}=\frac{1}{2}\text{BD} \) \(\text{y}=\frac{1}{2}\text{x or x}=2\text{y} \) Only 16, 8 is possible. Understanding
90665
Choose the correct answer from the given four options: In triangles ABC and DEF, \(\angle\text{B}=\angle\text{E},\angle\text{F}=\angle\text{C}\ \text{and}\text{ AB}=3\text{ DE}. \) Then, the two triangles are:
1 Congruent but not similar.
2 Similar but not congruent.
3 Neither congruent nor similar.
4 Congruent as well as similar.
Explanation:
BSimilar but not congruent. \(\text{In}\ \triangle\text{ABC}\text{ and}\ \triangle\text{DEF}, \angle\text{B}=\angle\text{E}=\angle\text{F}\ \text{and}=\text{AB}=3\text{DE} \)
We know that, if in two triangles corresponding two angles are same, then they are similar by AAA similarity criterion. Also \(\triangle\text{ABC}\text{ and}\ \triangle\text{DEF} \) do not satisfy any rule of congruency, (SAS, ASA, SSS), so both are not congruent. Understanding
TRIANGLES
90666
A man goes 24m due west and then 10m due north. How far is he from the starting point?
1 34m
2 17m
3 26m
4 28m
Explanation:
C26m
Let O be the starting point. From O the man goes west that is towards, W till point A. He then moves 10m due nirth, that is towards N to point B. \(\triangle\text{OAB} \) forms a right - angled triangle. By Pythagoras theorem, OB\(^{2}\) = OA\(^{2}\) + AB\(^{2}\) OB\(^{2 }\)=\(^{ }\)24\(^{2 }\)+ 10\(^{2}\) OB\(^{2 }\)= 576 + 100 OB\(^{2 }\)= 676 OB = 26m So, the man is 26m away from the the starting point.
TRIANGLES
90685
If \(\triangle\text{ABC}\sim\triangle\text{QRP},\frac{\text{ar}(\triangle\text{ABC})}{\text{ar}(\triangle\text{PQR})}=\frac{9}{4},\text{AB}=18\text{cm} \) and \(\text{BC}=15\text{cm} \) then \(\text{PR}=? \)
90668
In the figure, RS || DB || PQ. If CP = PD = 11cm and DR = RA = 3cm. Then the values of x and y are respectively:
1 12, 10.
2 14, 6.
3 10, 7
4 16, 8.
Explanation:
D16, 8. the figure RS || DB || PQ CP = PD = 11cm DR = RA = 3cm In \(\triangle\text{ABD} \) RS || BD and AR = RD \(\text{RS}=\frac{1}{2}\text{BD} \) \(\text{y}=\frac{1}{2}\text{x or x}=2\text{y} \) Only 16, 8 is possible. Understanding
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
TRIANGLES
90665
Choose the correct answer from the given four options: In triangles ABC and DEF, \(\angle\text{B}=\angle\text{E},\angle\text{F}=\angle\text{C}\ \text{and}\text{ AB}=3\text{ DE}. \) Then, the two triangles are:
1 Congruent but not similar.
2 Similar but not congruent.
3 Neither congruent nor similar.
4 Congruent as well as similar.
Explanation:
BSimilar but not congruent. \(\text{In}\ \triangle\text{ABC}\text{ and}\ \triangle\text{DEF}, \angle\text{B}=\angle\text{E}=\angle\text{F}\ \text{and}=\text{AB}=3\text{DE} \)
We know that, if in two triangles corresponding two angles are same, then they are similar by AAA similarity criterion. Also \(\triangle\text{ABC}\text{ and}\ \triangle\text{DEF} \) do not satisfy any rule of congruency, (SAS, ASA, SSS), so both are not congruent. Understanding
TRIANGLES
90666
A man goes 24m due west and then 10m due north. How far is he from the starting point?
1 34m
2 17m
3 26m
4 28m
Explanation:
C26m
Let O be the starting point. From O the man goes west that is towards, W till point A. He then moves 10m due nirth, that is towards N to point B. \(\triangle\text{OAB} \) forms a right - angled triangle. By Pythagoras theorem, OB\(^{2}\) = OA\(^{2}\) + AB\(^{2}\) OB\(^{2 }\)=\(^{ }\)24\(^{2 }\)+ 10\(^{2}\) OB\(^{2 }\)= 576 + 100 OB\(^{2 }\)= 676 OB = 26m So, the man is 26m away from the the starting point.
TRIANGLES
90685
If \(\triangle\text{ABC}\sim\triangle\text{QRP},\frac{\text{ar}(\triangle\text{ABC})}{\text{ar}(\triangle\text{PQR})}=\frac{9}{4},\text{AB}=18\text{cm} \) and \(\text{BC}=15\text{cm} \) then \(\text{PR}=? \)
90668
In the figure, RS || DB || PQ. If CP = PD = 11cm and DR = RA = 3cm. Then the values of x and y are respectively:
1 12, 10.
2 14, 6.
3 10, 7
4 16, 8.
