NEET Test Series from KOTA - 10 Papers In MS WORD
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REAL NUMBERS
90197
The largest number which divides 33 and 75, leaving remainders 1 and 3 respectively is:
1 )8
2 )12
3 )16
4 )6
Explanation:
Exp: A 8 Let us subtract 1 from 33 and 3 from 75 in order to find their HCF 33 - 1 = 32 75 - 3 = 72 To find HCF of 32, 72 72 = 32 × 2 + 8 32 = 8 × 4 + 0 8 is the largest number which divides 33 and 75, leaving remainders 1 and 3 respectively.
REAL NUMBERS
90198
If the sum of LCM and HCF of two numbers is 1260 and their LCM is 900 more than their HCF, then the product of two numbers is:
1 )203400
2 )194400
3 )198400
4 )205400
Explanation:
Exp: B 194400 Given that sum of LCM and HCF = 1260 LCM + HCF = 1260 .....(1) Let two numbers be a and b and HCF (a, b) = x According to question: Put value of HCF and LCM in equation (1) \(\Rightarrow\)900 + x + x = 1260 \(\Rightarrow\)2x = 1260 - 900 \(\Rightarrow\)2x = 360 \(\Rightarrow\ \text{x}=\frac{360}{2}\) \(\Rightarrow\)x = 180 ......(2) Now, LCM × HCF = Product of two numbers Product of two number = (x + 900)(x) = (180 + 900)(180) = 1080 × 180 = 194400 Applying
REAL NUMBERS
90202
Which of the following is an irrational number?
1 )\(\frac{22}{7}\)
2 )\(3.1416\)
3 )\(3.\overline{1416}\)
4 )\(3.141141114...\)
Explanation:
Exp: D \(3.141141114...\) An irrational number is a number that is non-terminating and non-repeating. Option (a) is a rational number, while option (c) is a repeating decimal number, and so are rational numbers. Option (d) is an irrational number. Never Active Medium **[Real Numbers]**
REAL NUMBERS
90203
If the LCM of two numbers is 45 times their HCF and the sum of LCM and HCF is 1150, then HCF =
1 )25
2 )1150
3 )50
4 )45
Explanation:
Exp: A 25 Given: LCM = 45 × HCF ...(i) And LCM + HCF = 1150 ...(ii) Putting the value of LCM from eq. (i) in eq. (ii), we get 45 × HCF + HCF = 1150 HCF (45 + 1) = 1150 \(\Rightarrow\)46 × HCF = 1150 \(\Rightarrow\)HCF = 25
90197
The largest number which divides 33 and 75, leaving remainders 1 and 3 respectively is:
1 )8
2 )12
3 )16
4 )6
Explanation:
Exp: A 8 Let us subtract 1 from 33 and 3 from 75 in order to find their HCF 33 - 1 = 32 75 - 3 = 72 To find HCF of 32, 72 72 = 32 × 2 + 8 32 = 8 × 4 + 0 8 is the largest number which divides 33 and 75, leaving remainders 1 and 3 respectively.
REAL NUMBERS
90198
If the sum of LCM and HCF of two numbers is 1260 and their LCM is 900 more than their HCF, then the product of two numbers is:
1 )203400
2 )194400
3 )198400
4 )205400
Explanation:
Exp: B 194400 Given that sum of LCM and HCF = 1260 LCM + HCF = 1260 .....(1) Let two numbers be a and b and HCF (a, b) = x According to question: Put value of HCF and LCM in equation (1) \(\Rightarrow\)900 + x + x = 1260 \(\Rightarrow\)2x = 1260 - 900 \(\Rightarrow\)2x = 360 \(\Rightarrow\ \text{x}=\frac{360}{2}\) \(\Rightarrow\)x = 180 ......(2) Now, LCM × HCF = Product of two numbers Product of two number = (x + 900)(x) = (180 + 900)(180) = 1080 × 180 = 194400 Applying
REAL NUMBERS
90202
Which of the following is an irrational number?
1 )\(\frac{22}{7}\)
2 )\(3.1416\)
3 )\(3.\overline{1416}\)
4 )\(3.141141114...\)
Explanation:
Exp: D \(3.141141114...\) An irrational number is a number that is non-terminating and non-repeating. Option (a) is a rational number, while option (c) is a repeating decimal number, and so are rational numbers. Option (d) is an irrational number. Never Active Medium **[Real Numbers]**
REAL NUMBERS
90203
If the LCM of two numbers is 45 times their HCF and the sum of LCM and HCF is 1150, then HCF =
1 )25
2 )1150
3 )50
4 )45
Explanation:
Exp: A 25 Given: LCM = 45 × HCF ...(i) And LCM + HCF = 1150 ...(ii) Putting the value of LCM from eq. (i) in eq. (ii), we get 45 × HCF + HCF = 1150 HCF (45 + 1) = 1150 \(\Rightarrow\)46 × HCF = 1150 \(\Rightarrow\)HCF = 25
90197
The largest number which divides 33 and 75, leaving remainders 1 and 3 respectively is:
1 )8
2 )12
3 )16
4 )6
Explanation:
Exp: A 8 Let us subtract 1 from 33 and 3 from 75 in order to find their HCF 33 - 1 = 32 75 - 3 = 72 To find HCF of 32, 72 72 = 32 × 2 + 8 32 = 8 × 4 + 0 8 is the largest number which divides 33 and 75, leaving remainders 1 and 3 respectively.
