119242 The number of ways of choosing 10 objects out of 31 objects of which 10 are identical and the remaining 21 are distinct, is

119243 Some identical balls are arranged in rows to form an equilateral triangle. This first row consists of one ball, the second row consists of two balls and so on. If 99 more identical balls are added to the total number of ball used in forming the equilateral triangle, then all these balls can be arranged in a square whose each side contains exactly 2 balls less than number of balls each side of the triangle contains. Then, the number of balls used to form the equilateral triangle is

119245 The last digit in
\((1 !+3 !+5 !+\ldots+99 !)-(2 !+4 !+\ldots+100 !) \text { is }\)

119246 The number of ways in which 3 identical balls can be distributed into 7 distinct bins is

119242 The number of ways of choosing 10 objects out of 31 objects of which 10 are identical and the remaining 21 are distinct, is

119243 Some identical balls are arranged in rows to form an equilateral triangle. This first row consists of one ball, the second row consists of two balls and so on. If 99 more identical balls are added to the total number of ball used in forming the equilateral triangle, then all these balls can be arranged in a square whose each side contains exactly 2 balls less than number of balls each side of the triangle contains. Then, the number of balls used to form the equilateral triangle is

119245 The last digit in
\((1 !+3 !+5 !+\ldots+99 !)-(2 !+4 !+\ldots+100 !) \text { is }\)

119246 The number of ways in which 3 identical balls can be distributed into 7 distinct bins is

119242 The number of ways of choosing 10 objects out of 31 objects of which 10 are identical and the remaining 21 are distinct, is

119243 Some identical balls are arranged in rows to form an equilateral triangle. This first row consists of one ball, the second row consists of two balls and so on. If 99 more identical balls are added to the total number of ball used in forming the equilateral triangle, then all these balls can be arranged in a square whose each side contains exactly 2 balls less than number of balls each side of the triangle contains. Then, the number of balls used to form the equilateral triangle is

119245 The last digit in
\((1 !+3 !+5 !+\ldots+99 !)-(2 !+4 !+\ldots+100 !) \text { is }\)

119246 The number of ways in which 3 identical balls can be distributed into 7 distinct bins is

119242 The number of ways of choosing 10 objects out of 31 objects of which 10 are identical and the remaining 21 are distinct, is

119243 Some identical balls are arranged in rows to form an equilateral triangle. This first row consists of one ball, the second row consists of two balls and so on. If 99 more identical balls are added to the total number of ball used in forming the equilateral triangle, then all these balls can be arranged in a square whose each side contains exactly 2 balls less than number of balls each side of the triangle contains. Then, the number of balls used to form the equilateral triangle is

119245 The last digit in
\((1 !+3 !+5 !+\ldots+99 !)-(2 !+4 !+\ldots+100 !) \text { is }\)

119246 The number of ways in which 3 identical balls can be distributed into 7 distinct bins is