90269
The LCM of two numbers is 1200. Which of the following cannot be their HCF?
1 )600
2 )500
3 )400
4 )200
Explanation:
Exp: B 500 LCM of two number = 1200 Their HCF of these two numbers will be the factor of 1200 500 cannot be its HCF.
REAL NUMBERS
90270
If n is any natural number, then 6\(^{n}\) - 5\(^{n}\) always ends with:
1 )1
2 )3
3 )5
4 )7
Explanation:
Exp: A 1 n is any natural number and 6\(^{n}\) - 5\(^{n}\) We know that 6\(^{n}\) ends with 6 and 5\(^{n}\) ends with 5 6\(^{n}\) - 5\(^{n}\) will end with 6 - 5 = 1
REAL NUMBERS
90271
The sum of two irrational numbers is always
1 )None of these
2 )a rational number or an irrational number
3 )an irrational number
4 )a rational number
Explanation:
Exp: B a rational number or an irrational number The sum of two irrational numbers can be either a rational number or an irrational number. \(\text{e.g }5\sqrt{3}+3\sqrt{2}=5\sqrt{3}+3\sqrt{2}\) sum is irrational \((2+6\sqrt{7})+(-6\sqrt{7})=2\) sum is rational Hence sum can be either rational or irrational
REAL NUMBERS
90273
The number of possible pairs of number, whose product is 5400 and the HCF is 30 is:
1 )1
2 )2
3 )3
4 )4
Explanation:
Exp: B 2 Given that product of the number is 5400 = 30 × 3 × 2 × 30. \(\therefore\) Possible pairs as per the requirment are (1) 30 × (3 × 2 × 30) = 30 × 180 (2) (30 ×3) × (2 × 30) = 90 × 60 \(\therefore\) Total number of pairs = 2
90269
The LCM of two numbers is 1200. Which of the following cannot be their HCF?
1 )600
2 )500
3 )400
4 )200
Explanation:
Exp: B 500 LCM of two number = 1200 Their HCF of these two numbers will be the factor of 1200 500 cannot be its HCF.
REAL NUMBERS
90270
If n is any natural number, then 6\(^{n}\) - 5\(^{n}\) always ends with:
1 )1
2 )3
3 )5
4 )7
Explanation:
Exp: A 1 n is any natural number and 6\(^{n}\) - 5\(^{n}\) We know that 6\(^{n}\) ends with 6 and 5\(^{n}\) ends with 5 6\(^{n}\) - 5\(^{n}\) will end with 6 - 5 = 1
REAL NUMBERS
90271
The sum of two irrational numbers is always
1 )None of these
2 )a rational number or an irrational number
3 )an irrational number
4 )a rational number
Explanation:
Exp: B a rational number or an irrational number The sum of two irrational numbers can be either a rational number or an irrational number. \(\text{e.g }5\sqrt{3}+3\sqrt{2}=5\sqrt{3}+3\sqrt{2}\) sum is irrational \((2+6\sqrt{7})+(-6\sqrt{7})=2\) sum is rational Hence sum can be either rational or irrational
REAL NUMBERS
90273
The number of possible pairs of number, whose product is 5400 and the HCF is 30 is:
1 )1
2 )2
3 )3
4 )4
Explanation:
Exp: B 2 Given that product of the number is 5400 = 30 × 3 × 2 × 30. \(\therefore\) Possible pairs as per the requirment are (1) 30 × (3 × 2 × 30) = 30 × 180 (2) (30 ×3) × (2 × 30) = 90 × 60 \(\therefore\) Total number of pairs = 2
90269
The LCM of two numbers is 1200. Which of the following cannot be their HCF?
1 )600
2 )500
3 )400
4 )200
Explanation:
Exp: B 500 LCM of two number = 1200 Their HCF of these two numbers will be the factor of 1200 500 cannot be its HCF.
REAL NUMBERS
90270
If n is any natural number, then 6\(^{n}\) - 5\(^{n}\) always ends with:
1 )1
2 )3
3 )5
4 )7
Explanation:
Exp: A 1 n is any natural number and 6\(^{n}\) - 5\(^{n}\) We know that 6\(^{n}\) ends with 6 and 5\(^{n}\) ends with 5 6\(^{n}\) - 5\(^{n}\) will end with 6 - 5 = 1
REAL NUMBERS
90271
The sum of two irrational numbers is always
1 )None of these
2 )a rational number or an irrational number
3 )an irrational number
4 )a rational number
Explanation:
Exp: B a rational number or an irrational number The sum of two irrational numbers can be either a rational number or an irrational number. \(\text{e.g }5\sqrt{3}+3\sqrt{2}=5\sqrt{3}+3\sqrt{2}\) sum is irrational \((2+6\sqrt{7})+(-6\sqrt{7})=2\) sum is rational Hence sum can be either rational or irrational
REAL NUMBERS
90273
The number of possible pairs of number, whose product is 5400 and the HCF is 30 is:
1 )1
2 )2
3 )3
4 )4
Explanation:
Exp: B 2 Given that product of the number is 5400 = 30 × 3 × 2 × 30. \(\therefore\) Possible pairs as per the requirment are (1) 30 × (3 × 2 × 30) = 30 × 180 (2) (30 ×3) × (2 × 30) = 90 × 60 \(\therefore\) Total number of pairs = 2
90269
The LCM of two numbers is 1200. Which of the following cannot be their HCF?
1 )600
2 )500
3 )400
4 )200
Explanation:
Exp: B 500 LCM of two number = 1200 Their HCF of these two numbers will be the factor of 1200 500 cannot be its HCF.
REAL NUMBERS
90270
If n is any natural number, then 6\(^{n}\) - 5\(^{n}\) always ends with:
1 )1
2 )3
3 )5
4 )7
Explanation:
Exp: A 1 n is any natural number and 6\(^{n}\) - 5\(^{n}\) We know that 6\(^{n}\) ends with 6 and 5\(^{n}\) ends with 5 6\(^{n}\) - 5\(^{n}\) will end with 6 - 5 = 1
REAL NUMBERS
90271
The sum of two irrational numbers is always
1 )None of these
2 )a rational number or an irrational number
3 )an irrational number
4 )a rational number
Explanation:
Exp: B a rational number or an irrational number The sum of two irrational numbers can be either a rational number or an irrational number. \(\text{e.g }5\sqrt{3}+3\sqrt{2}=5\sqrt{3}+3\sqrt{2}\) sum is irrational \((2+6\sqrt{7})+(-6\sqrt{7})=2\) sum is rational Hence sum can be either rational or irrational
REAL NUMBERS
90273
The number of possible pairs of number, whose product is 5400 and the HCF is 30 is:
1 )1
2 )2
3 )3
4 )4
Explanation:
Exp: B 2 Given that product of the number is 5400 = 30 × 3 × 2 × 30. \(\therefore\) Possible pairs as per the requirment are (1) 30 × (3 × 2 × 30) = 30 × 180 (2) (30 ×3) × (2 × 30) = 90 × 60 \(\therefore\) Total number of pairs = 2
