Sets, Relation and Function
116951
\(\log _8 128\) is equal to
1 \(\frac{7}{3}\)
2 \(\frac{3}{7}\)
3 \(\frac{1}{16}\)
4 16
Explanation:
A Given,
\(\log _8 128=\frac{\log _2 128}{\log _2 8}=\frac{\log _2 2^7}{\log _2 2^3}=\frac{7 \log _2 2}{3 \log _2 2}=\frac{7}{3}\)