Explanation:
B Here,
3 dices are thrown \(\Rightarrow n=6^3\)
Same number appears mean sample space is
\(\mathrm{A}=\{(1,1,1,) ;(2,2,2),(3,3,3),(4,4,4),(5,5,5),(6,\)
\(6,6)\}\)
\(\text { Total number of favourable cases, in which all three }\)
\(\text { dice have same number, } \mathrm{n}(\mathrm{F})=6\)
\(\therefore \quad \text { Required probability }=\frac{6}{6^3}=\frac{1}{36}\)Total number of favourable cases, in which all three dice have same number, \(\mathrm{n}(\mathrm{F})=6\)