REAL NUMBERS
90198
If the sum of LCM and HCF of two numbers is 1260 and their LCM is 900 more than their HCF, then the product of two numbers is:
1 )203400
2 )194400
3 )198400
4 )205400
Explanation:
Exp: B 194400 Given that sum of LCM and HCF = 1260 LCM + HCF = 1260 .....(1) Let two numbers be a and b and HCF (a, b) = x According to question: Put value of HCF and LCM in equation (1) \(\Rightarrow\)900 + x + x = 1260 \(\Rightarrow\)2x = 1260 - 900 \(\Rightarrow\)2x = 360 \(\Rightarrow\ \text{x}=\frac{360}{2}\) \(\Rightarrow\)x = 180 ......(2) Now, LCM × HCF = Product of two numbers Product of two number = (x + 900)(x) = (180 + 900)(180) = 1080 × 180 = 194400 Applying
REAL NUMBERS
90202
Which of the following is an irrational number?
1 )\(\frac{22}{7}\)
2 )\(3.1416\)
3 )\(3.\overline{1416}\)
4 )\(3.141141114...\)
Explanation:
Exp: D \(3.141141114...\) An irrational number is a number that is non-terminating and non-repeating. Option (a) is a rational number, while option (c) is a repeating decimal number, and so are rational numbers. Option (d) is an irrational number. Never Active Medium **[Real Numbers]**
REAL NUMBERS
90203
If the LCM of two numbers is 45 times their HCF and the sum of LCM and HCF is 1150, then HCF =
1 )25
2 )1150
3 )50
4 )45
Explanation:
Exp: A 25 Given: LCM = 45 × HCF ...(i) And LCM + HCF = 1150 ...(ii) Putting the value of LCM from eq. (i) in eq. (ii), we get 45 × HCF + HCF = 1150 HCF (45 + 1) = 1150 \(\Rightarrow\)46 × HCF = 1150 \(\Rightarrow\)HCF = 25
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
REAL NUMBERS
90197
The largest number which divides 33 and 75, leaving remainders 1 and 3 respectively is:
1 )8
2 )12
3 )16
4 )6
Explanation:
Exp: A 8 Let us subtract 1 from 33 and 3 from 75 in order to find their HCF 33 - 1 = 32 75 - 3 = 72 To find HCF of 32, 72 72 = 32 × 2 + 8 32 = 8 × 4 + 0 8 is the largest number which divides 33 and 75, leaving remainders 1 and 3 respectively.
REAL NUMBERS
90198
If the sum of LCM and HCF of two numbers is 1260 and their LCM is 900 more than their HCF, then the product of two numbers is:
1 )203400
2 )194400
3 )198400
4 )205400
Explanation:
Exp: B 194400 Given that sum of LCM and HCF = 1260 LCM + HCF = 1260 .....(1) Let two numbers be a and b and HCF (a, b) = x According to question: Put value of HCF and LCM in equation (1) \(\Rightarrow\)900 + x + x = 1260 \(\Rightarrow\)2x = 1260 - 900 \(\Rightarrow\)2x = 360 \(\Rightarrow\ \text{x}=\frac{360}{2}\) \(\Rightarrow\)x = 180 ......(2) Now, LCM × HCF = Product of two numbers Product of two number = (x + 900)(x) = (180 + 900)(180) = 1080 × 180 = 194400 Applying
REAL NUMBERS
90202
Which of the following is an irrational number?
1 )\(\frac{22}{7}\)
2 )\(3.1416\)
3 )\(3.\overline{1416}\)
4 )\(3.141141114...\)
Explanation:
Exp: D \(3.141141114...\) An irrational number is a number that is non-terminating and non-repeating. Option (a) is a rational number, while option (c) is a repeating decimal number, and so are rational numbers. Option (d) is an irrational number. Never Active Medium **[Real Numbers]**
REAL NUMBERS
90203
If the LCM of two numbers is 45 times their HCF and the sum of LCM and HCF is 1150, then HCF =
1 )25
2 )1150
3 )50
4 )45
Explanation:
Exp: A 25 Given: LCM = 45 × HCF ...(i) And LCM + HCF = 1150 ...(ii) Putting the value of LCM from eq. (i) in eq. (ii), we get 45 × HCF + HCF = 1150 HCF (45 + 1) = 1150 \(\Rightarrow\)46 × HCF = 1150 \(\Rightarrow\)HCF = 25