Explanation:
D16, 8. the figure RS || DB || PQ CP = PD = 11cm DR = RA = 3cm In \(\triangle\text{ABD} \) RS || BD and AR = RD \(\text{RS}=\frac{1}{2}\text{BD} \) \(\text{y}=\frac{1}{2}\text{x or x}=2\text{y} \) Only 16, 8 is possible. Understanding
90665
Choose the correct answer from the given four options: In triangles ABC and DEF, \(\angle\text{B}=\angle\text{E},\angle\text{F}=\angle\text{C}\ \text{and}\text{ AB}=3\text{ DE}. \) Then, the two triangles are:
1 Congruent but not similar.
2 Similar but not congruent.
3 Neither congruent nor similar.
4 Congruent as well as similar.
Explanation:
BSimilar but not congruent. \(\text{In}\ \triangle\text{ABC}\text{ and}\ \triangle\text{DEF}, \angle\text{B}=\angle\text{E}=\angle\text{F}\ \text{and}=\text{AB}=3\text{DE} \)
We know that, if in two triangles corresponding two angles are same, then they are similar by AAA similarity criterion. Also \(\triangle\text{ABC}\text{ and}\ \triangle\text{DEF} \) do not satisfy any rule of congruency, (SAS, ASA, SSS), so both are not congruent. Understanding
TRIANGLES
90666
A man goes 24m due west and then 10m due north. How far is he from the starting point?
1 34m
2 17m
3 26m
4 28m
Explanation:
C26m
Let O be the starting point. From O the man goes west that is towards, W till point A. He then moves 10m due nirth, that is towards N to point B. \(\triangle\text{OAB} \) forms a right - angled triangle. By Pythagoras theorem, OB\(^{2}\) = OA\(^{2}\) + AB\(^{2}\) OB\(^{2 }\)=\(^{ }\)24\(^{2 }\)+ 10\(^{2}\) OB\(^{2 }\)= 576 + 100 OB\(^{2 }\)= 676 OB = 26m So, the man is 26m away from the the starting point.
TRIANGLES
90685
If \(\triangle\text{ABC}\sim\triangle\text{QRP},\frac{\text{ar}(\triangle\text{ABC})}{\text{ar}(\triangle\text{PQR})}=\frac{9}{4},\text{AB}=18\text{cm} \) and \(\text{BC}=15\text{cm} \) then \(\text{PR}=? \)
90668
In the figure, RS || DB || PQ. If CP = PD = 11cm and DR = RA = 3cm. Then the values of x and y are respectively:
1 12, 10.
2 14, 6.
3 10, 7
4 16, 8.
Explanation:
D16, 8. the figure RS || DB || PQ CP = PD = 11cm DR = RA = 3cm In \(\triangle\text{ABD} \) RS || BD and AR = RD \(\text{RS}=\frac{1}{2}\text{BD} \) \(\text{y}=\frac{1}{2}\text{x or x}=2\text{y} \) Only 16, 8 is possible. Understanding
90665
Choose the correct answer from the given four options: In triangles ABC and DEF, \(\angle\text{B}=\angle\text{E},\angle\text{F}=\angle\text{C}\ \text{and}\text{ AB}=3\text{ DE}. \) Then, the two triangles are:
1 Congruent but not similar.
2 Similar but not congruent.
3 Neither congruent nor similar.
4 Congruent as well as similar.
Explanation:
BSimilar but not congruent. \(\text{In}\ \triangle\text{ABC}\text{ and}\ \triangle\text{DEF}, \angle\text{B}=\angle\text{E}=\angle\text{F}\ \text{and}=\text{AB}=3\text{DE} \)
We know that, if in two triangles corresponding two angles are same, then they are similar by AAA similarity criterion. Also \(\triangle\text{ABC}\text{ and}\ \triangle\text{DEF} \) do not satisfy any rule of congruency, (SAS, ASA, SSS), so both are not congruent. Understanding
TRIANGLES
90666
A man goes 24m due west and then 10m due north. How far is he from the starting point?
1 34m
2 17m
3 26m
4 28m
Explanation:
C26m
Let O be the starting point. From O the man goes west that is towards, W till point A. He then moves 10m due nirth, that is towards N to point B. \(\triangle\text{OAB} \) forms a right - angled triangle. By Pythagoras theorem, OB\(^{2}\) = OA\(^{2}\) + AB\(^{2}\) OB\(^{2 }\)=\(^{ }\)24\(^{2 }\)+ 10\(^{2}\) OB\(^{2 }\)= 576 + 100 OB\(^{2 }\)= 676 OB = 26m So, the man is 26m away from the the starting point.
TRIANGLES
90685
If \(\triangle\text{ABC}\sim\triangle\text{QRP},\frac{\text{ar}(\triangle\text{ABC})}{\text{ar}(\triangle\text{PQR})}=\frac{9}{4},\text{AB}=18\text{cm} \) and \(\text{BC}=15\text{cm} \) then \(\text{PR}=? \)
90668
In the figure, RS || DB || PQ. If CP = PD = 11cm and DR = RA = 3cm. Then the values of x and y are respectively:
1 12, 10.
2 14, 6.
3 10, 7
4 16, 8.
Explanation:
D16, 8. the figure RS || DB || PQ CP = PD = 11cm DR = RA = 3cm In \(\triangle\text{ABD} \) RS || BD and AR = RD \(\text{RS}=\frac{1}{2}\text{BD} \) \(\text{y}=\frac{1}{2}\text{x or x}=2\text{y} \) Only 16, 8 is possible. Understanding
